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CBSE Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes — 20 MCQs with Answers

Chapter 6 Haloalkanes and Haloarenes is a foundation of CBSE Class 12 Chemistry, bridging nomenclature, reaction mechanisms, and real-world applications of halogenated organic compounds. The 2025 board paper typically allocates 3–5 marks to this chapter via MCQs, assertion-reason pairs, and short answers. This page delivers 20 exam-style MCQs mirroring NCERT concepts, CBSE question patterns, and JEE/NEET trends to sharpen your preparation.

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Key takeaways

  • Haloalkanes undergo nucleophilic substitution (SN1 or SN2) depending on structure and substrate; tertiary halides favour SN1 via carbocation intermediates.
  • Haloarenes are less reactive than haloalkanes due to resonance stabilisation of C–X bond and sp² hybridisation of carbon.
  • Chloroform (CHCl₃), iodoform (CHI₃), DDT, and freons are polyhalogen compounds with distinct industrial and environmental significance.
  • Wurtz reaction, Sandmeyer reaction, and Finkelstein reaction are classic name reactions frequently tested in MCQs and board exams.
  • Assertion-Reason MCQs in CBSE 2025 Class 12 Chemistry carry 5 marks; understanding mechanism logic is essential for scoring.
  • NCERT Class 12 Chemistry MCQ practice builds speed and accuracy for both term exams and JEE/NEET where this chapter contributes ~4–6% weightage.
  • Using CBSETUTOR.ai's 24×7 photo-upload AI tutor (₹999/month, 3-day free trial) helps clarify tricky mechanisms and reaction pathways instantly.

Nomenclature, Classification, and Structure — MCQs 1–4

Haloalkanes are aliphatic compounds where one or more hydrogen atoms are replaced by halogen atoms (F, Cl, Br, I). Haloarenes have the halogen directly attached to an sp²-hybridised aromatic ring carbon. IUPAC nomenclature rules require identifying the longest carbon chain, numbering to give the lowest locant to the halogen substituent, and using prefixes fluoro-, chloro-, bromo-, or iodo-. Classification into primary (1°), secondary (2°), and tertiary (3°) depends on the carbon bearing the halogen. This section tests fundamental NCERT definitions and IUPAC naming conventions essential for board exams and competitive entrance tests.
  • MCQ 1: The IUPAC name of (CH₃)₃C–Br is: (A) 1-Bromo-2-methylpropane (B) 2-Bromo-2-methylpropane (C) tert-Butyl bromide (D) Isobutyl bromide | Answer: (B) 2-Bromo-2-methylpropane | Reason: The longest chain has three carbons; Br is on C-2 with two methyl groups also on C-2.
  • MCQ 2: Which of the following is a secondary haloalkane? (A) CH₃–CH(Cl)–CH₃ (B) (CH₃)₃C–Cl (C) CH₃–CH₂–CH₂–Cl (D) C₆H₅–CH₂–Cl | Answer: (A) CH₃–CH(Cl)–CH₃ | Reason: The carbon bearing Cl is attached to two other carbons, making it 2° (secondary).
  • MCQ 3: Haloarenes are less reactive than haloalkanes in nucleophilic substitution because: (A) C–X bond is shorter (B) Resonance delocalises the lone pair on halogen (C) Aromatic ring is electron-deficient (D) Haloarenes form carbocations easily | Answer: (B) Resonance delocalises the lone pair on halogen | Reason: Resonance between halogen lone pair and π-electrons of benzene ring gives partial double-bond character, stabilising C–X.
  • MCQ 4: The compound with the highest C–Cl bond length is: (A) CH₃Cl (B) CH₂=CH–Cl (C) C₆H₅Cl (D) CH₃–CH₂Cl | Answer: (A) CH₃Cl | Reason: sp³ C–Cl bond is longest; vinyl and aryl halides have sp² carbon with shorter C–Cl bonds due to higher s-character and resonance.

Preparation of Haloalkanes — MCQs 5–7

Haloalkanes are prepared by multiple routes: (i) free-radical halogenation of alkanes using Cl₂/Br₂ in UV light, (ii) addition of HX to alkenes following Markovnikov's rule (HBr in presence of peroxide follows anti-Markovnikov via free-radical mechanism), (iii) Hunsdiecker reaction (silver salt of carboxylic acid + Br₂ → alkyl bromide with one less carbon), and (iv) halogen exchange via Finkelstein (NaI in acetone) or Swarts reaction (AgF). NCERT Class 12 Chemistry emphasises mechanism understanding and product prediction, both tested in MCQs and short-answer questions in CBSE board exams.
  • MCQ 5: Propene reacts with HBr in presence of peroxide to give: (A) 1-Bromopropane (B) 2-Bromopropane (C) 1,2-Dibromopropane (D) Propane | Answer: (A) 1-Bromopropane | Reason: Peroxide effect (anti-Markovnikov); free-radical mechanism adds Br to less-substituted carbon.
  • MCQ 6: Finkelstein reaction is used to prepare: (A) Alkyl fluorides (B) Alkyl iodides (C) Alkyl chlorides (D) Aryl halides | Answer: (B) Alkyl iodides | Reason: NaI in dry acetone; NaCl/NaBr precipitates, driving equilibrium forward to form R–I.
  • MCQ 7: In the Hunsdiecker reaction, CH₃CH₂COOAg + Br₂ → product. The product is: (A) CH₃CH₂Br (B) CH₃Br (C) CH₃CH₂CH₂Br (D) CH₃COBr | Answer: (A) CH₃CH₂Br | Reason: Decarboxylative bromination; loss of CO₂ gives alkyl halide with one carbon less than the acid.

Preparation of Haloarenes — MCQs 8–9

Haloarenes are chiefly prepared by electrophilic aromatic halogenation (benzene + Cl₂/FeCl₃ → chlorobenzene) or via Sandmeyer and Gattermann reactions from aniline. In the Sandmeyer reaction, aniline is diazotised (NaNO₂ + HCl, 0–5 °C) to form benzenediazonium chloride, then treated with CuCl/CuBr/KI to yield the corresponding aryl halide. Gattermann reaction uses Cu powder instead of Cu(I) salts. Direct halogenation is less selective; diazonium route offers better control. CBSE Class 12 Chemistry chapter 6 quiz and board papers frequently ask mechanism steps and reagent identification for these name reactions.
  • MCQ 8: Chlorobenzene is prepared from benzene by treating with Cl₂ in presence of: (A) AlCl₃ (B) FeCl₃ (C) UV light (D) H₂SO₄ | Answer: (B) FeCl₃ | Reason: FeCl₃ acts as Lewis acid catalyst for electrophilic substitution; generates Cl⁺ electrophile.
  • MCQ 9: In Sandmeyer reaction, aniline is converted to bromobenzene via intermediate: (A) Phenol (B) Nitrobenzene (C) Benzenediazonium bromide (D) Benzyl bromide | Answer: (C) Benzenediazonium bromide | Reason: Aniline → [C₆H₅N₂]⁺Br⁻ (diazonium salt) → C₆H₅Br using CuBr catalyst.

Nucleophilic Substitution: SN1 and SN2 Mechanisms — MCQs 10–12

Haloalkanes undergo nucleophilic substitution via two pathways. SN2 is a one-step bimolecular mechanism with inversion of configuration (Walden inversion), favoured by primary substrates, strong nucleophiles, and polar aprotic solvents. SN1 is a two-step unimolecular mechanism forming a planar carbocation intermediate, leading to racemisation, favoured by tertiary substrates and polar protic solvents. NCERT explains that tertiary halides prefer SN1 due to stable 3° carbocations, while primary halides undergo SN2 due to steric accessibility. CBSE 2025 board exams and JEE/NEET routinely test mechanism identification, stereochemistry, and rate-determining steps through MCQs and assertion-reason questions.
  • MCQ 10: Which substrate undergoes SN2 reaction fastest? (A) (CH₃)₃C–Br (B) (CH₃)₂CH–Br (C) CH₃CH₂–Br (D) CH₃–Br | Answer: (D) CH₃–Br | Reason: Methyl halide has least steric hindrance; SN2 rate ∝ accessibility to nucleophile.
  • MCQ 11: Hydrolysis of (R)-2-bromobutane by aqueous KOH via SN2 gives: (A) (R)-butan-2-ol (B) (S)-butan-2-ol (C) Racemic mixture (D) But-1-ene | Answer: (B) (S)-butan-2-ol | Reason: SN2 causes inversion of configuration (Walden inversion); R → S.
  • MCQ 12: The rate of SN1 reaction depends on: (A) Concentration of nucleophile only (B) Concentration of substrate only (C) Both substrate and nucleophile (D) Temperature only | Answer: (B) Concentration of substrate only | Reason: SN1 is unimolecular; rate-determining step is ionisation of R–X to R⁺ + X⁻, first-order kinetics.

Elimination Reactions: E1 and E2, Saytzeff Rule — MCQs 13–15

Haloalkanes can undergo elimination to form alkenes when treated with strong bases like alcoholic KOH. E2 is a one-step bimolecular mechanism where base abstracts β-hydrogen while halide leaves simultaneously, giving anti-periplanar transition state geometry. E1 is stepwise, forming carbocation then losing proton. Saytzeff's rule (Zaitsev's rule) states that the major alkene product is the more substituted (thermodynamically stable) one. However, bulky bases (e.g. tert-butoxide) favour Hofmann product (less substituted alkene) due to steric factors. CBSE Class 12 Chemistry Haloalkanes and Haloarenes important questions often ask for major product prediction and mechanistic pathways, testing understanding of regioselectivity and stereochemistry.
  • MCQ 13: Dehydrohalogenation of 2-bromobutane with alcoholic KOH gives major product: (A) But-1-ene (B) But-2-ene (C) Butane (D) Butan-2-ol | Answer: (B) But-2-ene | Reason: Saytzeff rule; more substituted alkene (But-2-ene) is major product due to greater stability.
  • MCQ 14: E2 mechanism is favoured by: (A) Weak base (B) Tertiary substrate (C) Strong bulky base and heat (D) Polar protic solvent | Answer: (C) Strong bulky base and heat | Reason: Strong base abstracts proton; heat promotes elimination over substitution.
  • MCQ 15: Which of the following does NOT favour elimination? (A) Alcoholic KOH (B) Aqueous KOH (C) High temperature (D) Secondary substrate | Answer: (B) Aqueous KOH | Reason: Aqueous medium favours substitution (SN1/SN2); alcoholic medium promotes elimination.

Reactions of Haloalkanes: Wurtz, Grignard, Reduction — MCQs 16–17

Haloalkanes are versatile intermediates in organic synthesis. The Wurtz reaction couples two alkyl halides using sodium metal in dry ether to form a higher alkane (2 R–X + 2 Na → R–R + 2 NaX). Formation of Grignard reagent (R–X + Mg in dry ether → R–MgX) opens routes to alcohols, aldehydes, ketones, and carboxylic acids. Reduction of haloalkanes using Zn/HCl or LiAlH₄ replaces halogen with hydrogen. NCERT Class 12 Chemistry MCQ sets and board exams test reagent choice, product identification, and functional group interconversions. Understanding dry ether necessity (moisture destroys Grignard) and coupling selectivity (Wurtz limitations with different R groups) is crucial.
  • MCQ 16: Wurtz reaction of CH₃Br with Na in dry ether gives: (A) Ethane (B) Propane (C) Butane (D) Methane | Answer: (A) Ethane | Reason: 2 CH₃Br + 2 Na → CH₃–CH₃ + 2 NaBr; coupling of two methyl groups forms ethane.
  • MCQ 17: Grignard reagent reacts with formaldehyde (HCHO) followed by hydrolysis to give: (A) Primary alcohol (B) Secondary alcohol (C) Tertiary alcohol (D) Aldehyde | Answer: (A) Primary alcohol | Reason: R–MgX + HCHO → R–CH₂OMgX; H₃O⁺ gives R–CH₂OH (1° alcohol with one more carbon than R).

Polyhalogen Compounds: Chloroform, Iodoform, DDT, Freons — MCQs 18–19

Polyhalogen compounds contain two or more halogen atoms. Chloroform (CHCl₃) is prepared by haloform reaction (ethanol or acetone + Cl₂/NaOH) and used as a solvent and anesthetic (historical). Iodoform (CHI₃, yellow precipitate) is a characteristic test for CH₃CO– or CH₃CH(OH)– groups. DDT (dichlorodiphenyltrichloroethane) was a potent insecticide, now banned due to bioaccumulation and environmental persistence. Freons (CFCs like CCl₂F₂) were refrigerants; now restricted under the Montreal Protocol for ozone layer depletion. CBSE Class 12 Chemistry chapter 6 quiz and board exams ask structural formulas, uses, environmental impacts, and identification tests. NCERT sections on polyhalogen compounds emphasise real-world applications and regulatory aspects.
  • MCQ 18: Iodoform test is positive for: (A) CH₃CHO (B) HCHO (C) CH₃COCH₃ (D) Both A and C | Answer: (D) Both A and C | Reason: Compounds with CH₃CO– group (acetaldehyde, acetone) or CH₃CH(OH)– give yellow CHI₃ precipitate with I₂/NaOH.
  • MCQ 19: Freons (CFCs) cause ozone depletion by releasing: (A) Cl radicals (B) F radicals (C) CO₂ (D) SO₂ | Answer: (A) Cl radicals | Reason: UV light breaks C–Cl bond in CFCs; Cl· catalytically destroys O₃ in stratosphere (Cl· + O₃ → ClO· + O₂).

How to Attempt MCQs in the CBSE Chemistry Paper — Strategy & Tips

CBSE Class 12 Chemistry 2025 paper includes ~20 MCQs (1 mark each) plus 5 assertion-reason questions (1 mark each) in Section A. For Chapter 6 Haloalkanes and Haloarenes, expect 2–3 direct MCQs and 1 assertion-reason pair. Start by reading each MCQ stem carefully, identify keywords (e.g. 'Saytzeff', 'SN2', 'Sandmeyer'), and eliminate obviously wrong options. For mechanism-based questions, sketch a quick reaction pathway on rough paper. Assertion-reason MCQs have four answer codes: (A) both true, reason explains assertion; (B) both true, reason does not explain; (C) assertion true, reason false; (D) assertion false, reason true. Practice 50+ MCQs from NCERT exemplar, previous years' papers (2019–2024), and sample papers to build pattern recognition. Time management is critical: allocate ~30 seconds per MCQ. Mark tricky questions for review and return after completing easier ones. Using CBSETUTOR.ai's chapter-wise MCQ drills and instant photo-upload doubt solving (₹999/month, 3-day free trial) accelerates revision and clarifies conceptual gaps on demand, especially valuable during final-month preparation when speed and accuracy decide marks.
  • Read the question stem twice to catch keywords like 'major product', 'fastest rate', 'IUPAC name' that signal the concept being tested.
  • For assertion-reason MCQs, verify the truth of each statement independently first, then check logical connection between assertion and reason.
  • Eliminate options using NCERT definitions: e.g. if the question says 'SN1', rule out primary substrates immediately.
  • Sketch mechanism arrows for multi-step reactions (Sandmeyer, Wurtz, Grignard) to avoid silly errors in intermediate identification.
  • In numerical or formula-based MCQs (rare in this chapter), double-check units and substitution values before selecting the answer.
  • Flag questions where two options seem correct; return after Section B/C to re-evaluate with a fresh perspective.
  • Practice past-year MCQs from 2020–2024 CBSE papers to identify recurring themes: nomenclature, SN1 vs SN2, Saytzeff rule, and polyhalogen tests.

Environmental Impact and Real-World Applications

Haloalkanes and haloarenes have profound industrial and environmental significance. DDT's role in malaria control saved millions but its bioaccumulation led to global bans post-Rachel Carson's 'Silent Spring'. Freons revolutionised refrigeration but their ozone-depleting potential triggered the 1987 Montreal Protocol, phasing out CFCs in favour of HFCs and HCFCs with lower ozone depletion indices. Chloroform and carbon tetrachloride, once common solvents, are now restricted due to carcinogenicity and liver toxicity. Modern applications include agrochemicals (herbicides, pesticides), pharmaceuticals (anesthetics, antiseptics), and polymer precursors (PVC from vinyl chloride, Teflon from tetrafluoroethylene). CBSE board exams occasionally ask 3-mark questions on environmental chemistry linkages; understanding the trade-off between utility and ecological harm is vital. This real-world context also appears in case-study MCQs introduced in recent CBSE patterns, testing students' ability to apply organic chemistry principles to contemporary issues.
  • DDT (C₁₄H₉Cl₅) is a non-biodegradable organochlorine; biomagnification in food chains led to eggshell thinning in birds and its global restriction.
  • CFCs like CCl₂F₂ release chlorine radicals under UV light in the stratosphere, catalytically destroying ozone (O₃ → O₂), increasing UV-B radiation on Earth's surface.
  • Carbon tetrachloride (CCl₄) was used in fire extinguishers and dry cleaning; now replaced due to hepatotoxicity and ozone depletion.
  • Polyvinyl chloride (PVC) is synthesised from vinyl chloride (CH₂=CHCl), a proven human carcinogen; strict industrial hygiene protocols are mandatory.
  • Modern refrigerants like HFC-134a have zero ozone depletion potential but are potent greenhouse gases, prompting shift to hydrocarbons and ammonia.
  • Chloroform (CHCl₃) was an early anesthetic; replaced by safer alternatives (halothane, isoflurane) after discovery of hepatotoxicity and cardiac arrhythmia risks.

Common Mistakes Students Make in Chapter 6 MCQs

Recurring errors in CBSE Class 12 Chemistry Haloalkanes and Haloarenes MCQs include confusing SN1 and SN2 conditions, misapplying Saytzeff rule, and incorrect IUPAC nomenclature. Students often forget that haloarenes do NOT undergo simple nucleophilic substitution due to resonance and sp² hybridisation, leading to wrong mechanism selection. Another pitfall is mixing up reagents: using aqueous KOH for elimination or alcoholic KOH for substitution. In assertion-reason questions, many mark (A) when both statements are true but fail to check if the reason logically explains the assertion. For polyhalogen compound tests, confusing conditions for iodoform vs carbylamine tests costs easy marks. Nomenclature errors arise from incorrect chain selection or ignoring lowest-locant rule. Practice under timed conditions using NCERT exemplar and previous years' papers exposes these blind spots. Immediate clarification via CBSETUTOR.ai's AI tutor (available 24×7 at ₹999/month for Classes 6–12, 3-day free trial) prevents repetition and solidifies correct logic pathways.
  • Confusing SN1 and SN2: Tertiary halides never undergo SN2 (too crowded); primary halides rarely do SN1 (unstable 1° carbocation).
  • Misapplying Saytzeff rule: Forgetting that bulky bases (e.g. (CH₃)₃CO⁻K⁺) give Hofmann product (less substituted alkene).
  • IUPAC nomenclature: Choosing wrong parent chain or numbering from wrong end, e.g. calling (CH₃)₂CHCl '2-chloropropane' instead of '2-chloropropane' is correct, but '1-chloro-2-methylpropane' is wrong for (CH₃)₂CHCH₂Cl (should be 1-chloro-2-methylpropane).
  • Reagent mix-up: Writing Grignard + H₂O instead of Grignard + carbonyl compound then H₃O⁺ hydrolysis; moisture destroys RMgX instantly.
  • Assertion-reason traps: Both statements true but reason unrelated to assertion, e.g. Assertion: Chlorobenzene is less reactive. Reason: Benzene is aromatic. Mark (B), not (A).
  • Iodoform test errors: Forgetting that only CH₃CO– or CH₃CH(OH)– groups react; ethanol gives positive (oxidises to acetaldehyde), but methanol does not.
  • Ignoring stereochemistry: Not recognising that SN2 inverts configuration (R ↔ S) while SN1 gives racemic mixture due to planar carbocation.

Frequently asked questions

How many MCQs from Haloalkanes and Haloarenes appear in CBSE Class 12 Chemistry board exam?+
Typically 2–3 standalone MCQs (1 mark each) plus 1 assertion-reason question (1 mark) in Section A, totaling 3–4 marks. Additional 3-mark or 5-mark descriptive questions may appear in Sections B or C.
What is the difference between SN1 and SN2 mechanisms?+
SN1 is a two-step unimolecular mechanism forming a carbocation intermediate, favoured by tertiary substrates and polar protic solvents, giving racemic products. SN2 is a one-step bimolecular mechanism with backside attack, favoured by primary substrates and polar aprotic solvents, causing inversion of configuration (Walden inversion).
Why are haloarenes less reactive than haloalkanes in nucleophilic substitution?+
In haloarenes, the C–X bond has partial double-bond character due to resonance between the halogen lone pair and the aromatic π-system. Additionally, the sp² hybridised carbon is more electronegative and holds halogen more tightly, making nucleophilic displacement difficult under normal conditions.
Which reactions are most important for MCQs in Chapter 6?+
Sandmeyer reaction (aniline to aryl halides via diazonium salt), Wurtz reaction (coupling haloalkanes), Finkelstein and Swarts reactions (halogen exchange), Saytzeff vs Hofmann elimination, and iodoform test for CH₃CO– or CH₃CH(OH)– groups are high-frequency MCQ topics.
How do I identify whether a question tests SN1 or SN2?+
Look at substrate structure: tertiary halides → SN1; primary halides → SN2. Check solvent: polar protic (water, alcohols) → SN1; polar aprotic (acetone, DMSO) → SN2. Note nucleophile strength: weak nucleophile → SN1; strong nucleophile → SN2. Stereochemistry clue: racemisation → SN1; inversion → SN2.
What is the iodoform test and which compounds give positive result?+
Iodoform test uses I₂ and NaOH; compounds with CH₃CO– (methyl ketones, acetaldehyde) or CH₃CH(OH)– (secondary alcohols with methyl group at C-2) oxidise and form yellow CHI₃ precipitate. Ethanol, acetone, and 2-butanone give positive tests; methanol and benzaldehyde do not.
Can CBSETUTOR.ai help with mechanism-based doubts in Haloalkanes and Haloarenes?+
Yes. CBSETUTOR.ai offers 24×7 AI-powered tutoring for Classes 6–12 at ₹999/month (one flat price, 3-day free trial). Upload a photo of any mechanism, MCQ, or reaction scheme, and receive step-by-step explanations instantly, clarifying SN1/SN2 pathways, Saytzeff rule applications, and reagent choices.
What are polyhalogen compounds and their environmental concerns?+
Polyhalogen compounds contain two or more halogen atoms. Examples include CHCl₃ (chloroform), CHI₃ (iodoform), DDT, and CFCs. Environmental concerns: DDT bioaccumulates and persists in ecosystems; CFCs deplete stratospheric ozone by releasing Cl radicals; CCl₄ is hepatotoxic and ozone-depleting, leading to global bans and restrictions.
How should I approach assertion-reason MCQs in this chapter?+
Read assertion and reason separately. Check if each is factually correct per NCERT. Then ask: does the reason logically explain the assertion? If both true and reason explains assertion → (A). Both true but unrelated → (B). Assertion true, reason false → (C). Assertion false → (D) or vice versa depending on coding.
What is Saytzeff rule and when does it not apply?+
Saytzeff (Zaitsev) rule states that in elimination reactions, the major alkene product is the more substituted (stable) one. It does not apply when using bulky bases like tert-butoxide; steric hindrance then favours abstraction of more accessible proton, giving less substituted Hofmann product.

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