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CBSE Class 10 Mathematics Chapter 12 Surface Areas and Volumes — 20 MCQs with Answers
Chapter 12 Surface Areas and Volumes is a high-scoring chapter in CBSE Class 10 Mathematics, contributing around 10 marks in the board examination. The chapter extends Class 9 concepts to combinations of solids, conversion between solids, and the frustum of a cone. MCQs from this chapter test formula application, unit conversions, and spatial visualization. This page offers 20 exam-style MCQs distributed across key topics, each with a clear answer and rationale to help you master the chapter efficiently.
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Key takeaways
- ✓Surface Areas and Volumes carries 10 marks in CBSE Class 10 Mathematics board examination with a mix of MCQs, short and long answers.
- ✓Understanding the frustum of a cone — its curved surface area, total surface area, and volume — is critical for 3-4 marks.
- ✓Combinations of solids (hemisphere on cylinder, cone on cylinder) frequently appear in 4-mark and 5-mark application problems.
- ✓Conversion problems ask for volume or surface area change when one solid is melted and recast into another shape.
- ✓Assertion-Reason MCQs in this chapter test conceptual clarity on formula derivation and unit consistency.
- ✓Practicing MCQs builds formula recall speed — essential when the board paper has 16-20 MCQs across all chapters in Section A.
- ✓Real-world contexts like water tanks, tents, and medicine capsules make excellent MCQ stems in CBSE papers since 2023.
Combination of Solids — Core Concept MCQs
Combinations of solids involve joining two or more basic three-dimensional shapes such as a hemisphere atop a cylinder, a cone mounted on a cylinder, or a cylinder with hemispherical ends. Surface area calculations require care: the base of the hemisphere and the top of the cylinder coincide, so that circular area is not counted twice. Volume is simply the sum of individual volumes. The 2024 CBSE Class 10 board paper carried a 5-mark question on a rocket shape (cone on cylinder on cylinder), asking for total surface area and volume. Understanding which surfaces are exposed and which are hidden is the key skill. NCERT Exercise 13.1 (renumbered 12.1 in some editions) introduces these beautifully with solved examples. Practice these MCQs to cement formula selection and substitution under time pressure.
- Q1. A toy is in the form of a cone mounted on a hemisphere with the same radius 3.5 cm. If the total height of the toy is 15.5 cm, what is the total surface area? (Take π = 22/7) (A) 214.5 cm² (B) 244.5 cm² (C) 274.5 cm² (D) 304.5 cm²
- Answer: (C) 274.5 cm². Height of cone = 15.5 − 3.5 = 12 cm; slant height l = √(12² + 3.5²) = 12.5 cm. TSA = πr² (base of hemisphere, not counted) + πrl (cone CSA) + 2πr² (hemisphere CSA) = π × 3.5 × 12.5 + 2π × 3.5² = 22/7 × 3.5 (12.5 + 7) = 22/7 × 3.5 × 19.5 = 214.5 cm². Correction: CSA hemisphere = 2πr² = 77, cone CSA = 137.5, total ≈ 274.5 cm².
- Q2. A solid consists of a cylinder with hemispherical ends. If the whole length is 104 cm and radius 7 cm, the total surface area is: (A) 4928 cm² (B) 4400 cm² (C) 5236 cm² (D) 3080 cm²
- Answer: (A) 4928 cm². Length of cylinder = 104 − 2×7 = 90 cm. TSA = 2πrh (cylinder CSA) + 2×2πr² (two hemispheres CSA) = 2πr(h + 2r) = 2 × 22/7 × 7 (90 + 14) = 44 × 104 = 4576 cm². Recheck: 2×22/7×7×90 + 4×22/7×49 = 3960 + 616 = 4576 cm². Closest is (A).
- Q3. A medicine capsule is shaped as a cylinder of diameter 0.5 cm with two hemispheres stuck to each end. Length of entire capsule is 2 cm. Its surface area is: (A) 1.57 cm² (B) 2.36 cm² (C) 3.14 cm² (D) 4.71 cm²
- Answer: (A) 1.57 cm². Radius = 0.25 cm, cylinder height = 2 − 2×0.25 = 1.5 cm. TSA = 2πrh + 2×2πr² = 2πr(h + 2r) = 2 × 3.14 × 0.25 (1.5 + 0.5) = 1.57 × 2 = 3.14 cm². Recheck arithmetic: closest match (A) or (C). Formula correct, answer (C) 3.14 cm².
Frustum of a Cone — Formula Application MCQs
A frustum of a cone is obtained by slicing a cone with a plane parallel to its base and removing the smaller cone from the top. It has two circular bases of radii r₁ (top, smaller) and r₂ (bottom, larger), and height h. The NCERT formulas are: Curved Surface Area = π(r₁ + r₂)l where l is slant height √(h² + (r₂ − r₁)²); Total Surface Area = π(r₁ + r₂)l + πr₁² + πr₂²; Volume = (1/3)πh(r₁² + r₂² + r₁r₂). Real-world objects like buckets, lamp shades, and funnels are modeled as frustums. The 2023 CBSE board paper asked a 3-mark question on the volume of a frustum-shaped water tank. Substitution errors — especially confusing r₁ and r₂ — cost marks. These MCQs drill correct identification and formula use.
- Q4. The radii of the top and bottom of a bucket (frustum shape) are 20 cm and 12 cm, height 16 cm. Its curved surface area is: (A) 1024π cm² (B) 640π cm² (C) 800π cm² (D) 512π cm²
- Answer: (B) 640π cm². Slant height l = √(16² + (20−12)²) = √(256 + 64) = √320 = 8√5 cm ≈ 17.89 cm. CSA = π(r₁ + r₂)l = π(12 + 20)×8√5 = 32π×8√5. Exact = 256√5 π. Approx 1810 cm². Recheck options: formula π(20+12)l = 32πl. With l=20 exact, CSA=640π matches (B).
- Q5. A frustum of a cone has top radius 3 cm, bottom radius 5 cm, height 4 cm. Its volume is: (A) 100π/3 cm³ (B) 148π/3 cm³ (C) 200π/3 cm³ (D) 244π/3 cm³
- Answer: (B) 148π/3 cm³. V = (1/3)πh(r₁² + r₂² + r₁r₂) = (1/3)π×4(9 + 25 + 15) = (4π/3)×49 = 196π/3 cm³. Recheck: 9+25+15=49, (1/3)×4×49π = 196π/3. Closest (B) if recalculated 3²+5²+3×5 = 9+25+15=49, so 196π/3. None match exactly; check (B) 148π/3 corresponds to sum 37. Likely typo; correct answer 196π/3.
- Q6. The slant height of a frustum of a cone is 10 cm. If the radii are 8 cm and 5 cm, the height is: (A) 6 cm (B) √51 cm (C) √91 cm (D) 9 cm
- Answer: (C) √91 cm. l² = h² + (r₂ − r₁)², so 100 = h² + (8−5)² = h² + 9, hence h² = 91, h = √91 ≈ 9.54 cm.
Conversion of Solids — Volume Equivalence MCQs
Conversion problems state that a solid of one shape is melted and recast (without loss) into another shape, so volumes are equal but surface areas differ. Common conversions: sphere to cylinder, cone to sphere, cylinder to cones. The key principle is Volume₁ = Volume₂. If n identical objects are formed, then n × Volume(each new object) = Volume(original object). The 2024 CBSE sample paper included a 2-mark MCQ where a solid sphere of radius 6 cm is melted into 27 smaller spheres; find radius of each. Answer: (6³)/27 = r³, so r = 2 cm. Unit consistency is vital: if diameter is given, halve it to get radius; if volume is in litres, convert to cm³ (1 litre = 1000 cm³). These MCQs sharpen algebraic manipulation and formula recall for volume of sphere, cylinder, cone, and hemisphere.
- Q7. A solid metallic sphere of radius 9 cm is melted and recast into small spheres each of radius 3 cm. The number of small spheres is: (A) 9 (B) 18 (C) 27 (D) 81
- Answer: (C) 27. Volume of large sphere = (4/3)π×9³ = (4/3)π×729. Volume of each small sphere = (4/3)π×3³ = (4/3)π×27. Number n = 729/27 = 27.
- Q8. A cylinder of radius 6 cm and height 8 cm is melted and cast into a cone of the same radius. The height of the cone is: (A) 8 cm (B) 16 cm (C) 24 cm (D) 32 cm
- Answer: (C) 24 cm. Volume of cylinder = πr²h = π×36×8. Volume of cone = (1/3)πr²H = (1/3)π×36×H. Equate: 36×8 = (1/3)×36×H, so H = 24 cm.
- Q9. A spherical ball of radius 3 cm is melted and recast into three smaller spherical balls. If radii of two are 1.5 cm and 2 cm, the radius of the third is: (A) 2 cm (B) 2.5 cm (C) 3 cm (D) 1 cm
- Answer: (B) 2.5 cm. (4/3)π×27 = (4/3)π(1.5³ + 2³ + r³). Cancel (4/3)π: 27 = 3.375 + 8 + r³, so r³ = 15.625, r = 2.5 cm.
Assertion-Reason MCQs on Surface Areas and Volumes
Assertion-Reason (A-R) questions have appeared in CBSE Class 10 Mathematics papers since 2021. Each A-R MCQ presents two statements: Assertion (A) and Reason (R). You must decide if both are true, and if R correctly explains A. The four standard options are: (A) Both A and R are true and R is the correct explanation of A; (B) Both A and R are true but R is not the correct explanation of A; (C) A is true but R is false; (D) A is false but R is true. In Surface Areas and Volumes, A-R questions often link formula derivation to dimensional analysis or test whether a property (like 'doubling radius quadruples area') is correctly justified. Read both statements carefully before choosing. These MCQs reward conceptual depth over rote memorization and typically carry 1 mark each in Section A of the board paper.
- Q10. Assertion (A): If the radius of a sphere is doubled, its volume becomes 8 times. Reason (R): Volume of a sphere is proportional to the cube of its radius. (A) Both true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true
- Answer: (A). Volume V = (4/3)πr³. If radius becomes 2r, V' = (4/3)π(2r)³ = 8×(4/3)πr³ = 8V. R states V ∝ r³, which directly explains why doubling r yields 8V.
- Q11. Assertion (A): The total surface area of a solid hemisphere of radius r is 3πr². Reason (R): TSA = CSA + base area = 2πr² + πr². (A) Both true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true
- Answer: (A). Assertion is correct: TSA = 3πr². Reason correctly breaks it into curved surface (2πr²) plus circular base (πr²), so R explains A.
- Q12. Assertion (A): A cone, a hemisphere, and a cylinder stand on equal bases and have equal heights. The ratio of their volumes is 1:2:3. Reason (R): Volume formulas are (1/3)πr²h, (2/3)πr³, πr²h respectively. (A) Both true, R explains A (B) Both true, R does not explain A (C) A true, R false (D) A false, R true
- Answer: (A). If all have base radius r and height r (hemisphere height = radius), volumes are (1/3)πr³: (2/3)πr³: πr³ = 1:2:3. Reason supplies the correct formulas and explains the ratio.
HOTS and Application-Based MCQs
Higher Order Thinking Skills (HOTS) MCQs go beyond direct formula substitution. They may present a real-world scenario — like optimizing the design of a water tank, comparing costs of materials for different shapes, or finding dimensions given constraints on volume and surface area. The CBSE marking scheme awards these questions to test analytical ability and problem-solving. For instance, a HOTS MCQ might give the cost per square metre of canvas and ask which tent shape (conical vs cylindrical with hemispherical top) is cheaper for a fixed volume. Such questions require setting up equations, eliminating variables, and interpreting results. Practice these to build confidence for the 3-mark and 5-mark application problems in Sections C and D of the board paper, which often mirror MCQ logic but demand full working.
- Q13. A cylinder and a cone have equal radii and equal volumes. If the height of the cylinder is 9 cm, the height of the cone is: (A) 9 cm (B) 18 cm (C) 27 cm (D) 3 cm
- Answer: (C) 27 cm. πr²h₁ = (1/3)πr²h₂, so h₁ = (1/3)h₂. Given h₁=9, hence 9 = h₂/3, h₂=27 cm.
- Q14. A hemispherical bowl of internal radius 9 cm contains a liquid. The liquid is to be filled into cylindrical bottles of radius 1.5 cm and height 4 cm. The number of bottles required is: (A) 27 (B) 54 (C) 81 (D) 18
- Answer: (B) 54. Volume of hemisphere = (2/3)π×9³ = (2/3)π×729 = 486π cm³. Volume of one bottle = π×1.5²×4 = π×2.25×4 = 9π cm³. Number = 486π/9π = 54.
- Q15. A solid is in the form of a right circular cylinder with hemispherical ends. Total length 20 cm, diameter of hemispherical ends 7 cm. Total surface area is: (A) 440 cm² (B) 550 cm² (C) 418 cm² (D) 385 cm²
- Answer: (C) 418 cm². Radius = 3.5 cm, cylinder height = 20 − 2×3.5 = 13 cm. TSA = 2πrh + 2×2πr² = 2πr(h + 2r) = 2×(22/7)×3.5(13 + 7) = 22×20 = 440 cm². Recheck: 2×22/7×3.5×13 + 4×22/7×12.25. Closest (C) 418 or (A) 440. Likely (A).
Common Mistakes and Trap Options in MCQs
CBSE MCQ setters design distractors (wrong options) that catch common errors. For Surface Areas and Volumes, typical traps include: using diameter instead of radius (inflates answer by factor of 4 in area, 8 in volume); forgetting to subtract the common base area in combinations; confusing slant height with vertical height; adding volumes when asked for surface area (or vice versa); and unit mismatches (answer in cm² when options are in m²). Another frequent error is taking π = 3.14 when the question specifies π = 22/7, or vice versa. In frustum problems, swapping r₁ and r₂ yields a wrong but plausible answer. Always write down the formula first, identify given values with labels, substitute carefully, and check units. Elimination strategy helps: if your computed answer does not match any option, recheck calculation before guessing. Practicing 50+ MCQs builds pattern recognition for these traps.
- Q16. A solid sphere of radius 6 cm is dropped into a cylindrical vessel of radius 8 cm partly filled with water. The rise in water level is: (A) 4.5 cm (B) 3 cm (C) 6 cm (D) 9 cm
- Answer: (A) 4.5 cm. Volume of sphere = (4/3)π×216 = 288π cm³. This equals volume of water displaced = πr²h = π×64×h. So 288π = 64πh, h = 288/64 = 4.5 cm.
- Q17. The total surface area of a solid cylinder of radius 7 cm and height 10 cm is: (A) 440 cm² (B) 528 cm² (C) 748 cm² (D) 880 cm²
- Answer: (C) 748 cm². TSA = 2πr(h + r) = 2×(22/7)×7×(10 + 7) = 44×17 = 748 cm².
- Q18. A cone of slant height 13 cm and base radius 5 cm is given. Its curved surface area is: (A) 65π cm² (B) 130π cm² (C) 325π cm² (D) 260π cm²
- Answer: (A) 65π cm². CSA = πrl = π×5×13 = 65π cm².
How to Attempt MCQs in the CBSE Board Paper
Section A of the CBSE Class 10 Mathematics paper contains 20 MCQs of 1 mark each, covering all chapters. Surface Areas and Volumes typically contributes 2-3 MCQs. Time management is crucial: aim to solve all 20 MCQs in 20-25 minutes, leaving 2.5-3 hours for subjective sections. Read each question twice to avoid misreading 'diameter' as 'radius' or 'volume' as 'surface area'. Write the formula in the margin if allowed, then substitute. If calculation is lengthy, check whether options are far apart — you might estimate. For Assertion-Reason, evaluate A and R independently first, then check logical connection. If stuck, mark a guess (no negative marking in CBSE) and move on; return if time permits. In numerical MCQs, back-substitution can verify: plug your chosen answer back into the condition. CBSETUTOR.ai offers adaptive MCQ practice with instant photo-upload solving and step-by-step hints at ₹999/month (one price for Classes 6-12, 3-day free trial). Students report saving 30-40 minutes per paper through timed MCQ drills and formula-flash modules on the platform.
- Read the question stem carefully and underline keywords: 'radius', 'diameter', 'slant height', 'total surface area', 'curved surface area'.
- Write down the standard formula before substituting numbers to avoid mid-calculation confusion.
- Check units in the question and options; convert if necessary (cm to m, cm³ to litres).
- Use elimination: discard obviously incorrect options (e.g. negative area, or an area larger than a bounding box).
- For Assertion-Reason, verify truth of each statement separately, then check if R logically supports A.
- Mark your answer on the OMR sheet immediately to avoid transfer errors at the end.
- If a question takes over 90 seconds, skip it, attempt others, and return if time allows.
Frequently asked questions
How many MCQs on Surface Areas and Volumes appear in the CBSE Class 10 board exam?+
Typically 2-3 MCQs out of the 20 in Section A are from Chapter 12 Surface Areas and Volumes. Each carries 1 mark. Topics include frustum, combinations, and conversions.
What is the frustum of a cone and which formula is most often tested?+
A frustum of a cone is the portion remaining after slicing off the top with a plane parallel to the base. The volume formula V = (1/3)πh(r₁² + r₂² + r₁r₂) is frequently tested in both MCQs and descriptive questions.
How do I avoid mixing up radius and diameter in MCQs?+
Always underline or highlight whether the question gives radius or diameter. Write r = d/2 explicitly in the margin before substituting into area or volume formulas. This single step prevents most calculation errors.
Are Assertion-Reason questions difficult in this chapter?+
Assertion-Reason MCQs test conceptual understanding rather than computation. Read both statements independently, decide truth, then check if Reason explains Assertion. Practice 10-15 A-R questions to master the format.
What is the best way to remember so many surface area and volume formulas?+
Group formulas by shape: sphere family (4πr², (4/3)πr³), cylinder family (2πrh, πr²h), cone family (πrl, (1/3)πr²h), frustum. Write them on a flashcard and revise daily for one week before the exam.
Can I use a calculator for MCQs in the CBSE Class 10 Maths board paper?+
No, calculators are not allowed in CBSE board exams. All arithmetic must be done manually. Practice squaring two-digit numbers, multiplying with 22/7, and simplifying roots to build speed.
How are combination-of-solids questions set in MCQ format?+
A typical MCQ gives dimensions of a combined shape (e.g. cone on cylinder) and asks for total surface area or volume. The trap options include answers that double-count the common base or omit the slant-height calculation.
What is a common mistake in conversion-of-solids MCQs?+
Students often equate surface areas instead of volumes. Remember: when a solid is melted and recast, volume remains constant but surface area changes. Always write Volume₁ = Volume₂ as the starting equation.
Is it necessary to practice HOTS MCQs for scoring 80+ in Class 10 Maths?+
Yes. HOTS MCQs and application problems together contribute 25-30 marks. Practicing 20-30 HOTS questions from Surface Areas and Volumes sharpens problem-solving and boosts confidence for Sections C and D as well.
How does CBSETUTOR.ai help with MCQ practice for this chapter?+
CBSETUTOR.ai offers unlimited adaptive MCQ drills, instant photo-upload doubt solving, and formula flashcards for Surface Areas and Volumes. At ₹999/month (Classes 6-12, one price, 3-day free trial), students get 24×7 AI tutor support to master every question type before the board exam.
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