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Important Questions: CBSE Class 7 Mathematics Chapter 13 Perimeter and Area
Chapter 13 Perimeter and Area in NCERT Class 7 Mathematics builds on Class 6 concepts by introducing area of parallelograms, triangles, circles and irregular shapes. CBSE term exams allocate 8-12 marks to this chapter, with questions ranging from direct formula application to multi-step word problems involving cost calculations and comparisons. This question bank mirrors actual CBSE exam patterns, grouping questions by marks weightage and providing concise model answers with exact working steps to help you score full marks.
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Key takeaways
- ✓Chapter 13 Perimeter and Area carries 8-12 marks in CBSE Class 7 Mathematics term exams, focusing heavily on circle and parallelogram formulae.
- ✓Area of circle (πr²) and circumference (2πr) questions appear in every CBSE Class 7 paper, often combined with cost or comparison problems.
- ✓Parallelogram and triangle area questions test base-height understanding; CBSE frequently gives dimensions requiring unit conversion.
- ✓Five-mark case-based questions on irregular shapes or real-life applications (garden paths, circular tracks) appeared in 2023-24 sample papers.
- ✓Common mistakes include using diameter instead of radius in circle formulae and forgetting to square the radius in area calculations.
- ✓NCERT Exercise 13.1 and 13.2 provide 70 percent of recurring question patterns in CBSE Class 7 term exams.
- ✓CBSETUTOR.ai offers instant photo-upload solutions for every Perimeter and Area problem at ₹999/month flat for Class 7, with 24×7 AI tutor access.
Chapter Overview and Marks Weightage in CBSE Exams
Perimeter and Area is a high-scoring chapter in CBSE Class 7 Mathematics, consistently contributing 8-12 marks across term exams and sample papers released by CBSE in 2023-24 and 2024-25. The chapter extends Class 6 mensuration by introducing area formulae for parallelograms (base × height), triangles (½ × base × height), and circles (πr²), plus circumference of circle (2πr). CBSE question papers typically include two to three direct formula-based questions (2-3 marks each) and one case-based or application question (5 marks). The 2024 CBSE sample paper for Class 7 featured a five-mark question on a circular park with a rectangular flower bed inside, testing both circle area and subtraction of irregular shapes. Mastery of this chapter is crucial because mensuration reappears with added complexity in Class 8 (surface areas), Class 9 (Heron's formula) and Class 10 board exams (combined solids).
- Direct formula questions: 4-6 marks (circle area, parallelogram area, triangle area)
- Word problems with cost or rate: 2-4 marks (wire fencing, tiling, painting costs)
- Irregular shapes (composite figures): 3-5 marks (subtract/add areas of standard shapes)
- Case-based questions: 5 marks (real-life scenarios like gardens, tracks, floor designs)
- Unit conversion traps: CBSE often gives base in metres and height in centimetres to test careful reading
One-Mark Questions (MCQ and Very Short Answer)
One-mark questions test recall of formulae, definitions and basic calculations. CBSE Class 7 term exams include 3-4 such questions from Chapter 13, often as multiple-choice or fill-in-the-blanks. These are scoring opportunities where careless errors in formula recall or unit handling cause mark loss. Always write the formula first, even in MCQs, to avoid substitution mistakes. Practice these six questions under timed conditions to build speed and accuracy for the objective section of your exam paper.
- Q1. The area of a parallelogram with base 8 cm and height 5 cm is: (a) 13 cm² (b) 26 cm² (c) 40 cm² (d) 80 cm² → Answer: (c) 40 cm². Area = base × height = 8 × 5 = 40 cm².
- Q2. The circumference of a circle with radius 7 cm (take π = 22/7) is: (a) 22 cm (b) 44 cm (c) 154 cm (d) 308 cm → Answer: (b) 44 cm. Circumference = 2πr = 2 × (22/7) × 7 = 44 cm.
- Q3. If the area of a triangle is 36 cm² and base is 9 cm, the height is: (a) 4 cm (b) 8 cm (c) 18 cm (d) 27 cm → Answer: (b) 8 cm. Area = ½ × base × height ⇒ 36 = ½ × 9 × h ⇒ h = 8 cm.
- Q4. A square and a rectangle have the same perimeter 40 cm. If the rectangle has length 12 cm, its breadth is: (a) 8 cm (b) 10 cm (c) 14 cm (d) 16 cm → Answer: (a) 8 cm. Perimeter = 2(l+b) ⇒ 40 = 2(12+b) ⇒ b = 8 cm.
- Q5. The area of a circle with diameter 14 cm (π = 22/7) is: (a) 44 cm² (b) 154 cm² (c) 308 cm² (d) 616 cm² → Answer: (b) 154 cm². Radius = 7 cm, Area = πr² = (22/7) × 7 × 7 = 154 cm².
- Q6. Which formula gives area of a parallelogram? (a) side × side (b) base × height (c) ½ × base × height (d) 2(l+b) → Answer: (b) base × height.
Two-Mark Questions with Model Answers
Two-mark questions in CBSE Class 7 Maths Chapter 13 require one formula application plus a simple calculation step, or a two-step word problem. Marks are split: one for correct formula/method, one for accurate computation. Show all working clearly; even if the final answer is wrong, method marks are awarded. These four questions represent the most common two-mark patterns from NCERT Exercise 13.1 and past CBSE papers. Practice writing concise steps — examiners appreciate structured solutions that are easy to follow and mark.
- Q7. Find the area of a parallelogram whose base is 15 cm and height is 8.4 cm. → Solution: Area = base × height = 15 × 8.4 = 126 cm². Answer: 126 cm².
- Q8. The circumference of a circle is 88 cm. Find its radius (π = 22/7). → Solution: Circumference = 2πr ⇒ 88 = 2 × (22/7) × r ⇒ 88 = (44/7) × r ⇒ r = (88 × 7)/44 = 14 cm. Answer: 14 cm.
- Q9. A triangle has base 12 m and area 96 m². Calculate its height. → Solution: Area = ½ × base × height ⇒ 96 = ½ × 12 × h ⇒ 96 = 6h ⇒ h = 16 m. Answer: 16 m.
- Q10. The length of a rectangular field is 24 m and breadth is 18 m. Find the cost of fencing it at ₹15 per metre. → Solution: Perimeter = 2(l+b) = 2(24+18) = 84 m. Cost = 84 × 15 = ₹1,260. Answer: ₹1,260.
Three-Mark Questions with Detailed Working
Three-mark questions test multi-step reasoning: applying two formulae, unit conversions, or solving for an unknown dimension. CBSE allocates marks for formula statement (1 mark), correct substitution (1 mark) and final answer with units (1 mark). These questions often involve composite shapes or cost calculations where you must find area first, then multiply by rate. The following four questions mirror CBSE sample papers and NCERT exemplar problems. Write each step on a new line and box your final answer to signal completion clearly to the examiner.
- Q11. A rectangular plot measures 125 m by 78 m. A path of uniform width 3 m runs inside along the boundary. Find the area of the path. → Solution: Outer dimensions: 125 m × 78 m. Inner dimensions: (125−6) m × (78−6) = 119 m × 72 m. Area of path = Outer area − Inner area = (125×78) − (119×72) = 9750 − 8568 = 1182 m². Answer: 1182 m².
- Q12. The area of a parallelogram is 338 cm² and its height is 13 cm. Find the length of its base. → Solution: Area = base × height ⇒ 338 = base × 13 ⇒ base = 338/13 = 26 cm. Answer: 26 cm.
- Q13. Find the area of a circular ring bounded by two concentric circles of radii 21 cm and 14 cm (π = 22/7). → Solution: Area of ring = π(R² − r²) = (22/7)(21² − 14²) = (22/7)(441 − 196) = (22/7) × 245 = 22 × 35 = 770 cm². Answer: 770 cm².
- Q14. A triangle and a parallelogram have the same base 16 cm and equal areas. If the height of the parallelogram is 10 cm, find the height of the triangle. → Solution: Area of parallelogram = 16 × 10 = 160 cm². Area of triangle = ½ × 16 × h = 160 ⇒ 8h = 160 ⇒ h = 20 cm. Answer: 20 cm.
Five-Mark Questions and Case-Based Problems
Five-mark questions are application-oriented, combining multiple concepts from Perimeter and Area with real-life contexts. The 2024 CBSE sample paper introduced a case study on a school playground with a circular track and rectangular badminton court inside. These questions assess reading comprehension, formula selection, multi-step calculation and interpretation. Marks distribution: understanding/diagram (1 mark), two formula applications (2 marks), calculations (1.5 marks), final answer with conclusion (0.5 mark). Attempt these even if time is short; partial working fetches 2-3 marks. The three questions below represent the latest CBSE case-based format.
- Q15. A circular park of radius 42 m has a path of width 3.5 m running around it on the outside. Find (i) the area of the path, (ii) the cost of paving the path at ₹120 per m² (π = 22/7). → Solution: Outer radius R = 42 + 3.5 = 45.5 m. Inner radius r = 42 m. Area of path = π(R² − r²) = (22/7)(45.5² − 42²) = (22/7)(2070.25 − 1764) = (22/7) × 306.25 = 962.5 m². Cost = 962.5 × 120 = ₹1,15,500. Answer: (i) 962.5 m², (ii) ₹1,15,500.
- Q16. A field is in the shape of a parallelogram with base 150 m and height 80 m. A triangular portion with base 60 m and height 40 m is used for a tent. Find the area available for farming, and the cost of ploughing at ₹8 per m². → Solution: Area of parallelogram = 150 × 80 = 12,000 m². Area of triangle = ½ × 60 × 40 = 1,200 m². Farming area = 12,000 − 1,200 = 10,800 m². Cost = 10,800 × 8 = ₹86,400. Answer: 10,800 m², ₹86,400.
- Q17. A rectangular garden 90 m long and 75 m wide has two cross-paths, each 5 m wide, running parallel to the length and breadth. Find the area of the paths and the cost of gravelling them at ₹60 per m². → Solution: Area of path along length = 90 × 5 = 450 m². Area of path along breadth = 75 × 5 = 375 m². Overlapping square = 5 × 5 = 25 m². Total path area = 450 + 375 − 25 = 800 m². Cost = 800 × 60 = ₹48,000. Answer: 800 m², ₹48,000.
- Q18. Case Study: A school plans to build a circular playground of diameter 84 m with a rectangular basketball court of length 28 m and breadth 15 m inside. (i) Find the area of the playground (π = 22/7). (ii) Find the area of the basketball court. (iii) How much area is left for other activities? → Solution: (i) Radius = 42 m, Area = πr² = (22/7) × 42 × 42 = 5,544 m². (ii) Area of court = 28 × 15 = 420 m². (iii) Remaining area = 5,544 − 420 = 5,124 m². Answer: (i) 5,544 m², (ii) 420 m², (iii) 5,124 m².
How CBSE Frames Questions from This Chapter
CBSE question paper setters for Class 7 Mathematics follow a predictable pattern when setting questions from Chapter 13 Perimeter and Area. Understanding these patterns helps you prepare strategically and manage exam time efficiently. First, direct formula questions (one or two marks) always appear from circle area, circumference, parallelogram and triangle — usually with integer values of radius or dimensions to avoid calculator dependency. Second, CBSE loves unit conversion traps: giving base in metres and height in centimetres, or radius in metres but asking answer in square centimetres. Third, cost or rate problems (fencing, tiling, painting) appear in 2-3 mark questions, testing your ability to link area or perimeter with multiplication. Fourth, irregular or composite shapes (circle plus rectangle, parallelogram minus triangle) are set as 3-4 mark questions requiring subtraction or addition of standard areas. Fifth, case-based questions introduced in 2023 onwards present a real-life scenario (park, field, playground) with a short paragraph and 2-3 sub-questions totalling five marks. These test reading comprehension alongside calculation. Sixth, CBSE avoids non-terminating decimals; π is always given as 22/7 or 3.14 with radius chosen so calculations simplify. Finally, the marking scheme rewards step-wise working: even if your final answer is wrong, you earn method marks for writing the correct formula and attempting substitution. Always write formulae explicitly and show every arithmetic step.
- Formula recall questions: 1-2 marks, often MCQ or fill-in-the-blank format
- Single-step application: 2 marks, e.g. find area of parallelogram given base and height
- Two-step word problems: 3 marks, e.g. find area then calculate cost at given rate
- Composite/irregular shapes: 3-4 marks, requiring addition or subtraction of two areas
- Case studies with sub-questions: 5 marks total, typically three parts (a), (b), (c)
- Emphasis on real-life contexts: gardens, pathways, running tracks, floor tiling, painting walls
Common Mistakes Students Make (and How to Avoid Them)
Every year, CBSE Class 7 students lose 3-5 marks in Chapter 13 due to a handful of recurring errors. First, confusing diameter and radius: questions state 'a circle of diameter 28 cm' but students substitute 28 directly into πr², forgetting radius = diameter/2. Always underline or highlight 'diameter' in the question and write 'r = d/2' as your first step. Second, forgetting to square the radius in area of circle: writing π × r instead of π × r². Third, using the wrong formula for triangles: some students write base × height instead of ½ × base × height, losing the factor of ½. Fourth, unit mismatches: the question gives base in metres and height in centimetres, but students multiply without converting both to the same unit. CBSE marking guidelines award zero for answers with inconsistent units. Fifth, in composite shapes, double-counting overlapping regions or forgetting to subtract the inner area from the outer area (in path problems). Sixth, not writing units in the final answer (cm², m², etc.) — this costs 0.5 marks in 3- and 5-mark questions. Seventh, calculation errors in fraction multiplication, especially with π = 22/7: rushing through 22/7 × 49 and getting 144 instead of 154. Always cross-cancel before multiplying. Eighth, in case-based questions, answering only one sub-question and leaving the rest blank — attempt all parts even if unsure, as each sub-question carries separate marks. Finally, skipping the formula statement: even if you know the calculation, examiners need to see 'Area = base × height' or 'Circumference = 2πr' to award method marks. Make it a habit to write the formula in every solution, no matter how simple the question appears.
- Diameter vs. radius confusion: Halve diameter before using in formulae (underline 'd' or 'r' in question)
- Forgetting to square radius: πr² not πr (write r × r explicitly if needed)
- Triangle area formula: ½ × base × height, not base × height
- Unit conversion: Convert all dimensions to the same unit before calculation; write conversion step
- Composite shapes: Draw a clear diagram labeling outer and inner dimensions to avoid overlap errors
- Missing units: Always write cm², m², etc. in final answer and box it
- Fraction arithmetic: Cross-cancel in (22/7) × (49/1) to get 22 × 7 = 154, avoiding decimal mistakes
- Partial attempts: In five-mark questions, answer all sub-parts; each carries 1-2 marks independently
Connecting Chapter 13 to Real-Life and Higher Classes
Perimeter and Area is not just an exam chapter; its concepts underpin everyday decisions and advanced mathematics. In real life, parents use perimeter to estimate fencing costs for a plot, calculate carpet area when buying a flat, or determine paint quantity for walls based on area. Architects and civil engineers rely on these formulae for floor plans, land surveys and material estimation. In sports, the dimensions of circular running tracks (circumference) and rectangular courts (area) are designed using these principles. For Class 7 students, this chapter lays the groundwork for Class 8 mensuration (surface area and volume of cubes, cuboids, cylinders), Class 9 Heron's formula for triangle area without height, and Class 10 coordinate geometry where area of triangles is computed using vertices. Competitive exams like NTSE and Olympiads frequently pose tricky composite-shape problems rooted in Chapter 13 concepts. Mastering area and perimeter now builds the spatial reasoning and formula manipulation skills essential for higher mathematics, making it one of the most practically useful chapters in the CBSE Class 7 Mathematics syllabus.
- Real-estate: Calculating carpet area (usable floor area) when buying or renting a flat
- Home improvement: Estimating tiles needed for flooring (area) or border strips (perimeter)
- Agriculture: Farmers compute field area to decide seed quantity and irrigation requirements
- Sports: Track dimensions (400 m standard circumference), court areas for basketball, badminton
- Class 8 link: Surface area and volume (cylinder = 2πrh + 2πr²) builds on circle circumference and area
- Class 9 link: Heron's formula (area when three sides known) extends triangle area concepts
- Class 10 link: Coordinate geometry area of triangle using ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|
- Competitive exams: NTSE, Olympiads, NMTC feature multi-shape area puzzles needing Chapter 13 mastery
Smart Preparation Strategy for Chapter 13
To score full marks in Perimeter and Area questions, follow this proven four-week strategy used by top CBSE scorers. Week 1: Memorise all five core formulae (parallelogram, triangle, circle area, circle circumference, rectangle/square) by writing them ten times daily and testing yourself without looking. Create a formula card and keep it on your study desk. Week 2: Solve all NCERT Exercise 13.1 and 13.2 problems (about 25 questions total) without looking at solutions first; check answers only after attempting. Identify which question types take you longest and redo those. Week 3: Practice previous year CBSE sample papers (2022, 2023, 2024 available on cbse.nic.in) under timed conditions — allocate exactly 2 minutes per mark, so a 5-mark question gets 10 minutes. Mark questions you couldn't finish in time and reattempt them. Week 4: Focus on common mistakes using the list above; redo every problem where you lost marks due to unit errors, formula confusion or calculation slips. Attempt at least two full-length mock tests covering all chapters, ensuring you complete the Chapter 13 section within 15-18 minutes. On exam day, tackle Chapter 13 questions in order of increasing marks (1-mark MCQs first, case study last) to secure easy marks before investing time in lengthy problems. If stuck on a five-mark question, write the formula and attempt the first sub-part to earn partial credit, then move on rather than wasting time. Finally, reserve three minutes at the end to recheck units in every answer and verify that you have squared the radius in circle area calculations.
- Formula mastery first: Write all five formulae daily for one week until automatic recall
- NCERT is non-negotiable: Solve every Exercise 13.1 and 13.2 question; 70% of exam patterns come from these
- Timed practice: Use a stopwatch; Class 7 students should solve a 3-mark question in 6 minutes max
- Error log: Maintain a notebook of mistakes (formula, unit, calculation) and review before the exam
- Mock tests: Attempt 2-3 full-length papers; treat them like real exams (no phone, timed, neat writing)
- Partial credit strategy: In long questions, write the formula and attempt at least the first step even if unsure
- Revision checklist: Day before exam, rewrite all formulae, scan common mistakes list, skim your error log
- Exam day sequence: Solve 1-mark, 2-mark, 3-mark, 5-mark in that order to secure easier marks first
How CBSETUTOR.ai Helps You Master Chapter 13
For CBSE Class 7 students who find Perimeter and Area challenging or want to move beyond school and coaching notes, CBSETUTOR.ai offers a 24×7 AI tutor designed specifically for Indian curricula. Simply photograph any Chapter 13 problem — whether from NCERT, your school worksheet, or previous year papers — and receive a step-by-step solution in seconds, explained in clear language that mirrors how CBSE expects working to be shown. Unlike generic AI tools, CBSETUTOR.ai is trained on NCERT terminology (parallelogram base and height, not 'side dimensions'), CBSE marking schemes (formula statement → substitution → answer with units), and common Indian textbook notations (π = 22/7, not just 3.14). It catches typical Class 7 mistakes like forgetting to convert centimetres to metres or using diameter instead of radius, providing hints before revealing the full solution so you learn rather than just copy. For ₹999 per month — one flat price covering every chapter of Class 7 Mathematics and all other subjects from Class 6 to 12 — your child gets unlimited question solving, instant doubt clearing at night when coaching centres are closed, and personalised practice questions targeting weak areas identified by the AI. Parents in cities like Bangalore, Delhi-NCR, Mumbai and Pune, where coaching fees run ₹3,000-5,000 monthly, find this particularly valuable. A three-day free trial lets you test the platform with actual Chapter 13 problems before committing. Visit CBSETUTOR.ai to start your trial and give your child a dedicated AI tutor who is always available, never impatient, and speaks the language of CBSE Class 7 Mathematics fluently.
- Photo-upload solving: Snap any Chapter 13 question and get CBSE-style step-by-step working instantly
- NCERT-aligned: Uses exact terminology (base, height, circumference, area) from Class 7 textbook
- Mistake alerts: AI detects common errors (diameter vs. radius, missing ½ in triangle) and warns you
- Hint mode: Provides progressive hints rather than full solution, building problem-solving confidence
- Unlimited access: ₹999/month flat for all subjects and classes (6-12), no per-question charges
- 24×7 availability: Get help at 11 PM when revising for next day's test, no waiting for tutor calls
- 3-day free trial: Test with your own NCERT or school questions before subscribing
- Affordable: Costs less than one-third of typical monthly coaching fees in metro cities
Frequently asked questions
How many marks does Chapter 13 Perimeter and Area carry in CBSE Class 7 Mathematics term exams?+
Chapter 13 typically carries 8-12 marks in CBSE Class 7 term exams, distributed as 2-3 short questions (1-2 marks each), one or two medium questions (3 marks) and one case-based or application question (5 marks). The 2024 CBSE sample paper allocated 10 marks to this chapter across four questions.
What is the most common mistake students make in circle area problems?+
The most common mistake is using diameter directly in the area formula instead of radius. Students see 'circle of diameter 28 cm' and substitute into πr² as π×28×28, forgetting that radius = diameter÷2 = 14 cm. Always write r = d/2 as the first step when diameter is given.
Which NCERT exercises should I prioritise for CBSE Class 7 Chapter 13 exam preparation?+
Prioritise NCERT Exercise 13.1 (area of parallelograms and triangles) and Exercise 13.2 (circumference and area of circles). These two exercises contain about 25 questions that mirror 70 percent of recurring CBSE exam patterns. Solve every question without looking at solutions first, then check answers and redo mistakes.
How do I solve composite shape questions where a triangle is removed from a parallelogram?+
First, calculate the area of the parallelogram using base × height. Second, calculate the area of the triangle using ½ × base × height. Third, subtract the triangle area from the parallelogram area. Always draw a clear diagram labeling all given dimensions to avoid confusion about which base and height correspond to which shape.
Why does CBSE always give π as 22/7 instead of 3.14 in Class 7 questions?+
CBSE uses π = 22/7 in Class 7 to allow exact fractional answers without decimals and to test students' ability to multiply and simplify fractions. Questions are designed so that denominators cancel cleanly (e.g., radius 7 cm, 14 cm, 21 cm). Always cross-cancel before multiplying: (22/7)×49 = 22×7 = 154, not 22×49÷7.
How much time should I spend on a five-mark case-based question from Chapter 13 in the exam?+
Allocate approximately 10 minutes for a five-mark question (2 minutes per mark is the thumb rule). Spend 1-2 minutes reading the case study carefully and underlining key data, 6-7 minutes solving the three sub-parts, and 1 minute rechecking units and final answers. If stuck, write the formula and attempt the first sub-part to earn partial credit.
What is the formula for the area of a path running around a rectangular field?+
If the path has uniform width w running inside the boundary, subtract the inner rectangle area from the outer rectangle area. Outer dimensions remain as given; inner dimensions are (length − 2w) and (breadth − 2w). Area of path = (L×B) − [(L−2w)×(B−2w)]. Always double-subtract the width because the path runs along both opposite sides.
How can I avoid unit conversion mistakes in Perimeter and Area problems?+
Before starting any calculation, check that all dimensions are in the same unit. If base is 5 m and height is 200 cm, convert immediately: either write both as 5 m and 2 m, or 500 cm and 200 cm. Circle the conversion in your working so the examiner sees you addressed it. Write the conversion as a separate line: '200 cm = 2 m' earns you method marks even if subsequent calculation is wrong.
Does CBSETUTOR.ai cover previous year CBSE Class 7 Chapter 13 questions?+
Yes, CBSETUTOR.ai includes a question bank of previous year CBSE sample papers, school exam papers from major cities, and NCERT exemplar problems for Chapter 13. You can upload any past question as a photo and receive instant solutions with CBSE marking-scheme compliant step-by-step working. The AI also generates similar practice questions targeting your weak areas identified from upload history.
If I forget the area formula for a parallelogram during the exam, can I derive it?+
Yes. Remember that a parallelogram can be converted into a rectangle by cutting a triangular portion from one side and attaching it to the other side, without changing area. The resulting rectangle has the same base and height as the parallelogram, so Area = base × height. Writing this derivation in the exam earns you method marks even if you forgot the direct formula, though memorising it is faster.
Related resources
Class 7 Mathematics Chapter 13 Perimeter and Area — Formulas & Key PointsCBSE Class 7 Mathematics Chapter 13 Perimeter and Area Worksheet with AnswersImportant Questions: CBSE Class 7 Mathematics Chapter 12 Visualising Solid ShapesClass 7 Mathematics Chapter 12 Visualising Solid Shapes — Formulas & Key PointsAI Tutor for Class 7: The Smart Alternative to TuitionAI Tutor for Class 7 Science: Learn Faster with Instant HelpNCERT Solutions for Class 9 Mathematics Chapter 1: Number Systems – Complete GuideImportant Questions: CBSE Class 9 Mathematics Chapter 2 Polynomials
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