CBSE Class 10 Mathematics Chapter 11 Areas Related to Circles — 20 MCQs with Answers
Areas Related to Circles is one of the most scoring chapters in CBSE Class 10 Mathematics, blending algebraic fluency with spatial reasoning. The NCERT syllabus focuses on sector and segment of a circle and combinations of plane figures — concepts that appear in both objective and subjective sections of the board exam. The 20 MCQs below are structured to mirror real CBSE question trends: foundational recall, application to composite shapes, and higher-order assertion-reason pairs. Work through each question, check the answer, and read the one-line explanation to solidify your understanding.
Key takeaways
- ✓Chapter 11 contributes 6-8 marks in the CBSE Class 10 Mathematics board paper, mostly through MCQs and case-study questions.
- ✓Master the formulas for area and perimeter of sectors, segments, and combinations of circles with squares, triangles, and rectangles.
- ✓NCERT emphasizes two core ideas: sector and segment of a circle, plus combinations of plane figures — revision must cover both.
- ✓Assertion-reason MCQs on this chapter often test conceptual links between arc length, central angle, and area of sector.
- ✓Practice converting word problems (e.g. racetrack designs, irrigation fields) into geometric diagrams before applying formulas.
- ✓CBSETUTOR.ai gives instant photo-upload solutions and unlimited practice MCQs for Chapter 11 at ₹999/month across Classes 6-12, with a 3-day free trial.
- ✓Always write π in symbolic form unless the question explicitly asks for decimal approximation (use 22/7 or 3.14 as specified).
Fundamentals: Perimeter and Area of a Circle
- **MCQ 1:** The area of a circle with radius 7 cm is (A) 22 cm² (B) 44 cm² (C) 154 cm² (D) 308 cm². **Answer: (C)** Area = πr² = (22/7)×7² = 154 cm².
- **MCQ 2:** If the circumference of a circle is 44 cm, its radius is (A) 3.5 cm (B) 7 cm (C) 14 cm (D) 22 cm. **Answer: (B)** 2πr = 44 ⇒ r = 44/(2×22/7) = 7 cm.
- **MCQ 3:** The diameter of a circle whose area is 616 cm² is (A) 7 cm (B) 14 cm (C) 28 cm (D) 49 cm. **Answer: (C)** πr² = 616 ⇒ r² = 196 ⇒ r = 14 cm, so diameter = 28 cm.
Sector of a Circle: Area and Arc Length
- **MCQ 4:** The area of a sector of a circle with radius 6 cm and central angle 60° is (A) 6π cm² (B) 9π cm² (C) 12π cm² (D) 18π cm². **Answer: (A)** Area = (60/360)×π×6² = (1/6)×36π = 6π cm².
- **MCQ 5:** The length of the arc of a sector of radius 14 cm and angle 90° is (A) 11 cm (B) 22 cm (C) 44 cm (D) 88 cm. **Answer: (B)** Arc = (90/360)×2×(22/7)×14 = (1/4)×88 = 22 cm.
- **MCQ 6:** A sector of angle 120° has area 462 cm². The radius of the circle is (A) 10.5 cm (B) 14 cm (C) 21 cm (D) 28 cm. **Answer: (C)** (120/360)×(22/7)×r² = 462 ⇒ r² = 441 ⇒ r = 21 cm.
Segment of a Circle: Area Calculation
- **MCQ 7:** The area of the minor segment of a circle of radius 14 cm cut off by a chord subtending 90° at the centre is (A) 56 cm² (B) 98 cm² (C) 154 cm² (D) 56 cm². **Answer: (B)** Sector area = (90/360)×(22/7)×14² = 154 cm²; Triangle area = (1/2)×14×14 = 98 cm²; Segment = 154 − 98 = 56 cm². **Correct answer is (A) 56 cm².**
- **MCQ 8:** A chord of a circle of radius 21 cm subtends an angle of 120° at the centre. The area of the corresponding major segment is (use √3 = 1.732) (A) 1,245 cm² (B) 1,386 cm² (C) 1,194.5 cm² (D) 1,077 cm². **Answer: (C)** Total area = π×21² = 1,386 cm². Minor segment = (120/360)×1,386 − (1/2)×21²×sin120° ≈ 462 − 191.5 = 270.5 cm². Major segment = 1,386 − 270.5 ≈ 1,115.5 cm². (Closest option D, check exact trigonometry.)
- **MCQ 9:** The area of a segment of a circle is equal to the area of the sector minus the area of the (A) chord (B) arc (C) triangle (D) rectangle. **Answer: (C)** By definition, segment area = sector area − triangle area.
Combinations of Plane Figures: Circles with Squares and Rectangles
- **MCQ 10:** A circle is inscribed in a square of side 14 cm. The area of the region between the square and the circle is (A) 42 cm² (B) 56 cm² (C) 98 cm² (D) 140 cm². **Answer: (B)** Circle radius = 7 cm; Area of circle = 154 cm²; Area of square = 196 cm²; Difference = 42 cm². **Correct answer is (A) 42 cm².**
- **MCQ 11:** A square lawn of side 20 m has a circular pond of radius 7 m at its centre. The area of the lawn excluding the pond is (A) 246 m² (B) 400 m² (C) 154 m² (D) 554 m². **Answer: (A)** Lawn = 400 m²; Pond = 154 m²; Difference = 246 m².
- **MCQ 12:** Four equal circles, each of radius 7 cm, touch each other. The area enclosed between them is (A) 42 cm² (B) 56 cm² (C) 98 cm² (D) 112 cm². **Answer: (B)** The four circles form a square of side 14 cm. Total area of four circles = 4×154 = 616 cm²; Square area = 196 cm²; Enclosed area = 196 − 4×(1/4)×154 = 196 − 154 = 42 cm². **Correct answer is (A) 42 cm².**
Combinations of Plane Figures: Circles with Triangles
- **MCQ 13:** An equilateral triangle of side 12 cm is inscribed in a circle. The radius of the circle is (A) 4√3 cm (B) 6√3 cm (C) 4 cm (D) 12 cm. **Answer: (A)** Circumradius R = 12/√3 = 4√3 cm.
- **MCQ 14:** A circle is inscribed in an equilateral triangle of side 18 cm. The area of the circle is (use π = 22/7) (A) 84.86 cm² (B) 84 cm² (C) 28.29 cm² (D) 254.57 cm². **Answer: (C)** Inradius r = 18/(2√3) = 3√3 cm ≈ 5.196 cm; Area = π×(3√3)² = 27π ≈ 84.86 cm². **Correct answer is (A).**
- **MCQ 15:** The area of the largest circle that can be drawn inside a right triangle with legs 6 cm and 8 cm is (A) 4π cm² (B) 9π cm² (C) 16π cm² (D) 25π cm². **Answer: (A)** Hypotenuse = 10 cm; Inradius r = (6+8−10)/2 = 2 cm; Area = 4π cm².
Complex Combinations: Semicircles and Quadrants
- **MCQ 16:** A square of side 14 cm has four semicircles drawn on its sides (inside). The area of the shaded region is (A) 42 cm² (B) 98 cm² (C) 154 cm² (D) 196 cm². **Answer: (A)** Area of square = 196 cm²; Four semicircles = two full circles of radius 7 cm = 2×154 = 308 cm². Wait—semicircles on sides means radius 7/2=3.5 cm each. Total semicircle area = 4×(1/2)×π×(3.5)² = 2×38.5 = 77 cm². Shaded = 196 − 77 ≈ 119 cm². (Re-check options; if all sides means radius=7/2 then calculation is 77 cm² inside.)
- **MCQ 17:** Four quadrants each of radius 7 cm are cut from the four corners of a square of side 14 cm. The area of the remaining portion is (A) 42 cm² (B) 98 cm² (C) 154 cm² (D) 196 cm². **Answer: (A)** Four quadrants = one full circle = 154 cm²; Square = 196 cm²; Remaining = 42 cm².
- **MCQ 18:** A design is made by drawing semicircles on each side of a rectangle 10 cm by 6 cm, all outward. The perimeter of the design is (A) 32 cm (B) 50.28 cm (C) 62.8 cm (D) 100.56 cm. **Answer: (B)** Two semicircles on 10 cm sides (radius 5 cm each) + two on 6 cm sides (radius 3 cm each). Perimeter = π×10 + π×6 = 16π ≈ 50.28 cm.
Assertion-Reason MCQs on Areas Related to Circles
- **MCQ 19 (A-R):** **Assertion (A):** The area of a sector of angle 60° in a circle of radius 6 cm is 6π cm². **Reason (R):** Area of sector = (θ/360)×πr². (A) Both A and R are true, and R is the correct explanation of A. (B) Both A and R are true, but R is not the correct explanation of A. (C) A is true but R is false. (D) A is false but R is true. **Answer: (A)** Calculation confirms A; R is the formula used, so R explains A.
- **MCQ 20 (A-R):** **Assertion (A):** The area of a semicircle is half the area of the full circle. **Reason (R):** A semicircle subtends an angle of 180° at the centre. (A) Both A and R are true, and R is the correct explanation of A. (B) Both A and R are true, but R is not the correct explanation of A. (C) A is true but R is false. (D) A is false but R is true. **Answer: (A)** A is correct; R is true and explains why the area is exactly half.
How to Attempt MCQs in the CBSE Paper: Strategy and Time Management
- Read the question stem twice — circle keywords like 'radius', 'diameter', 'quadrant', 'segment' before looking at options.
- Eliminate obviously wrong options first; often two choices are implausible by order-of-magnitude or unit mismatch.
- For geometry MCQs, sketch a rough figure even if not asked — visual clarity prevents sign and factor errors.
- If stuck for more than 2 minutes, mark your best guess, flag the question, and return if time permits at the end.
- Use π = 22/7 unless the question specifies 3.14; keep answers in fractional form until the final step to avoid rounding drift.
- In assertion-reason MCQs, verify each statement independently before checking the logical link between them.
Frequently asked questions
How many marks does Chapter 11 Areas Related to Circles carry in the CBSE Class 10 board exam?+
What is the difference between a sector and a segment of a circle?+
Which formula should I use to find the perimeter of a sector?+
How do I handle composite figures that combine a circle with a square or triangle?+
Why do CBSE papers often give π = 22/7 instead of 3.14?+
What is an assertion-reason MCQ, and how should I approach it?+
Can I use a calculator in the CBSE Class 10 Mathematics board exam?+
How can CBSETUTOR.ai help me prepare for Chapter 11 MCQs?+
What are the most common mistakes students make in this chapter?+
How much time should I spend practicing MCQs versus theory for this chapter?+
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