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Important Questions: CBSE Class 10 Mathematics Chapter 11 Areas Related to Circles
Areas Related to Circles is a high-scoring chapter in CBSE Class 10 Mathematics, typically fetching 8-10 marks in the board paper. The chapter builds on your understanding of circle geometry from Class 9, focusing on sector and segment of a circle and combinations of plane figures. Questions range from direct formula-based VSAs to multi-step case-based problems. This question bank gives you 18 carefully selected problems mirroring the CBSE pattern, complete with model answers to help you benchmark your preparation.
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Key takeaways
- ✓Chapter 11 Areas Related to Circles typically carries 8-10 marks in the CBSE Class 10 board exam, split across VSA, SA-I, SA-II and case-based questions.
- ✓Core concepts include perimeter and area of sector and segment, and combinations of plane figures like circles inscribed in triangles or squares.
- ✓CBSE frequently tests formula application for area of sector = (θ/360)×πr² and length of arc = (θ/360)×2πr, where θ is in degrees.
- ✓Case-based questions often involve real-life scenarios like circular parks, running tracks, or circular designs where you must identify sectors and segments.
- ✓Common mistakes include using the wrong unit of angle (radians vs degrees), forgetting to subtract areas for segment calculations, and incorrect use of π approximations.
- ✓Practise at least 3-4 combination problems where circles touch triangles, squares, or rectangles — these are examiner favourites for 3-mark and 5-mark questions.
- ✓CBSETUTOR.ai offers 24×7 AI tutoring with photo-upload doubt solving for just ₹999/month across all subjects and classes 6-12, with a 3-day free trial.
Chapter Overview and Marks Weightage in CBSE Board Exam
Chapter 11 Areas Related to Circles appears in Unit IV Geometry of the CBSE Class 10 Mathematics syllabus. The unit carries a total of 15 marks, and this chapter alone contributes 8-10 marks in most years. The 2024 CBSE Class 10 Maths paper had one 2-mark question on sector area, one 3-mark combination problem involving a circle inscribed in a square, and a 5-mark case-based question on a circular park with pathways. The chapter tests your ability to recall formulas for area and perimeter of sectors and segments, apply them to multi-step problems, and solve real-world scenarios involving combinations of plane figures. Expect 1-2 VSA questions (1 mark each), 1 SA-I question (2 marks), 1 SA-II question (3 marks), and often a 5-mark case-based or long-answer question. Because the formulas are standard, full marks are achievable with careful practice and attention to unit conversions.
- Unit IV Geometry total weightage: 15 marks; Chapter 11 typically 8-10 marks
- Question distribution: 1-2 VSA (1 mark), 1-2 SA-I (2 marks), 1 SA-II (3 marks), 1 case-based or LA (5 marks)
- Key NCERT topics: sector and segment of a circle, combinations of plane figures
- Common question types: direct area/perimeter calculation, shaded region problems, word problems on circular tracks or designs
1-Mark Questions: MCQ and Very Short Answer (VSA)
One-mark questions test quick recall of formulas and basic substitution. CBSE typically includes 1-2 such questions in the paper, either as multiple-choice or fill-in-the-blank. Focus on standard definitions and direct application of area and arc-length formulas. These questions often appear in Section A of the paper and should take no more than 30-40 seconds each. Memorise the formula for area of sector, length of arc, and the relationship between sector angle and central angle.
- Q1. If the area of a sector of a circle of radius 7 cm is 77 cm², the central angle of the sector (in degrees) is: (a) 60° (b) 90° (c) 120° (d) 180°. Answer: (d) 180°. Working: Area = (θ/360)×πr² ⇒ 77 = (θ/360)×(22/7)×49 ⇒ θ = 180°.
- Q2. The length of the arc of a circle of radius 14 cm which subtends an angle of 45° at the centre is: (a) 11 cm (b) 22 cm (c) 5.5 cm (d) 7 cm. Answer: (a) 11 cm. Working: Arc = (45/360)×2×(22/7)×14 = 11 cm.
- Q3. The perimeter of a sector of a circle of radius r and angle θ (in degrees) is given by: (a) 2r + (θ/360)×2πr (b) (θ/360)×πr² (c) 2r + (θ/180)×πr (d) (θ/360)×2πr only. Answer: (a) 2r + (θ/360)×2πr (two radii plus arc length).
- Q4. If the circumference of a circle is 44 cm, the area of its semicircle is: (a) 77 cm² (b) 154 cm² (c) 308 cm² (d) 38.5 cm². Answer: (b) 154 cm². Working: 2πr = 44 ⇒ r = 7 cm. Area of semicircle = (1/2)πr² = (1/2)×(22/7)×49 = 77 cm² (check: this is half of full circle 154 cm²).
2-Mark Questions: Short Answer-I (SA-I)
Two-mark questions require one or two steps of calculation, often involving a single geometric figure. CBSE expects you to state the formula, substitute values, and arrive at a numerical answer with correct units. Show your working clearly — even if you make a minor arithmetic error, you can earn a step mark. Typical problems include finding the area of a sector given radius and angle, or the area of a segment when the chord subtends a given angle. Always write the formula first, then plug in the numbers, and simplify step-by-step.
- Q5. Find the area of a sector of a circle of radius 21 cm and central angle 120°. Answer: Area = (θ/360)×πr² = (120/360)×(22/7)×21×21 = (1/3)×(22/7)×441 = 462 cm².
- Q6. A chord of a circle of radius 12 cm subtends an angle of 60° at the centre. Find the area of the corresponding minor segment. (Use π = 3.14 and √3 = 1.732.) Answer: Area of sector = (60/360)×3.14×144 = 75.36 cm². Area of equilateral triangle = (√3/4)×12² = 62.35 cm². Segment area = 75.36 – 62.35 = 13.01 cm².
- Q7. The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 10 minutes. Answer: In 10 min, minute hand sweeps 60° (since 60 min = 360°, 10 min = 60°). Area = (60/360)×(22/7)×14×14 = 102.67 cm².
- Q8. A sector of a circle of radius 10 cm has an arc length of 15.7 cm. Find the central angle of the sector. (Use π = 3.14.) Answer: Arc = (θ/360)×2πr ⇒ 15.7 = (θ/360)×2×3.14×10 ⇒ θ = (15.7×360)/(62.8) = 90°.
3-Mark Questions: Short Answer-II (SA-II)
Three-mark questions involve multi-step reasoning, often combining two or more geometric shapes. Common patterns include finding the area of a shaded region, calculating the perimeter of a sector or segment, or solving word problems on circular tracks or designs. CBSE awards 1 mark for correct formula, 1 mark for substitution and working, and 1 mark for the final answer. If a question asks for both area and perimeter, allocate roughly 1.5 marks to each part. Always label your diagram if the question involves a combination of figures, and clearly state which area you are subtracting from which.
- Q9. A circle is inscribed in a square of side 14 cm. Find the area of the region outside the circle but inside the square. Answer: Radius of inscribed circle = 7 cm (half the side). Area of square = 196 cm². Area of circle = (22/7)×49 = 154 cm². Area outside = 196 – 154 = 42 cm².
- Q10. Find the area of a quadrant of a circle whose circumference is 88 cm. Answer: 2πr = 88 ⇒ r = 14 cm. Area of quadrant = (1/4)πr² = (1/4)×(22/7)×196 = 154 cm².
- Q11. A circular park has a radius of 35 m. A path of width 3.5 m runs around the inside of the park. Find the area of the path. Answer: Inner radius = 35 – 3.5 = 31.5 m. Area of path = π(35² – 31.5²) = (22/7)(1225 – 992.25) = (22/7)×232.75 = 731.5 m².
- Q12. Two circles touch each other externally. The sum of their areas is 650π cm² and the distance between their centres is 50 cm. Find the radii of the circles. Answer: Let radii be r₁ and r₂. r₁ + r₂ = 50 and πr₁² + πr₂² = 650π ⇒ r₁² + r₂² = 650. Solving: (r₁ + r₂)² = 2500 ⇒ r₁² + r₂² + 2r₁r₂ = 2500 ⇒ 2r₁r₂ = 1850 ⇒ r₁r₂ = 925. Solving quadratic: r₁ = 35 cm, r₂ = 15 cm or vice versa.
5-Mark Questions: Case-Based and Long Answer (LA)
Five-mark questions are either case-based (a short paragraph describing a real-life scenario followed by 3-4 sub-questions) or traditional long-answer problems requiring multiple steps and integration of concepts. Case-based questions often involve circular parks, roundabouts, running tracks, or decorative designs. Read the case carefully, extract given dimensions, and identify which parts of the figure are sectors, segments, or combinations. Each sub-question typically carries 1-1.5 marks. For traditional LA questions, show every step: state the formula, substitute, simplify, and box your final answer. If the question involves subtraction of areas, clearly label each area calculation before subtracting.
- Q13. (Case-Based) A circular park of radius 42 m has a path of width 3.5 m running around it on the outside. (a) Find the area of the path. (b) If the cost of paving the path is ₹50 per m², find the total cost. Answer: (a) Outer radius = 42 + 3.5 = 45.5 m. Area of path = π(45.5² – 42²) = (22/7)(2070.25 – 1764) = (22/7)×306.25 = 962.5 m². (b) Cost = 962.5 × 50 = ₹48,125.
- Q14. (Case-Based) A decorative design consists of a square ABCD of side 20 cm with semicircles drawn on each side outside the square. (a) Find the total area of the four semicircles. (b) Find the perimeter of the entire design. Answer: (a) Radius of each semicircle = 10 cm. Area of 4 semicircles = 2πr² = 2×(22/7)×100 = 628.57 cm². (b) Perimeter = 4 × (πr) = 4×(22/7)×10 = 125.71 cm (since each semicircle contributes half circumference and there is no straight edge exposed).
- Q15. A chord AB of a circle of radius 14 cm makes an angle of 90° at the centre O. Find: (a) area of minor sector AOB, (b) area of minor segment, (c) area of major sector. Answer: (a) Minor sector = (90/360)×(22/7)×196 = 154 cm². (b) Area of triangle AOB = (1/2)×14×14 = 98 cm². Segment = 154 – 98 = 56 cm². (c) Major sector = π×196 – 154 = 616 – 154 = 462 cm².
- Q16. (Long Answer) A circular field has a perimeter of 660 m. A square plot is to be marked inside the circle such that all four vertices lie on the circle. Find the area of the square plot. Answer: 2πr = 660 ⇒ r = 105 m. Diameter = 210 m. Diagonal of square = diameter = 210 m. If side of square is a, then a√2 = 210 ⇒ a = 210/√2 = 148.49 m. Area = a² = 22050 m² (approx).
How CBSE Frames Questions from This Chapter
CBSE question setters follow predictable patterns for Areas Related to Circles. They favour problems that combine multiple shapes — circles inscribed in or circumscribed around squares, triangles, or rectangles — because these test both formula recall and spatial reasoning. Word problems are often set in real-life contexts: circular parks with pathways, clock hands sweeping sectors, horses tethered to corners of fields, or decorative rangoli designs. The 2024 and 2023 papers both included one case-based question worth 4-5 marks, structured as a short paragraph followed by 3-4 sub-questions of 1-1.5 marks each. For direct calculation questions, CBSE typically gives the radius and angle, asking for area or arc length, or vice versa. They may also ask you to find the radius or angle when area or perimeter is given, testing algebraic manipulation of the formulas. In 3-mark and 5-mark questions, expect to subtract the area of one shape from another to find shaded regions. CBSE awards partial marks generously — if your method is correct but you make an arithmetic slip, you will still earn step marks, so always show working.
- Common question frame 1: 'Find the area of the shaded region' — requires subtracting areas of circles, sectors, or triangles from rectangles or squares.
- Common question frame 2: 'A chord subtends an angle θ at the centre. Find the area of the segment' — tests sector area minus triangle area.
- Common question frame 3: 'A path of width w runs around (inside or outside) a circular park. Find the area of the path' — requires area of annulus.
- Common question frame 4: Case-based with diagram showing a composite figure, followed by 3-4 sub-questions asking for perimeter, area, cost, or ratio.
- Examiners prefer angles 30°, 45°, 60°, 90°, 120°, 180° because they yield integer or simple fractional answers.
- CBSE often specifies π = 22/7 or π = 3.14 to avoid calculator dependency; follow the instruction strictly.
Common Mistakes Students Make in Areas Related to Circles
Even careful students lose marks in this chapter due to a handful of recurring errors. The most frequent mistake is confusing degrees and radians — CBSE Class 10 uses only degrees, but if you have practised from coaching material that uses radians, you may accidentally apply the wrong formula. Another common slip is forgetting to subtract the triangle area when calculating the area of a segment; many students write only the sector area and lose 1-2 marks. In combination problems, students often add areas when they should subtract, or vice versa, because they do not label the diagram. Calculation errors multiply when you use the wrong value of π — always check the question to see if it specifies π = 22/7 or 3.14. In word problems, unit conversion errors are frequent: a path width given in metres but radius in centimetres, leading to a final answer that is off by a factor of 100 or 10000. Finally, in case-based questions, students rush through the paragraph and miss a critical piece of information, such as 'path runs inside the park' versus 'path runs outside the park', which completely changes whether you subtract or add the width to the radius.
- Mistake 1: Using radian formula (Area = (1/2)r²θ) instead of degree formula (Area = (θ/360)πr²) — CBSE Class 10 uses degrees only.
- Mistake 2: Writing area of sector as answer for area of segment — always subtract triangle area from sector area for segment.
- Mistake 3: Incorrect subtraction order in shaded-region problems — label each area (e.g. A₁, A₂) before subtracting.
- Mistake 4: Using π = 3.14 when question specifies π = 22/7, or vice versa — this can cost you the accuracy mark.
- Mistake 5: Unit mismatch — converting radius from cm to m but forgetting to convert area from cm² to m², or mixing up path width units.
- Mistake 6: In case-based questions, not reading whether path is inside or outside the park — changes the formula for inner/outer radius.
- Mistake 7: Skipping the final step — question asks for cost or ratio, but student stops after finding area.
Sector and Segment of a Circle: Key Formulas and Concepts
A sector is the region enclosed by two radii and the arc between them — think of a pizza slice. A segment is the region between a chord and the arc it cuts off. CBSE Class 10 expects you to know the formulas for area and perimeter of both. For a sector with central angle θ (in degrees) and radius r: area of sector = (θ/360)×πr², length of arc = (θ/360)×2πr, and perimeter of sector = 2r + arc length. For a segment, you must first find the area of the sector, then subtract the area of the triangle formed by the two radii and the chord. If the chord subtends angle θ at the centre, the triangle area = (1/2)r²sin(θ). However, CBSE usually gives θ as 30°, 60°, 90°, 120°, or 180°, so you can use standard triangle formulas (equilateral, right-angled, etc.) instead of sine. The perimeter of a segment = arc length + chord length. These formulas are listed in the NCERT textbook at the start of Chapter 11; memorise them and practise substitution with different values of θ and r.
- Area of sector = (θ/360) × πr²
- Length of arc = (θ/360) × 2πr
- Perimeter of sector = 2r + arc length
- Area of segment = Area of sector – Area of triangle
- For a chord subtending angle θ at centre, triangle area = (1/2)r² sin(θ) or use standard triangle formulas for common angles
- Area of circle = πr², circumference = 2πr (revise these from Class 9)
Combinations of Plane Figures: Circles with Squares, Triangles, and Rectangles
CBSE loves to test your ability to find areas of composite figures where circles are inscribed in or circumscribed around polygons. The key is to relate the radius of the circle to the dimensions of the polygon. For a circle inscribed in a square of side a, the radius r = a/2. For a circle circumscribed around a square (vertices on the circle), the diagonal of the square equals the diameter, so if diagonal = d, then r = d/2, and since d = a√2, we have r = a√2/2. For an equilateral triangle of side a, the radius of the inscribed circle (inradius) is r = a/(2√3) and the radius of the circumscribed circle (circumradius) is R = a/√3. When solving such problems, always draw a clear diagram, label the given dimensions, and write down the relationship between r and the polygon's side or diagonal before applying the area formulas. Questions often ask for the area of the region inside the polygon but outside the circle, or vice versa, so you will subtract one area from the other.
- Circle inscribed in square of side a: radius = a/2. Area outside circle = a² – πr².
- Circle circumscribed around square of side a: diagonal = a√2 = diameter, so r = a√2/2.
- Circle inscribed in equilateral triangle of side a: inradius = a/(2√3).
- Circle circumscribed around equilateral triangle of side a: circumradius = a/√3.
- For a rectangle of length l and breadth b with a circle of radius r inscribed, the circle touches all four sides, so diameter = min(l, b).
- In combination problems, identify the relationship first, then calculate each area, then add or subtract as needed.
Practice Strategy: Using CBSETUTOR.ai for Doubt Solving and Step-by-Step Help
Mastering Areas Related to Circles requires consistent practice with a variety of problems, especially combination figures and word problems. After working through this question bank, attempt the NCERT Exercise 11.1, 11.2, and miscellaneous exercises, plus previous years' CBSE papers from 2019-2024. When you get stuck on a step — say you are unsure whether to add or subtract an area, or you cannot figure out the inradius formula — you need instant, step-by-step help. CBSETUTOR.ai provides exactly that: a 24×7 AI tutor that lets you upload a photo of your problem and get a worked solution tailored to CBSE marking schemes. Unlike generic video lectures, the AI adapts to your specific doubt and shows you the exact steps you are missing. The platform covers all of Class 10 Mathematics and every other subject for classes 6-12, all for a flat ₹999 per month — no hidden charges, no per-subject fees. You also get a 3-day free trial, so you can test the photo-upload solving feature with your toughest Areas Related to Circles problems before committing. Many students use CBSETUTOR.ai as a safety net during revision: solve a problem on your own, then verify your method and answer with the AI. This builds confidence and ensures you are not practising incorrect techniques that will cost you marks in the board exam.
- Upload a photo of any problem from this chapter and get step-by-step solution within seconds.
- AI tutor explains which formula to use, how to substitute, and where students commonly go wrong.
- Covers all NCERT exercises, exemplar problems, and previous years' CBSE papers.
- Flat ₹999/month for all subjects, all classes (6-12); 3-day free trial available.
- Works on phone or desktop — perfect for quick doubt-solving during homework or late-night revision.
- Complements your school teaching and coaching; use it as your personal on-demand tutor.
Revision Checklist: Are You Exam-Ready for Chapter 11?
Use this checklist in the final week before your board exam. Tick each item only if you can do it confidently without referring to your notes. If you are unsure on any point, revisit the corresponding NCERT section and solve 2-3 more problems. Formula recall is non-negotiable — write out all six key formulas on a blank sheet from memory. Then pick a previous year 5-mark question and solve it under timed conditions (7 minutes). If you can score full marks without peeking at the solution, you are ready. If not, identify which step you are weak on and drill that concept. Remember, this chapter is about careful calculation and clear working — speed comes from familiarity, so the more problems you solve, the faster and more accurate you will become. Aim to finish your Chapter 11 questions in the exam with at least 2 minutes to spare for a quick check of units and arithmetic.
- Can you write all six formulas (area and perimeter of sector, segment, and circle) from memory?
- Have you solved at least 10 combination problems involving circles with squares, triangles, or rectangles?
- Can you identify whether a problem requires addition or subtraction of areas just by reading the question?
- Have you practised at least 3 previous years' case-based questions from this chapter?
- Do you know when to use π = 22/7 versus π = 3.14, and can you perform the arithmetic without a calculator?
- Can you draw and label a sector, segment, and composite figure quickly and accurately?
- Have you revised common mistakes and checked your solutions for unit consistency?
Frequently asked questions
How many marks does Chapter 11 Areas Related to Circles carry in the CBSE Class 10 board exam?+
Chapter 11 typically carries 8-10 marks out of the 80-mark theory paper. Expect 1-2 VSA questions (1 mark each), 1-2 SA-I (2 marks each), 1 SA-II (3 marks), and often a 5-mark case-based or long-answer question. The exact distribution varies slightly year to year, but this chapter is consistently high-weightage.
What is the difference between a sector and a segment of a circle?+
A sector is the pizza-slice region between two radii and the arc they cut. A segment is the region between a chord and the arc it cuts off. To find segment area, calculate the sector area first, then subtract the triangle area formed by the two radii and the chord.
Which formulas are most important for this chapter?+
Area of sector = (θ/360)×πr², length of arc = (θ/360)×2πr, perimeter of sector = 2r + arc, area of segment = sector area minus triangle area. Also revise area of circle = πr² and circumference = 2πr. Memorise these six formulas; they cover 90% of exam questions.
How do I find the area of a segment when the chord subtends angle θ at the centre?+
First find area of sector = (θ/360)×πr². Then find area of the triangle formed by the two radii and the chord. For common angles (30°, 60°, 90°, 120°), use standard triangle formulas. Subtract triangle area from sector area to get segment area. Show both steps in your working.
What are the common mistakes in combination problems involving circles and squares?+
Students often use the wrong relationship between radius and side. For a circle inscribed in a square, radius = side/2. For a circle circumscribed around a square, diameter = diagonal = side×√2. Always draw a diagram, label it, and write the relationship before calculating areas. Also, check whether you need to add or subtract areas.
Should I use π = 22/7 or π = 3.14 in my calculations?+
Use the value specified in the question. CBSE usually states 'Use π = 22/7' or 'Take π = 3.14'. If the question is silent, use 22/7 for exact fractional answers or 3.14 if the numbers are decimal-friendly. Never use a calculator approximation like 3.14159 unless the question allows a calculator.
How can I avoid losing marks due to incorrect units or decimal errors?+
Always write the unit (cm, m, cm², m²) immediately after your numerical answer. Double-check unit conversions — if radius is in cm and path width is in m, convert one to match the other before calculating area. For decimals, round only in the final step, and follow the rounding instruction in the question (usually 2 decimal places).
What is the best way to prepare for case-based questions from this chapter?+
Case-based questions describe a real-life scenario (park, track, design) and ask 3-4 sub-questions. Read the paragraph carefully, extract all given dimensions, draw a labelled diagram, and identify which parts are sectors, segments, or combinations. Practise at least 3-4 such questions from previous years' papers and NCERT exemplar. Each sub-question is usually 1-1.5 marks and straightforward if you have understood the setup.
How does CBSETUTOR.ai help with this chapter?+
CBSETUTOR.ai offers 24×7 AI tutoring. Upload a photo of any problem on sectors, segments, or combination figures and get a step-by-step solution instantly. The AI shows which formula to apply, how to substitute values, and where you went wrong if your answer does not match. It covers all NCERT exercises and previous years' CBSE papers. Flat ₹999/month for all subjects and classes 6-12; 3-day free trial available.
How much time should I spend on Chapter 11 questions in the board exam?+
Allocate roughly 1 minute per mark: 1-mark questions should take 30-40 seconds, 2-mark about 2 minutes, 3-mark about 3-4 minutes, and 5-mark case-based about 6-7 minutes. Because the formulas are standard and calculations straightforward, you should aim to finish this chapter's questions with time to spare for a quick accuracy check. If you practise enough, Chapter 11 can be a quick scoring section.
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