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Important Questions: CBSE Class 10 Science Chapter 4 Carbon and its Compounds

Carbon and its Compounds is a high-scoring, concept-heavy chapter in CBSE Class 10 Science that typically delivers 8–10 marks in the board exam. Questions span MCQs on covalent bonding and nomenclature, short-answer items on functional groups and isomers, and long-answer problems on properties of ethanol, ethanoic acid and soaps. This page presents 18 carefully selected important questions with model answers, organized by marks, to help you revise efficiently and confidently.

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Key takeaways

  • Chapter 4 Carbon and its Compounds typically carries 8–10 marks in the CBSE Class 10 Science board exam, split between MCQs, short answers and long answers.
  • Master NCERT definitions of covalent bonding, homologous series, functional groups, isomerism and nomenclature of the first three members of each series.
  • Practice drawing electron-dot structures for covalent compounds like H₂, O₂, CH₄, C₂H₆ and structural formulae for alcohols, aldehydes, ketones, carboxylic acids.
  • Understand chemical properties of ethanol and ethanoic acid, including reactions with sodium, NaOH, Na₂CO₃ and esterification.
  • Know the cleansing action of soaps and why hard water reduces soap efficiency; this 3-mark or 5-mark question appears frequently.
  • Expect one case-based or assertion-reason question on soaps, detergents or fuel-based hydrocarbons in the 2025 pattern.
  • Use CBSETUTOR.ai to upload photos of tricky structural formulae or reaction mechanisms for instant step-by-step solutions, all classes covered at ₹999/month with a 3-day free trial.

Chapter Overview and Marks Weightage in CBSE Class 10 Science Exam

Chapter 4 Carbon and its Compounds appears in Unit II – Periodic Classification of Elements and Chemical Bonding, which together account for roughly 15 marks. Of those, Carbon and its Compounds alone contributes 8–10 marks in the typical 80-mark theory paper. The 2025 CBSE sample paper includes one or two MCQs (1 mark each), one or two VSA/SA-I questions (2 marks each), one SA-II (3 marks) and one long-answer or case-based question (5 marks). The chapter tests both your ability to draw structures and your understanding of reaction mechanisms, nomenclature rules, and real-world applications such as soap chemistry and fuel types. Because the chapter is dense with definitions and diagrams, strategic practice of past-year and model questions is essential. Revision should prioritize NCERT in-text examples, end-of-chapter exercises, and the diagrams for electron-dot structures, homologous series tables and the esterification reaction. Students in metro cities like Delhi and Mumbai often supplement textbook study with coaching notes, but Tier-2 and Tier-3 learners sometimes struggle with structural formulae due to limited hands-on guidance; an AI tutor that accepts photo uploads can bridge that gap effectively.
  • Unit II total: ~15 marks; Carbon chapter alone: 8–10 marks.
  • Typical split: 2 MCQs (2 marks), 1–2 short answers (2–3 marks each), 1 long answer or case study (5 marks).
  • High-yield topics: covalent bonding, homologous series, functional groups, ethanol and ethanoic acid reactions, soaps vs detergents.
  • Diagrams carry marks: electron-dot structures, structural formulae, cleansing action of soap must be drawn neatly and labelled.

One-Mark Questions: MCQs and Very Short Answer (VSA)

These questions test quick recall of definitions, nomenclature and basic properties. The CBSE often asks you to identify a functional group from a structural formula, pick the correct IUPAC name or choose the product of a simple reaction. Although each carries only 1 mark, four such questions can swing your total by 4 marks, so accuracy matters. Below are five representative MCQs with answers. When practicing MCQs, watch out for common traps: confusing aldehydes with ketones, mixing up saturated and unsaturated hydrocarbons, or misidentifying homologous series members. Always cross-check your choice against NCERT definitions. For instance, NCERT defines a homologous series as a family of organic compounds with the same functional group and successive members differing by –CH₂–. The questions below mirror the style seen in 2023 and 2024 board papers and CBSE sample papers. Make sure you can answer each in under 30 seconds during the exam to save time for longer questions.
  • Q1. The molecular formula C₃H₆ represents: (a) an alkane (b) an alkene (c) an alkyne (d) an alcohol. Answer: (b) an alkene. The general formula CₙH₂ₙ corresponds to alkenes; propene (CH₃–CH=CH₂) is C₃H₆.
  • Q2. Which functional group is present in ethanoic acid? (a) –OH (b) –CHO (c) –COOH (d) –CO–. Answer: (c) –COOH (carboxylic acid group).
  • Q3. Detergents are preferred over soaps in hard water because: (a) they are cheaper (b) they do not form insoluble calcium and magnesium salts (c) they lather better (d) they are biodegradable. Answer: (b) they do not form insoluble precipitates with Ca²⁺ and Mg²⁺.
  • Q4. Identify the saturated hydrocarbon: (a) C₂H₄ (b) C₃H₆ (c) C₄H₁₀ (d) C₂H₂. Answer: (c) C₄H₁₀ (butane, alkane, CₙH₂ₙ₊₂).
  • Q5. Carbon exhibits catenation due to: (a) tetravalency (b) small size and strong C–C bonds (c) ability to form multiple bonds (d) low ionization energy. Answer: (b) small atomic size and strong, stable C–C covalent bonds enable long chains.

Two-Mark Questions with Model Answers

Two-mark questions usually ask you to define a term and give one example, draw a simple structure, or write a single balanced equation. CBSE awards 1 mark for the definition or concept and 1 mark for the example or equation. Clarity and correct chemical notation are critical; even a minor mistake in subscript or coefficient can cost you a mark. The four questions below are drawn from recurring themes in past board papers: covalent bonding, homologous series, functional groups and isomerism. When writing your answer in the exam, underline key terms like 'covalent bond', 'homologous series', 'functional group' or 'isomer' to signal the examiner that you have addressed the core concept. Always include the structural formula or equation where asked, because partial answers fetch partial marks. Practice writing these answers in under two minutes each to build speed. Students often lose marks by writing long paragraphs without the required example or equation, so stick to the two-part structure: define, then illustrate.
  • Q6. Define covalent bond. Draw the electron-dot structure of methane (CH₄). [2 marks] Answer: A covalent bond is formed by the sharing of a pair of electrons between two atoms. Methane: H:C:H with H above and below (each H shares one electron with C; C shares four electrons, one with each H, completing octets).
  • Q7. What is a homologous series? Give the general formula of alkanes. [2 marks] Answer: A homologous series is a family of organic compounds having the same functional group, similar chemical properties, and successive members differing by –CH₂– unit. General formula of alkanes: CₙH₂ₙ₊₂.
  • Q8. Write the molecular formula of the first two members of the carboxylic acid homologous series. [2 marks] Answer: First member – Methanoic acid (formic acid): HCOOH or CH₂O₂. Second member – Ethanoic acid (acetic acid): CH₃COOH or C₂H₄O₂.
  • Q9. Define isomers. Draw the structures of two isomers of butane (C₄H₁₀). [2 marks] Answer: Isomers are compounds with the same molecular formula but different structural arrangements. Butane isomers: (1) n-butane CH₃–CH₂–CH₂–CH₃ (straight chain); (2) isobutane (CH₃)₂CH–CH₃ (branched chain, 2-methylpropane).

Three-Mark Questions with Model Answers

Three-mark questions demand more depth: you might compare two concepts, explain a reaction mechanism with an equation, or describe a process such as esterification or saponification. CBSE typically allocates 1 mark for stating the concept, 1 mark for the chemical equation and 1 mark for additional explanation or labelling. The four questions below cover the high-frequency areas: nomenclature and isomerism, reactions of ethanol and ethanoic acid, and the difference between soaps and detergents. When answering, break your response into three clear points or sub-parts. For example, if asked to write the equation for esterification, first define esterification (1 mark), then write the balanced equation with structural formulae (1 mark), and finally mention the role of concentrated H₂SO₄ as a catalyst and dehydrating agent (1 mark). Avoid mixing points into a single paragraph, because examiners award marks point-wise. Many students lose a mark by forgetting to name the catalyst or by omitting the water molecule in the esterification equation. Practice these answers within three to four minutes each, and always double-check your chemical formulae before moving on.
  • Q10. Explain why carbon forms covalent compounds. Give three reasons. [3 marks] Answer: (i) Carbon has 4 valence electrons; losing or gaining 4 electrons to form C⁴⁺ or C⁴⁻ is energetically unfavourable due to high energy required. (ii) Small atomic size allows effective overlap of orbitals, forming strong covalent bonds. (iii) Tetravalency and ability to form single, double and triple bonds enable diverse compound formation.
  • Q11. Write the balanced chemical equation for esterification. Name the catalyst used. [3 marks] Answer: Esterification: CH₃COOH (ethanoic acid) + C₂H₅OH (ethanol) → CH₃COOC₂H₅ (ethyl ethanoate) + H₂O. Catalyst: Concentrated sulphuric acid (H₂SO₄) acts as dehydrating agent and catalyst. The reaction is reversible and requires heating.
  • Q12. Differentiate between soaps and detergents on three points. [3 marks] Answer: (i) Composition – Soaps are sodium or potassium salts of long-chain fatty acids; detergents are sodium salts of sulphonic acids. (ii) Hard water – Soaps form scum with Ca²⁺ and Mg²⁺, reducing efficiency; detergents do not form precipitates. (iii) Biodegradability – Soaps are biodegradable; many detergents have branched chains and are non-biodegradable, causing water pollution.
  • Q13. An organic compound X has molecular formula C₂H₆O. It reacts with sodium to liberate hydrogen gas. Identify X, write its structural formula and the equation of reaction with sodium. [3 marks] Answer: Compound X is ethanol (C₂H₅OH). Structural formula: CH₃–CH₂–OH. Reaction: 2 C₂H₅OH + 2 Na → 2 C₂H₅ONa (sodium ethoxide) + H₂↑. Only alcohols (and water) react with sodium to release hydrogen, confirming X is ethanol.

Five-Mark Questions and Case-Based Questions with Model Answers

Five-mark questions are the foundation of Chapter 4, often asking you to describe a chemical property with equations, explain cleansing action of soap with a diagram, or tackle a case-based scenario involving fuels or functional groups. CBSE awards marks for each distinct point, equation and diagram, so structure your answer into five clear sub-parts. Start with a brief definition or context (1 mark), then present two or three chemical equations with conditions and products (2–3 marks), and conclude with an explanation or diagram (1–2 marks). The three questions below represent the style seen in 2023, 2024 and the 2025 sample paper. Note that case-based questions present a short paragraph followed by sub-questions; read the passage carefully and extract numerical data or key terms before answering. When drawing the cleansing action of soap, label the hydrophilic head, hydrophobic tail, micelle and dirt particle clearly; examiners award a full mark for a well-labelled diagram. Students often rush through five-markers and lose 1–2 marks due to incomplete equations or missing labels. Allocate six to seven minutes per five-mark question during the exam, and practice writing under timed conditions at home.
  • Q14. (a) Write two chemical properties of ethanoic acid with balanced equations. (b) Why is ethanoic acid called a weak acid? [5 marks] Answer: (a) (i) Reaction with sodium carbonate: 2 CH₃COOH + Na₂CO₃ → 2 CH₃COONa + H₂O + CO₂↑ (brisk effervescence). (ii) Reaction with sodium hydroxide (neutralization): CH₃COOH + NaOH → CH₃COONa + H₂O. (b) Ethanoic acid is a weak acid because it does not ionize completely in aqueous solution; only a small fraction of CH₃COOH molecules release H⁺ ions, unlike strong acids like HCl which ionize 100%.
  • Q15. Explain the cleansing action of soap with the help of a diagram. Why do soaps not work well in hard water? [5 marks] Answer: Soap molecules have a hydrophilic (ionic) head (–COO⁻Na⁺) and a hydrophobic (long hydrocarbon) tail. In water, soap molecules surround oil or grease particles with tails pointing inward (toward grease) and heads outward (toward water), forming a spherical aggregate called a micelle. Agitation helps lift the micelle off the fabric, and rinsing washes it away. [Diagram: draw a circle with inward tails, outward heads, grease droplet in center, labelled 'micelle'.] In hard water, soap reacts with Ca²⁺ and Mg²⁺ to form insoluble calcium and magnesium salts (scum): 2 C₁₇H₃₅COONa + Ca²⁺ → (C₁₇H₃₅COO)₂Ca↓ + 2 Na⁺. This scum wastes soap and reduces cleaning efficiency.
  • Q16. A compound X with molecular formula C₂H₄O₂ reacts with sodium hydrogen carbonate to produce a gas that turns lime water milky. (a) Identify X and write its structural formula. (b) Write the equation for its reaction with NaHCO₃. (c) Name the gas evolved. (d) Write the equation for esterification of X with ethanol. [5 marks] Answer: (a) X is ethanoic acid (CH₃COOH). Structural formula: CH₃–COOH. (b) CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂↑. (c) Gas evolved: Carbon dioxide (CO₂), which turns lime water milky by forming CaCO₃. (d) Esterification: CH₃COOH + C₂H₅OH --(conc. H₂SO₄)--> CH₃COOC₂H₅ + H₂O (ethyl ethanoate, fruity smell).

How CBSE Frames Questions from Carbon and its Compounds

Understanding the examiner's approach helps you anticipate question types and prepare targeted answers. CBSE follows NCERT closely: definitions, in-text reactions and end-of-chapter exercises form the backbone of the question paper. For Chapter 4, the board typically includes one MCQ on nomenclature or functional groups, one two-marker on definitions or structures, one three-marker on a chemical reaction (ethanol oxidation, esterification or saponification), and one five-marker on cleansing action or a case study involving fuels and carbon compounds. The 2024 board paper featured a case-based question on biofuels and asked candidates to identify the functional group in ethanol and write the combustion equation. The 2023 paper included a three-mark question on the difference between soaps and detergents and a two-mark question drawing the electron-dot structure of ethene. Assertion-Reason questions introduced in recent years test conceptual links; for example, 'Assertion: Detergents work in hard water. Reason: Detergents do not form insoluble salts with Ca²⁺ and Mg²⁺.' Both statements are true and the reason correctly explains the assertion. CBSE also loves to ask 'Why?' questions: Why is carbon tetravalent? Why does soap not work in hard water? Why is ethanoic acid a weak acid? These require you to explain the underlying chemistry, not just state facts. Finally, diagram-based questions (electron-dot structures, structural formulae, cleansing action) are almost guaranteed; practice drawing neatly with a pencil and labelling clearly in the exam.
  • Stick to NCERT language: use terms like 'covalent bond', 'homologous series', 'functional group', 'catenation', 'isomer', 'esterification', 'saponification', 'micelle'.
  • Equations must be balanced and include states or conditions where relevant (e.g. 'conc. H₂SO₄', '↑' for gas).
  • Marks are awarded point-wise; structure your answer into clear sub-points (a), (b), (c) if the question has sub-parts.
  • Diagram marks: label every part; even a correct diagram without labels may lose a mark.
  • Case-based questions: read the passage twice, underline key data, then answer sub-questions one by one.
  • Assertion-Reason: evaluate each statement independently, then check if the reason explains the assertion.

Common Mistakes Students Make and How to Avoid Them

Even well-prepared students drop marks in Chapter 4 due to a handful of recurring errors. First, many confuse aldehydes (–CHO) and ketones (–CO–) when drawing structural formulae; remember that aldehydes have the carbonyl group at the end of the chain, ketones in the middle. Second, students often write incorrect IUPAC names by forgetting to number the carbon chain from the end nearest the functional group; for example, butan-2-ol, not butan-3-ol. Third, in electron-dot structures, pupils forget to show all valence electrons or draw single lines instead of shared electron pairs; CBSE specifically asks for dot structures, so crosses or dots must be visible. Fourth, when writing the esterification equation, many omit the water molecule or the catalyst label, costing 1 mark. Fifth, the cleansing action diagram is often drawn without labels; always mark 'hydrophilic head', 'hydrophobic tail', 'micelle' and 'grease particle'. Sixth, students mix up saponification (making soap from fats and alkali) with esterification (making ester from acid and alcohol); saponification uses NaOH and produces soap plus glycerol, esterification uses acid catalyst and produces ester plus water. Seventh, in hard-water questions, some write that soap 'does not dissolve' instead of 'forms insoluble calcium/magnesium salts (scum)'. Finally, many lose a mark in case-based questions by not quoting data or terms from the passage in their answer; always refer back to the passage. To avoid these pitfalls, solve at least 10 previous-year questions under timed conditions, compare your answers with NCERT solutions and mark schemes, and use a checklist before submitting your answer sheet in the exam.
  • Aldehyde vs ketone: aldehyde –CHO at chain end; ketone –CO– in the middle.
  • IUPAC numbering: start from the end nearest the functional group.
  • Electron-dot structures: show all 8 electrons around C (or relevant atom) as dots or crosses, not lines.
  • Esterification equation: include + H₂O and label catalyst 'conc. H₂SO₄'.
  • Cleansing action: draw and label the micelle diagram; missing labels = lost mark.
  • Saponification ≠ esterification: saponification uses NaOH, produces soap; esterification uses acid catalyst, produces ester.
  • Hard water: write 'forms insoluble Ca/Mg salts (scum)', not just 'does not dissolve'.
  • Case-based answers: quote the passage; for example, 'As stated, ethanol is a biofuel…'

Additional Practice Questions (Two-Mark and Three-Mark)

To deepen your practice, here are two more questions at the 2-mark and 3-mark level, complete with model answers. Solving a variety of questions builds confidence and helps you recognize patterns in how CBSE phrases its demands. For every question you attempt, time yourself: two-mark questions should take no more than two minutes, three-mark questions three to four minutes. After writing your answer, compare it against the model provided here and check: Have I defined the term? Have I given the correct example or equation? Have I included necessary labels or conditions? Self-assessment sharpens exam technique faster than passive reading. If you find yourself stuck or unsure about a structural formula or reaction, take a photo and upload it to CBSETUTOR.ai; the AI tutor will walk you through the electron-dot structure, name the compound using IUPAC rules and show you the step-by-step mechanism of the reaction, all within seconds. This instant feedback loop is invaluable during revision weeks when waiting for a teacher's response is not practical. The two questions below focus on versatile topics—catenation and the oxidation of ethanol—that often reappear in board exams and pre-board tests across CBSE schools in cities like Bengaluru, Pune, Hyderabad and Kolkata.
  • Q17. What is catenation? Why is carbon's catenation property exceptional compared to other elements? [2 marks] Answer: Catenation is the ability of an atom to form covalent bonds with other atoms of the same element, resulting in chain or ring structures. Carbon exhibits exceptional catenation due to its small atomic size and strong C–C bond (bond energy ~348 kJ/mol), allowing it to form long stable chains and complex molecules, unlike silicon or other elements where bonds are weaker.
  • Q18. Write the oxidation reactions of ethanol. Name the oxidizing agents used. [3 marks] Answer: (i) Mild oxidation (with alkaline KMnO₄ or acidified K₂Cr₂O₇): CH₃CH₂OH + [O] → CH₃CHO (ethanal/acetaldehyde) + H₂O. (ii) Strong oxidation (excess oxidizing agent): CH₃CH₂OH + 2[O] → CH₃COOH (ethanoic acid/acetic acid) + H₂O. Oxidizing agents: Alkaline potassium permanganate (KMnO₄) or acidified potassium dichromate (K₂Cr₂O₇). Controlled heating yields aldehyde; prolonged heating yields carboxylic acid.

Boost Your Preparation with CBSETUTOR.ai

Mastering Carbon and its Compounds requires not just memorization but the ability to draw, name and balance equations under exam pressure. Many students across India—whether in metro hubs like Delhi-NCR, Mumbai and Chennai or smaller towns in Rajasthan, Madhya Pradesh and Uttar Pradesh—struggle to get timely help when they are stuck on a tricky isomer or esterification mechanism late at night. CBSETUTOR.ai solves this problem by giving you a 24×7 AI tutor accessible from your phone. Snap a photo of any question from this chapter—whether it is an electron-dot structure, a structural formula you cannot name, or a reaction whose products you have forgotten—and receive a step-by-step solution within seconds. The platform covers all CBSE classes from 6 to 12 at a single flat fee of ₹999 per month, making it far more affordable than traditional coaching or hourly tutors. You also get a 3-day free trial to test the service with your own doubts before committing. During revision season, instant doubt resolution prevents small gaps from becoming big mistakes in the board exam. Use CBSETUTOR.ai alongside your NCERT textbook and the practice questions on this page for a well-rounded, confident approach to Chapter 4.
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Frequently asked questions

How many marks does Chapter 4 Carbon and its Compounds carry in the CBSE Class 10 Science board exam?+
Chapter 4 typically contributes 8–10 marks out of the 80-mark theory paper. Expect 1–2 MCQs (1 mark each), 1–2 short-answer questions (2–3 marks each) and one long-answer or case-based question (5 marks). The exact distribution varies slightly each year, but the chapter is a high-weightage topic.
What are the most important topics in Carbon and its Compounds for the board exam?+
Focus on covalent bonding and electron-dot structures, homologous series and functional groups, nomenclature and isomerism, chemical properties of ethanol and ethanoic acid (reactions with Na, NaOH, Na₂CO₃, esterification), and the cleansing action of soaps with the hard-water problem. These areas generate 70–80% of the questions.
How should I practice drawing structural formulae and electron-dot structures?+
Start by copying NCERT diagrams for CH₄, C₂H₆, C₂H₄, C₂H₂, ethanol and ethanoic acid. Practice drawing them from memory on blank paper, then label each bond and atom. Use a pencil in the exam for neatness. If you make a mistake, use an eraser rather than overwriting. Regular daily practice for 10 minutes builds muscle memory.
What is the difference between esterification and saponification?+
Esterification is the reaction between a carboxylic acid and an alcohol in the presence of concentrated H₂SO₄ to form an ester and water (e.g., CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O). Saponification is the reaction between a fat (ester of glycerol) and a strong base like NaOH to produce soap (sodium salt of fatty acid) and glycerol. They are reverse-type processes with different reagents.
Why do soaps not work well in hard water, and how do detergents solve this problem?+
Hard water contains Ca²⁺ and Mg²⁺ ions. Soaps (sodium salts of fatty acids) react with these ions to form insoluble calcium and magnesium salts (scum), which wastes soap and reduces lathering. Detergents are sodium salts of sulphonic acids and do not form such insoluble salts, so they remain effective in hard water and lather freely.
How can I remember the general formulae of alkanes, alkenes and alkynes?+
Use the mnemonic '2n+2, 2n, 2n−2': Alkanes CₙH₂ₙ₊₂ (single bonds, saturated), Alkenes CₙH₂ₙ (one double bond, unsaturated), Alkynes CₙH₂ₙ₋₂ (one triple bond, unsaturated). Write out the first three members of each series (methane/ethane/propane; ethene/propene/butene; ethyne/propyne/butyne) and verify the formula fits.
What are functional groups, and which ones must I know for Class 10?+
A functional group is an atom or group of atoms that determines the chemical properties of a compound. For Class 10, know: –OH (alcohol), –CHO (aldehyde), –CO– (ketone), –COOH (carboxylic acid), –O– (ether, basic awareness). NCERT focuses on alcohols, aldehydes, ketones and carboxylic acids; memorize their structures and one example each.
How do I write the IUPAC name of a simple organic compound?+
Step 1: Identify the longest carbon chain (this gives the root name: meth-, eth-, prop-, but-). Step 2: Number the chain from the end nearest the functional group. Step 3: Identify and name the functional group (suffix: -ol for alcohol, -al for aldehyde, -one for ketone, -oic acid for carboxylic acid). Step 4: Combine: prefix (if any) + root + suffix. Example: CH₃CH₂CH₂OH → propan-1-ol.
What is catenation, and why is it unique to carbon?+
Catenation is the ability of an element to form covalent bonds with atoms of the same element, creating long chains or rings. Carbon shows exceptional catenation because its small atomic size and high C–C bond strength (~348 kJ/mol) allow stable, long chains. Silicon and other elements have weaker bonds and show limited catenation, so carbon's property is unique and underlies the diversity of organic chemistry.
Can CBSETUTOR.ai help me with drawing structures and balancing equations for Carbon and its Compounds?+
Yes. Upload a photo of any question—whether it asks for an electron-dot structure, structural formula, IUPAC name or balanced equation—and CBSETUTOR.ai will provide a step-by-step solution with diagrams. The AI tutor is available 24×7, covers all CBSE classes at ₹999/month, and offers a 3-day free trial. It is especially helpful for visual learners who need to see the structure drawn out clearly.

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