CBSE Class 12 Chemistry Chapter 3 Chemical Kinetics — 20 MCQs with Answers
Chemical Kinetics is Chapter 3 in the NCERT Class 12 Chemistry textbook and carries significant weight in the CBSE board exam—expect 3–5 marks in Section A (MCQs) and at least one numerical in Section B. The chapter covers rate of reaction, rate laws, order and molecularity, integrated rate equations, temperature dependence via the Arrhenius equation, and collision theory. Mastering MCQs on these topics builds speed and confidence. Below are 20 carefully crafted multiple-choice questions mirroring the style and difficulty of recent CBSE papers, complete with answers and explanations.
Key takeaways
- ✓Rate of reaction is measured in mol L⁻¹ s⁻¹ and can be expressed as −d[R]/dt or +d[P]/dt depending on stoichiometry.
- ✓Order of reaction (sum of exponents in rate law) is experimentally determined and may differ from stoichiometric coefficients.
- ✓Molecularity is always a whole number (1, 2, or 3) and refers to the number of molecules participating in an elementary step.
- ✓Integrated rate equations link concentration and time: zero-order ([A]=[A]₀−kt), first-order (ln[A]=ln[A]₀−kt), second-order (1/[A]=1/[A]₀+kt).
- ✓The Arrhenius equation k=Ae^(−Ea/RT) shows reaction rate constant increases exponentially with temperature and decreases with higher activation energy.
- ✓Half-life for first-order reactions is independent of initial concentration (t₁/₂=0.693/k), a key exam concept.
- ✓Collision theory explains that only effective collisions—with proper orientation and energy ≥Ea—lead to product formation.
Rate of Reaction and Factors Affecting It — MCQs 1–4
- Q1. For the reaction 2N₂O₅ → 4NO₂ + O₂, if the rate of formation of NO₂ is 0.04 mol L⁻¹ s⁻¹, the rate of disappearance of N₂O₅ is: (A) 0.01 mol L⁻¹ s⁻¹ (B) 0.02 mol L⁻¹ s⁻¹ (C) 0.04 mol L⁻¹ s⁻¹ (D) 0.08 mol L⁻¹ s⁻¹
- Answer: (B) 0.02 mol L⁻¹ s⁻¹. Rate of disappearance = (2/4) × rate of formation of NO₂ = 0.02 mol L⁻¹ s⁻¹ by stoichiometry.
- Q2. Which factor does NOT affect the rate of reaction between two gases? (A) Temperature (B) Catalyst (C) Pressure (D) Molar mass of the container
- Answer: (D) Molar mass of the container. Reaction rate depends on reactant properties and conditions, not the container material or its molar mass.
- Q3. The instantaneous rate of reaction at time t is given by: (A) Δ[A]/Δt (B) d[A]/dt (C) [A]₀−[A] (D) k[A]
- Answer: (B) d[A]/dt. Instantaneous rate is the derivative (slope of tangent) on a concentration-time graph at a specific moment.
- Q4. Units of rate constant for a zero-order reaction are: (A) s⁻¹ (B) mol L⁻¹ s⁻¹ (C) L mol⁻¹ s⁻¹ (D) L² mol⁻² s⁻¹
- Answer: (B) mol L⁻¹ s⁻¹. For zero-order, rate = k, so units of k match units of rate.
Rate Law, Order, and Molecularity — MCQs 5–8
- Q5. For the reaction A + 2B → C, if doubling [A] doubles the rate and doubling [B] quadruples the rate, the order is: (A) 1 (B) 2 (C) 3 (D) 4
- Answer: (C) 3. Rate ∝ [A]¹[B]², so overall order = 1+2 = 3.
- Q6. Which statement is correct? (A) Order can be fractional; molecularity cannot. (B) Molecularity can be zero; order cannot. (C) Order is always an integer. (D) Molecularity is determined from the balanced equation.
- Answer: (A) Order can be fractional; molecularity cannot. Molecularity is a count of molecules in an elementary step, always a whole number.
- Q7. A reaction occurs in two steps: (i) A → B (slow), (ii) B + C → D (fast). The molecularity of the rate-determining step is: (A) 1 (B) 2 (C) 3 (D) cannot be determined
- Answer: (A) 1. The slow step (i) involves one molecule of A, so molecularity = 1 (unimolecular).
- Q8. For a reaction with rate = k[A]⁰[B]¹, if [A] is tripled, the rate: (A) triples (B) remains unchanged (C) becomes nine times (D) becomes one-third
- Answer: (B) remains unchanged. Zero order in A means [A] has no effect on rate; rate depends only on [B].
Integrated Rate Equations and Half-Life — MCQs 9–12
- Q9. A first-order reaction has k=0.02 s⁻¹. The half-life is approximately: (A) 17.3 s (B) 34.6 s (C) 50 s (D) 69.3 s
- Answer: (B) 34.6 s. t₁/₂=0.693/k=0.693/0.02≈34.6 s.
- Q10. For a zero-order reaction, a plot of [A] versus time is: (A) linear with negative slope (B) exponential curve (C) hyperbola (D) parabola
- Answer: (A) linear with negative slope. [A]=[A]₀−kt is the equation of a straight line with slope −k.
- Q11. Which statement about half-life is FALSE? (A) For first-order, t₁/₂ is independent of [A]₀. (B) For zero-order, t₁/₂ ∝ [A]₀. (C) For second-order, t₁/₂ ∝ 1/[A]₀. (D) For all orders, t₁/₂ ∝ 1/k.
- Answer: (D) For all orders, t₁/₂ ∝ 1/k. True for first-order, but zero-order t₁/₂ also depends on [A]₀, and second-order t₁/₂ on [A]₀.
- Q12. A reaction A→B follows first-order kinetics. If 75% of A decomposes in 60 minutes, t₁/₂ is: (A) 15 min (B) 20 min (C) 30 min (D) 40 min
- Answer: (C) 30 min. 75% decomposed means two half-lives elapsed (50% + 25% of remaining 50%). So 2×t₁/₂=60 min ⇒ t₁/₂=30 min.
Arrhenius Equation and Temperature Dependence — MCQs 13–16
- Q13. According to the Arrhenius equation, increasing temperature: (A) increases Ea (B) decreases Ea (C) increases k (D) has no effect on k
- Answer: (C) increases k. Higher T makes the exponent −Ea/RT less negative, so e^(−Ea/RT) and hence k increase.
- Q14. A plot of ln k versus 1/T for a reaction gives a straight line with slope −5000 K. The activation energy Ea (R=8.314 J K⁻¹ mol⁻¹) is: (A) 5 kJ mol⁻¹ (B) 41.57 kJ mol⁻¹ (C) 8.314 kJ mol⁻¹ (D) 5000 J mol⁻¹
- Answer: (B) 41.57 kJ mol⁻¹. Slope = −Ea/R ⇒ Ea = 5000×8.314 = 41,570 J = 41.57 kJ mol⁻¹.
- Q15. For a reaction, k doubles when temperature increases from 300 K to 310 K. The activation energy is approximately (R=8.314 J K⁻¹ mol⁻¹): (A) 26 kJ mol⁻¹ (B) 53 kJ mol⁻¹ (C) 13 kJ mol⁻¹ (D) 100 kJ mol⁻¹
- Answer: (B) 53 kJ mol⁻¹. Using ln(k₂/k₁)=ln2=0.693=(Ea/R)×(10/(300×310)), solve Ea ≈ 53 kJ mol⁻¹.
- Q16. Which factor does NOT appear in the Arrhenius equation? (A) Activation energy (B) Gas constant (C) Temperature (D) Enthalpy change of reaction
- Answer: (D) Enthalpy change of reaction. k=Ae^(−Ea/RT) involves Ea (activation energy), R, T, and A, not ΔH.
Collision Theory and Activation Energy — MCQs 17–18
- Q17. According to collision theory, the rate of reaction depends on: (A) number of collisions only (B) number of effective collisions with E ≥ Ea and proper orientation (C) temperature only (D) concentration of products
- Answer: (B) number of effective collisions with E ≥ Ea and proper orientation. Only collisions meeting both criteria lead to product formation.
- Q18. A catalyst increases the rate of reaction by: (A) increasing ΔH (B) increasing Ea (C) decreasing Ea (D) increasing the concentration of reactants
- Answer: (C) decreasing Ea. A catalyst provides an alternate pathway with lower activation energy, raising the fraction of effective collisions.
HOTS and Assertion-Reason MCQs — MCQs 19–20
- Q19. Assertion (A): The half-life of a first-order reaction is independent of initial concentration. Reason (R): The rate constant k for a first-order reaction has units of s⁻¹. (A) Both A and R true; R is correct explanation of A. (B) Both A and R true; R is NOT correct explanation of A. (C) A true, R false. (D) A false, R true.
- Answer: (B) Both A and R true; R is NOT correct explanation of A. A is true (t₁/₂=0.693/k, no [A]₀ term). R is true (units of k for first-order are indeed s⁻¹). But R does not explain why t₁/₂ is independent of [A]₀; that follows from the integrated rate law form.
- Q20. A reaction has rate = k[A]²[B]. If [A] is halved and [B] is doubled, the new rate relative to the original is: (A) unchanged (B) halved (C) doubled (D) quartered
- Answer: (B) halved. New rate = k(½[A])²(2[B]) = k × ¼[A]² × 2[B] = ½ × (k[A]²[B]) = ½ original rate.
How to Attempt MCQs in the CBSE Chemistry Paper
- Read the question stem completely before looking at options; keywords like 'NOT', 'EXCEPT', 'FALSE' flip the logic.
- For numerical MCQs, plug in values quickly and check units—mismatched units often signal a wrong option.
- In assertion-reason, evaluate A and R separately first, then check causation; don't assume R explains A just because both are true.
- If two options seem close, reread the question to spot which concept is actually being tested (order vs molecularity is a common trap).
- Use the 'strike-through' method: lightly cross out impossible options in the question paper to narrow choices.
- Budget roughly 1 minute per MCQ; if one takes longer, flag it and return after finishing easier questions.
- CBSE board papers have no negative marking, so never leave a question unattempted—guess intelligently if needed.
Common Mistakes Students Make in Chemical Kinetics MCQs
- Confusing order (experimental, can be fractional) with molecularity (integer, elementary step only).
- Using the wrong half-life formula—write all three down at the start of the exam to avoid mid-question panic.
- Unit mismatches in Arrhenius calculations: always convert Ea to J mol⁻¹ when using R=8.314 J K⁻¹ mol⁻¹.
- Forgetting to divide rate by stoichiometric coefficient when relating rates of different species in the same reaction.
- Rushing through assertion-reason MCQs and assuming R explains A without independent verification.
- Misreading question stems under time pressure—circle keywords like NOT, EXCEPT, INCREASES, DECREASES.
- Skipping NCERT exercise questions—at least 3–4 MCQs per paper are near-replicas of textbook problems.
Frequently asked questions
How many MCQs on Chemical Kinetics appear in the CBSE Class 12 Chemistry board exam?+
What is the difference between order and molecularity in a reaction?+
Which half-life formula should I memorize for the CBSE exam?+
How do I solve Arrhenius equation problems quickly in MCQs?+
Are graphical questions on rate laws asked as MCQs?+
What are effective collisions in collision theory?+
Can the order of a reaction be determined from the balanced chemical equation?+
How does a catalyst affect the rate constant k and activation energy Ea?+
Why is the first-order half-life independent of initial concentration?+
How can I prepare Chemical Kinetics MCQs without coaching in a Tier-2 city?+
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