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CBSE Class 9 Physics Chapter 9 Gravitation — 20 MCQs with Answers

Gravitation is one of the most scoring and conceptually rich chapters in CBSE Class 9 Physics. It introduces Newton's universal law, explains why objects fall, and clarifies the often-confused terms mass and weight. Multiple-choice questions on this chapter appear regularly in school unit tests, term exams, and even competitive exams like NTSE. Practising MCQs sharpens your ability to recall formulae under time pressure, identify correct units, and avoid common traps. This page presents 20 high-quality MCQs distributed across key topics, complete with answers and brief explanations rooted in NCERT language.

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Key takeaways

  • Newton's law of universal gravitation states F = G(m₁m₂)/r², where G ≈ 6.67 × 10⁻¹¹ N·m²/kg² is a constant for the entire universe.
  • Mass is the amount of matter in an object (measured in kg) and remains constant everywhere; weight W = mg is a force (measured in Newtons) and varies with location.
  • Acceleration due to gravity g ≈ 9.8 m/s² on Earth's surface; it decreases with altitude and also decreases as you go deeper inside the Earth.
  • In free fall, all objects accelerate at the same rate g, regardless of their mass, when air resistance is negligible.
  • The gravitational force is always attractive, acts along the line joining the centers of two masses, and follows an inverse-square law with distance.
  • Understanding the difference between G (universal constant) and g (local acceleration) is critical for solving numerical problems and MCQs correctly.
  • CBSE Class 9 Physics Chapter 9 MCQs test recall of definitions, formula manipulation, conceptual understanding of weight vs mass, and application to real-world scenarios like satellite motion and tides.

Universal Law of Gravitation — Core Concept MCQs

Newton's law of universal gravitation is the foundation of this chapter. It states that every object in the universe attracts every other object with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. The formula F = G(m₁m₂)/r² must be memorized, along with the value of G and its SI unit. Students often confuse G (the universal gravitational constant, roughly 6.67 × 10⁻¹¹ N·m²/kg²) with g (acceleration due to gravity, roughly 9.8 m/s²). Questions in this section test your grasp of the law's statement, the inverse-square relationship, and correct substitution into the formula. Pay special attention to units: force in Newtons, mass in kilograms, distance in meters. A common exam trick is to give the distance in centimeters or kilometers and expect you to convert it first.
  • Q1. The force of gravitation between two objects is inversely proportional to: (A) Sum of their masses (B) Product of their masses (C) Distance between them (D) Square of the distance between them. Answer: (D) Square of the distance between them. Reason: Newton's law states F ∝ 1/r².
  • Q2. The SI unit of the universal gravitational constant G is: (A) N·m²/kg (B) N·m²/kg² (C) N·kg²/m² (D) m/s². Answer: (B) N·m²/kg². Reason: From F = G(m₁m₂)/r², rearranging gives G = F·r²/(m₁m₂), hence units N·m²/kg².
  • Q3. Two masses are separated by a distance r. If the distance is doubled, the gravitational force becomes: (A) Double (B) Half (C) One-fourth (D) Four times. Answer: (C) One-fourth. Reason: F ∝ 1/r²; if r → 2r, then F → F/4.

Weight, Mass, and the Relation W = mg — Application MCQs

Mass is an intrinsic property of matter measured in kilograms; it does not change whether you are on Earth, the Moon, or floating in space. Weight, however, is the gravitational force acting on that mass, calculated by W = mg, where g is the local acceleration due to gravity. On Earth g ≈ 9.8 m/s² (often rounded to 10 m/s² in CBSE numericals), but on the Moon g is about one-sixth of Earth's value, roughly 1.6 m/s². A 60 kg student has a weight of 60 × 10 = 600 N on Earth but only 60 × 1.6 = 96 N on the Moon. The mass remains 60 kg in both places. CBSE loves to ask 'What happens to your weight on the Moon?' or 'Why do astronauts feel weightless?' (Answer: they are in free fall, not because gravity is absent.) These MCQs test whether you can distinguish mass from weight and apply W = mg correctly, including unit conversions.
  • Q4. The mass of an object is 50 kg on Earth. What will be its mass on the Moon? (A) 50 kg (B) 8.3 kg (C) 300 kg (D) Zero. Answer: (A) 50 kg. Reason: Mass is constant everywhere; only weight changes with g.
  • Q5. If g = 10 m/s², the weight of a 5 kg bag is: (A) 5 N (B) 50 N (C) 0.5 N (D) 500 N. Answer: (B) 50 N. Reason: W = mg = 5 × 10 = 50 N.
  • Q6. An astronaut feels weightless in a spacecraft orbiting Earth because: (A) Gravity is absent there (B) The spacecraft and astronaut are in free fall together (C) The astronaut has zero mass (D) Air resistance is zero. Answer: (B) The spacecraft and astronaut are in free fall together. Reason: Both fall at the same rate, so no normal force acts on the astronaut, creating the sensation of weightlessness.

Acceleration Due to Gravity (g) — Conceptual and Numerical MCQs

The acceleration due to gravity g is the rate at which any freely falling object accelerates near Earth's surface, approximately 9.8 m/s² (or 10 m/s² for simplified calculations). The value of g is not universal; it varies with location. It is slightly less at the equator than at the poles because Earth is an oblate spheroid (bulges at the equator) and because of the centrifugal effect of Earth's rotation. As you climb a mountain or go higher in altitude, g decreases because you are farther from Earth's centre. Conversely, if you descend into a mine shaft, g also decreases because part of Earth's mass is now above you. The formula for variation with height (for small h) is g_h ≈ g(1 – 2h/R), where R is Earth's radius. Questions here test your ability to predict how g changes and to apply g in kinematic equations like v = u + gt or s = ut + ½gt². Remember: g is always taken as positive 9.8 m/s² or 10 m/s² unless the question specifies another celestial body.
  • Q7. The value of acceleration due to gravity g is maximum at: (A) Equator (B) Poles (C) Centre of Earth (D) Top of Mount Everest. Answer: (B) Poles. Reason: Earth's radius is smallest at the poles, and there is no centrifugal reduction there.
  • Q8. As we go higher above Earth's surface, the value of g: (A) Increases (B) Decreases (C) Remains constant (D) First increases then decreases. Answer: (B) Decreases. Reason: Gravitational force weakens with distance from Earth's centre; g ∝ 1/r².
  • Q9. At the centre of Earth, the acceleration due to gravity is: (A) Maximum (B) Minimum (zero) (C) 9.8 m/s² (D) Infinite. Answer: (B) Minimum (zero). Reason: All of Earth's mass is symmetrically around you, so net gravitational force is zero, hence g = 0.

Free Fall and Motion Under Gravity — HOTS MCQs

Free fall describes motion under gravity alone, with no other forces like air resistance or thrust. In true free fall, all objects—regardless of their mass—accelerate at the same rate g. This counterintuitive fact puzzled scholars for centuries until Galileo and Newton clarified it. A hammer and a feather dropped together in a vacuum (like on the Moon, famously demonstrated by astronaut David Scott during Apollo 15) hit the ground simultaneously. The reason: although the hammer experiences a larger gravitational force (because it has more mass), it also has greater inertia (resistance to acceleration). These two effects exactly cancel, leaving the same acceleration g for both. On Earth, air resistance complicates things—a feather falls slower than a hammer in air because of drag. CBSE often asks assertion-reason questions: 'Assertion: A heavy stone and a light stone fall at the same rate in vacuum. Reason: Acceleration due to gravity is independent of mass.' Both are true, and the reason correctly explains the assertion.
  • Q10. In the absence of air resistance, a heavy object and a light object dropped from the same height will: (A) Reach the ground at different times (B) Reach the ground at the same time (C) The heavy one reaches first (D) The light one reaches first. Answer: (B) Reach the ground at the same time. Reason: Both accelerate at g, independent of mass.
  • Q11. Assertion (A): A coin and a feather fall at the same rate in a vacuum. Reason (R): The value of g does not depend on the mass of the falling object. (A) Both A and R true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true. Answer: (A) Both A and R true, R explains A. Reason: g is constant for all masses, so both fall equally fast in vacuum.
  • Q12. A ball is thrown upward with initial velocity u. At the highest point of its motion, its: (A) Velocity is u and acceleration is zero (B) Velocity is zero and acceleration is g downward (C) Both velocity and acceleration are zero (D) Velocity is zero and acceleration is g upward. Answer: (B) Velocity is zero and acceleration is g downward. Reason: At the peak, v = 0 momentarily, but gravity still acts downward at g.

Distinguishing Between G and g — Common Confusion MCQs

A frequent source of error in exams is mixing up G (the universal gravitational constant) and g (acceleration due to gravity). G is a fundamental constant of nature, approximately 6.67 × 10⁻¹¹ N·m²/kg², and it is the same everywhere in the universe. It appears in Newton's law F = G(m₁m₂)/r². In contrast, g is a local quantity that varies from place to place; on Earth's surface it is about 9.8 m/s², on the Moon about 1.6 m/s², and on Jupiter much larger. The two are related: if you apply F = G(M_Earth × m)/R² to an object of mass m on Earth's surface and also write F = mg, you can derive g = G M_Earth / R². So g depends on the mass and radius of the celestial body, while G is universal. CBSE loves to ask 'Which of the following is constant throughout the universe?' or 'The value of G on the Moon is...' (Answer: same as on Earth, because G is universal). These MCQs check whether you truly understand the conceptual difference.
  • Q13. The universal gravitational constant G: (A) Has different values on different planets (B) Is the same throughout the universe (C) Depends on the masses of the objects (D) Has units m/s². Answer: (B) Is the same throughout the universe. Reason: G is a fundamental constant, not dependent on location or mass.
  • Q14. The value of g on the Moon is about 1.6 m/s². The value of G on the Moon is: (A) Also 1.6 (B) 9.8 (C) 6.67 × 10⁻¹¹ (D) Zero. Answer: (C) 6.67 × 10⁻¹¹. Reason: G is universal; only g varies with the celestial body.
  • Q15. Which of the following is correct? (A) G = 9.8 m/s² (B) g = 6.67 × 10⁻¹¹ N·m²/kg² (C) g = 9.8 m/s² on Earth (D) G varies with altitude. Answer: (C) g = 9.8 m/s² on Earth. Reason: G is the constant in the universal law; g is the local acceleration.

Numerical Problems as MCQs — Calculation Practice

CBSE Class 9 Physics exams often include one or two numerical-based MCQs in the objective section, especially in sample papers and board-style mock tests. These require you to substitute values into formulae, perform arithmetic (sometimes with scientific notation), and pick the correct option. Common pitfalls include forgetting to square the distance in F = G(m₁m₂)/r², using wrong units (e.g. distance in cm instead of m), or confusing mass with weight. Always write down the given data, identify the formula, substitute carefully, and double-check units. For Chapter 9 Gravitation, typical numericals ask you to calculate gravitational force between two masses, find weight given mass and g, or determine the new value of g at a certain height. Practice these under timed conditions to build speed. Remember: in MCQs, you can often eliminate obviously wrong answers (e.g. if weight must be in Newtons and one option is in kg, discard it immediately).
  • Q16. Two objects of mass 5 kg and 10 kg are 2 m apart. The gravitational force between them is (use G = 6.67×10⁻¹¹ N·m²/kg²): (A) 8.34×10⁻¹⁰ N (B) 1.67×10⁻⁹ N (C) 3.34×10⁻¹⁰ N (D) 6.67×10⁻¹¹ N. Answer: (A) 8.34×10⁻¹⁰ N. Reason: F = 6.67×10⁻¹¹ × (5×10)/2² = 6.67×10⁻¹¹ × 50/4 = 8.34×10⁻¹⁰ N.
  • Q17. A body of mass 2 kg falls freely under gravity (g = 10 m/s²). The force acting on it is: (A) 2 N (B) 20 N (C) 0.2 N (D) 200 N. Answer: (B) 20 N. Reason: F = mg = 2×10 = 20 N.
  • Q18. If the mass of Earth is 6×10²⁴ kg and its radius is 6.4×10⁶ m, the approximate value of g on Earth's surface is (use G = 6.67×10⁻¹¹): (A) 9.8 m/s² (B) 8.9 m/s² (C) 10 m/s² (D) 7.5 m/s². Answer: (A) 9.8 m/s². Reason: g = G M / R² = (6.67×10⁻¹¹ × 6×10²⁴)/(6.4×10⁶)² ≈ 9.8 m/s².

Assertion-Reason and Higher-Order Thinking MCQs

CBSE has introduced assertion-reason (A-R) type questions in recent years, and they are excellent for testing deep conceptual understanding rather than rote memorization. In an A-R question, you are given two statements: an Assertion and a Reason. You must decide if each is true or false, and if both are true, whether the Reason correctly explains the Assertion. For example: Assertion – 'The weight of an object on the Moon is less than its weight on Earth.' Reason – 'The Moon has less mass than Earth.' Both statements are individually true, and the Reason does explain the Assertion (because g on the Moon is smaller due to lower mass). Mark option (A). If the Reason were 'The Moon has no atmosphere,' that is also true but does not explain why weight is less, so you would mark (B). These questions reward careful reading and logical thinking. For Gravitation, expect A-R questions on why astronauts float, why g decreases with height, why all objects fall at the same rate in vacuum, and the difference between mass and weight.
  • Q19. Assertion: The gravitational force between two bodies is always attractive. Reason: Gravity acts along the line joining the centres of the two masses. (A) Both true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true. Answer: (B) Both true, R does not explain A. Reason: Both statements are correct, but the direction of force (along the line) does not explain why it is attractive.
  • Q20. Assertion: A man can jump higher on the Moon than on Earth. Reason: The value of g on the Moon is about one-sixth that on Earth. (A) Both true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true. Answer: (A) Both true, R explains A. Reason: Lower g means weaker gravitational pull, so the same muscular effort lifts the man higher.

How CBSETUTOR.ai Helps You Master Gravitation MCQs

Practising MCQs from a static page is useful, but real mastery comes when you can ask follow-up questions, clarify doubts instantly, and get step-by-step solutions tailored to your learning pace. That is where CBSETUTOR.ai shines. It is a 24×7 AI tutor designed specifically for CBSE students in Classes 6 to 12, covering every subject including Physics. You can upload a photo of any Gravitation MCQ or numerical problem from your textbook, worksheet, or school test, and the AI will recognize the question and provide a detailed, NCERT-aligned solution within seconds. The explanations use the exact terminology and steps you see in this guide—no generic Internet answers. If you are confused about why option (B) is correct or how to apply F = G(m₁m₂)/r² in a tricky scenario, simply type your doubt and get a clear answer. The AI adapts to your level, offering hints first if you want to try again, or a full solution if you are stuck. The best part: CBSETUTOR.ai costs just ₹999 per month for unlimited questions across all subjects and classes, with a 3-day free trial so you can experience it risk-free. Thousands of students in Delhi, Mumbai, Pune, Bengaluru, and smaller cities are already using it to boost their confidence and scores. Whether you are preparing for a unit test next week or revising for term exams, having an AI tutor in your pocket transforms your study sessions from frustrating to efficient.
  • Upload any Class 9 Gravitation MCQ photo and receive an instant, step-by-step solution with conceptual clarity.
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Strategy: How to Attempt MCQs in the CBSE Physics Paper

Multiple-choice questions in CBSE Physics papers are designed to test both knowledge recall and application. Here is a systematic approach to maximize your score. First, read the question stem carefully—underline keywords like 'increases,' 'decreases,' 'maximum,' 'minimum,' 'on the Moon,' 'in vacuum.' These words often hold the key to the correct answer. Second, before looking at the options, try to recall the relevant formula or concept. For example, if the question is about gravitational force, mentally note F = G(m₁m₂)/r². Third, eliminate obviously wrong answers. If the question asks for a force and one option is in kilograms, discard it. If it asks for the value of G and one option is 9.8, eliminate it (that is g, not G). Fourth, substitute values carefully if it is a numerical question. Write down your working on the margin of the question paper—CBSE allows rough work on the question booklet. Double-check your arithmetic, especially powers of ten. Fifth, for assertion-reason questions, evaluate the Assertion and Reason separately first, then check if the Reason explains the Assertion. Do not assume that if both are true, the answer is automatically (A)—the Reason must logically explain the Assertion. Sixth, manage your time. CBSE typically allocates 1 mark per MCQ, so spend about 1 minute per question. If you are stuck, mark your best guess and move on—come back if time permits. Seventh, avoid changing answers unless you are very sure; your first instinct is often correct. Finally, revise all MCQs if you finish early. Check that you have not misread 'increases' as 'decreases' or missed a 'not' in the question. These strategies, combined with thorough topic understanding and regular practice, will help you score full marks in the MCQ section of Chapter 9 Gravitation and beyond.
  • Read each question twice, underlining keywords that indicate direction of change (increases, decreases, constant, zero, maximum, minimum).
  • Recall the formula or definition before looking at options—this prevents you from being misled by clever distractors.
  • Eliminate absurd answers first (wrong units, values that violate basic physics, options that contradict well-known facts like 'gravity is repulsive').
  • For numericals, write your substitution step-by-step in the margin; mistakes in arithmetic or sign are common under exam pressure.
  • In assertion-reason MCQs, check if both statements are individually true, then verify the logical connection between them.
  • Allocate roughly 1 minute per MCQ; if uncertain, make an educated guess, mark the question number, and revisit it at the end.
  • Trust your first answer unless you spot a clear error—over-thinking often leads to changing a correct answer to a wrong one.
  • Use the last 2-3 minutes to scan all MCQs again, ensuring you did not misread 'Moon' as 'Mars' or miss a negative sign.

Frequently asked questions

What is the difference between mass and weight in CBSE Class 9 Physics Chapter 9 Gravitation?+
Mass is the amount of matter in an object, measured in kilograms, and remains constant everywhere. Weight is the gravitational force acting on that mass, calculated by W = mg, measured in Newtons, and varies with the local value of g. On the Moon, your mass stays the same but your weight becomes about one-sixth of your Earth weight because g on the Moon is roughly 1.6 m/s² compared to 9.8 m/s² on Earth.
How many MCQs on Gravitation typically appear in the CBSE Class 9 Physics term exam?+
CBSE Class 9 term exams usually include 2 to 4 objective questions (MCQs or assertion-reason) from Chapter 9 Gravitation, each carrying 1 mark. The exact number varies by year and school, but practising 15-20 MCQs covering all sub-topics—universal law, weight vs mass, free fall, g variation—ensures you are well-prepared for any format.
What is the value of the universal gravitational constant G, and how is it different from g?+
The universal gravitational constant G is approximately 6.67 × 10⁻¹¹ N·m²/kg² and is the same everywhere in the universe. It appears in Newton's law F = G(m₁m₂)/r². In contrast, g is the acceleration due to gravity, roughly 9.8 m/s² on Earth's surface, and varies from place to place depending on the mass and radius of the celestial body. G is a universal constant; g is a local variable.
Why do all objects fall at the same rate in a vacuum, regardless of their mass?+
In a vacuum (no air resistance), all objects experience only the gravitational force, which gives them an acceleration g. Although a heavier object experiences a larger force (F = mg is bigger), it also has greater inertia (mass). These two effects exactly cancel, leaving the same acceleration g for all objects. This is why a hammer and a feather fall together on the Moon, as demonstrated by astronaut David Scott during the Apollo 15 mission.
How does the value of g change with altitude and depth inside the Earth?+
As you go higher above Earth's surface, g decreases because you are farther from Earth's centre; the approximate formula is g_h = g(1 – 2h/R) for small heights. Conversely, as you descend into the Earth (for example, in a mine), g also decreases because part of Earth's mass is now above you, reducing the net gravitational pull. At the very centre of Earth, g becomes zero because the mass is symmetrically distributed all around you.
What is the best way to prepare for assertion-reason MCQs in Chapter 9 Gravitation?+
First, ensure you understand each concept clearly—do not just memorize statements. For each assertion, ask yourself 'Why is this true?' and see if the given reason answers that question. Practise sample assertion-reason questions from NCERT Exemplar, CBSE sample papers, and previous years' questions. Write down the logic: Is the assertion true? Is the reason true? Does the reason explain the assertion? This disciplined approach prevents confusion during the exam and boosts accuracy significantly.
Can CBSETUTOR.ai help me if I get stuck on a tricky Gravitation MCQ during homework?+
Absolutely. CBSETUTOR.ai is available 24×7. Simply take a photo of the MCQ with your phone, upload it to the platform, and within seconds you will receive a detailed solution showing which option is correct and why, complete with the relevant formula and step-by-step working. You can also type follow-up questions like 'Why is option C wrong?' or 'Can you explain the inverse-square law again?' and get instant, NCERT-aligned answers. The AI tutor costs just ₹999 per month for unlimited questions across all subjects, and you can try it free for 3 days.
What are the most common mistakes students make in Gravitation MCQs?+
Common errors include confusing G with g, forgetting to square the distance in F = G(m₁m₂)/r², mixing up mass (kg) and weight (N), assuming g is constant everywhere, neglecting unit conversions (e.g. cm to m), and misreading assertion-reason questions by not checking if the reason actually explains the assertion. Practising a variety of MCQs and reviewing your mistakes carefully helps you avoid these pitfalls in the actual exam.
Is it necessary to memorize the value of G for Class 9 Physics exams?+
Yes, you should memorize G ≈ 6.67 × 10⁻¹¹ N·m²/kg² because some MCQs and short-answer questions require you to substitute it into F = G(m₁m₂)/r² to calculate gravitational force. CBSE sometimes provides the value in the question, but knowing it by heart saves time and shows strong foundational knowledge. Similarly, remember g ≈ 9.8 m/s² (or 10 m/s² for quick approximations) and the relation W = mg.
How can I improve my speed in solving numerical-based Gravitation MCQs under exam pressure?+
Practice is the key. Solve at least 20-30 numerical MCQs under timed conditions before your exam. Write down the formula first, substitute values carefully, and do not skip steps mentally—small arithmetic errors are common under pressure. Use approximations smartly: if the options are widely spaced, round numbers to simplify calculations. For example, if G = 6.67×10⁻¹¹ and the options differ by orders of magnitude, you can estimate instead of computing exactly. Regular practice with a timer builds both accuracy and speed, ensuring you finish the MCQ section comfortably within the allotted time.

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