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Class 12 Mathematics Chapter 7 Integrals — Formulas & Key Points
Chapter 7 Integrals is one of the highest-weighted chapters in CBSE Class 12 Mathematics, contributing around 10-12 marks in the Board exam. Integration techniques underpin coordinate geometry, differential equations and application problems. This formula sheet organises every standard integral, property, theorem and technique from your NCERT textbook into quick-reference tables, memory aids and worked examples so you can revise efficiently.
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Key takeaways
- ✓Integration is the reverse process of differentiation; every derivative formula yields a corresponding integral formula.
- ✓Indefinite integrals produce a family of functions with an arbitrary constant C; definite integrals yield a real number representing area under the curve.
- ✓The Fundamental Theorem of Calculus connects derivatives and integrals: integral from a to b of f'(x)dx equals f(b) minus f(a).
- ✓Substitution method simplifies integrals by replacing a function with a new variable; partial fractions decompose rational functions into simpler fractions.
- ✓Standard forms for trigonometric, exponential and rational functions must be memorised verbatim for quick pattern recognition in Board exams.
- ✓Properties of definite integrals reduce computation significantly, especially for even and odd functions over symmetric intervals.
- ✓Common mistakes include forgetting the constant of integration in indefinite integrals and incorrect limits transformation during substitution in definite integrals.
Standard Integration Formulas — Algebraic and Power Functions
These formulas form the backbone of all integration work. Memorise them as automatic responses. Every formula assumes the integrand is a function of x and includes the arbitrary constant C for indefinite integrals. The power rule is the most frequently used formula, applicable whenever you see x raised to a rational or real exponent. Remember that the integral of 1/x is the natural logarithm, not a power function. The constant multiple rule allows you to factor out coefficients before integrating. When you see a polynomial, break it term by term and apply the power rule individually to each term. These formulas appear directly or after simplification in 70 percent of Board exam integration problems, so fluency here saves precious exam minutes and reduces silly errors during long calculations.
- Power rule works for all real n except n = -1; for n = -1 use the logarithmic form
- Always add the constant of integration C in indefinite integrals; marks are deducted if you forget it
- Constant multiple rule: integral of k·f(x) dx equals k times integral of f(x) dx
- Integral of sum equals sum of integrals: linearity property simplifies polynomial integration
Trigonometric Integration Formulas
Trigonometric integrals appear in 2-3 questions every Board exam. Memorise the six basic forms perfectly, including signs. A common error is mixing up the signs for cos x and sec²x versus their negatives for csc²x and cot x. Notice the symmetry: integrals of sine and cosine are straightforward, but integrals of tangent and cotangent involve logarithms. The secant squared and cosecant squared integrals are direct antiderivatives of differentiation results you learned in Chapter 5 Continuity and Differentiability. When you encounter products or powers of trig functions, use identities like sin²x + cos²x = 1 or 1 + tan²x = sec²x to rewrite the integrand into standard forms. These formulas are also essential building blocks for integration by parts and substitution problems involving trigonometric expressions later in the chapter and in differential equations.
- Integral of sin x is negative cos x; integral of cos x is positive sin x — remember the sign flip for sine
- Integral of sec²x is tan x; integral of csc²x is negative cot x — these come directly from differentiation
- Integral of sec x tan x is sec x; integral of csc x cot x is negative csc x
- Integrals of tan x and cot x produce logarithmic functions: ln|sec x| and ln|sin x| respectively
Exponential and Logarithmic Integration Formulas
Exponential and logarithmic functions integrate cleanly because of their unique derivative properties. The integral of eˣ is simply eˣ plus the constant, making it one of the easiest functions to integrate. For the general exponential function aˣ, you must divide by the natural logarithm of the base a. This formula is less commonly tested but appears in competitive exams and occasionally in Board long-answer questions. The integral of 1/x is the natural logarithm, which you already saw in the algebraic section, but it warrants repetition because it bridges algebraic and transcendental functions. When you encounter expressions like e^(kx) where k is a constant, remember to apply the chain rule in reverse: the integral becomes (1/k)e^(kx). These formulas combine with substitution when the exponent or argument is a composite function, so practice identifying when to set u equal to the exponent or the argument.
- The function eˣ is its own integral and its own derivative, a unique property in calculus
- For aˣ where a is a positive constant not equal to 1, divide by ln(a) after integrating
- When integrating e raised to a linear function like e^(3x), use substitution or recall the direct formula: integral is (1/3)e^(3x) + C
- Logarithmic integration requires the argument to be positive; always write absolute value in ln|x|
Standard Integrals — Inverse Trigonometric Forms
Inverse trigonometric integrals arise from specific rational and irrational forms. These six formulas must be memorised exactly, including the denominators and the constants a. The first formula gives arcsin when you see a squared constant minus x squared in the square root. The second formula gives arctan when you see a squared constant plus x squared in the denominator without a square root. The third formula gives arcsec when you see x times the square root of x squared minus a squared in the denominator. Many students confuse these forms, so make flash cards or a mnemonic. The key is pattern recognition: identify the algebraic structure (square root of difference, sum of squares, product of x and square root) and match it to the correct inverse trig function. These forms often appear after substitution or partial fraction decomposition, especially in definite integral problems where limits are given. Practicing 10-15 problems of each type builds the muscle memory needed for Board exam speed and accuracy.
- Memorise the three pairs: arcsin for root(a²-x²), arctan for (a²+x²), arcsec for x·root(x²-a²)
- The constant a appears in the formula output as (1/a) multiplying the inverse trig function
- Always check the sign and structure: plus or minus under the square root, x in numerator or not
- These formulas are results of reverse differentiation of inverse trigonometric functions from Chapter 5
Methods of Integration — Substitution and Transformation Rules
Substitution is the workhorse technique for CBSE Class 12 integration problems. The idea is to replace a composite function or a complicated expression with a single variable, say t, to simplify the integrand into a standard form. After integrating with respect to t, substitute back the original expression. The key skill is choosing the right substitution. Look for an inner function whose derivative is present elsewhere in the integrand. For definite integrals, transform the limits when you substitute so you do not need to substitute back. Common substitutions include setting t equal to the denominator, the argument of a trigonometric function, or the expression under a square root. Another powerful transformation is trigonometric substitution, where you replace x with a sin θ, a tan θ, or a sec θ to eliminate square roots involving quadratic expressions. Partial fractions decompose a rational function into simpler fractions when the degree of the numerator is less than the degree of the denominator. If not, perform polynomial long division first, then apply partial fractions to the remainder term.
- Substitution rule: if u = g(x), then ∫ f(g(x))·g'(x) dx = ∫ f(u) du; always check that du = g'(x) dx appears
- For definite integrals, change limits: if x = a gives u = g(a) and x = b gives u = g(b), integrate from g(a) to g(b) in u
- Trigonometric substitution: use x = a sin θ for √(a²-x²), x = a tan θ for √(a²+x²), x = a sec θ for √(x²-a²)
- Partial fractions: factor the denominator, write A/(linear factor) + B/(repeated factor) + (Cx+D)/(quadratic factor), solve for coefficients
Integration by Parts — Formula and Application Strategy
Integration by parts is the product rule of differentiation in reverse. Use it when the integrand is a product of two functions, one easy to differentiate (call it u) and the other easy to integrate (call it dv). The formula is ∫ u dv = u·v - ∫ v du. Choosing u and dv correctly is critical. The ILATE rule is a priority mnemonic: Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential. Pick u in that order of preference and let the rest be dv. For example, in ∫ x·sin x dx, x is Algebraic and sin x is Trigonometric, so set u = x and dv = sin x dx. Then du = dx and v = -cos x, giving u·v - ∫ v du = x·(-cos x) - ∫ (-cos x) dx = -x cos x + sin x + C. Sometimes you need to apply integration by parts twice, especially with products like x²·eˣ or eˣ·sin x. In rare cases, applying integration by parts twice in a loop yields an equation you can solve algebraically for the original integral. This technique appears in 1-2 Board exam questions every year, often combined with substitution or standard forms.
- Formula: ∫ u dv = u·v - ∫ v du; choose u using ILATE priority to minimize complexity in the second integral
- ILATE: Inverse trig > Logarithmic > Algebraic > Trigonometric > Exponential; this order usually makes du simpler than u
- Always compute du by differentiating u and compute v by integrating dv before substituting into the formula
- For repeated products like x²·eˣ, apply integration by parts twice; for eˣ·sin x, apply twice and solve the resulting equation
Properties of Definite Integrals — Computational Shortcuts
Definite integrals have powerful properties that simplify evaluation, especially when the function or limits have symmetry. Property 1: ∫[a to b] f(x) dx = ∫[a to b] f(t) dt; the dummy variable does not matter. Property 2: ∫[a to b] f(x) dx = -∫[b to a] f(x) dx; reversing limits flips the sign. Property 3: ∫[a to b] f(x) dx = ∫[a to c] f(x) dx + ∫[c to b] f(x) dx; split the interval. Property 4: ∫[0 to a] f(x) dx = ∫[0 to a] f(a-x) dx; replace x with a minus x. This is powerful when f(x) plus f(a minus x) simplifies. Property 5: If f(x) is even (f(-x) = f(x)), then ∫[-a to a] f(x) dx = 2∫[0 to a] f(x) dx. If f(x) is odd (f(-x) = -f(x)), then ∫[-a to a] f(x) dx = 0. Property 6: ∫[0 to 2a] f(x) dx = ∫[0 to a] f(x) dx + ∫[0 to a] f(2a-x) dx. These properties often convert a difficult integral into a trivial one, saving 5-10 minutes in the Board exam. Board setters love setting problems where recognizing symmetry or applying the f(a-x) substitution transforms the integrand into a constant or a simple algebraic form. Practice these properties with past Board papers to build intuition for when to apply which property.
- Property 4 (King Property): ∫[0 to a] f(x) dx = ∫[0 to a] f(a-x) dx; add the two forms to eliminate complex terms
- Even-Odd Property: even functions double the integral from 0 to a; odd functions over symmetric intervals integrate to zero
- Property for periodic functions: ∫[a to a+T] f(x) dx = ∫[0 to T] f(x) dx if f has period T
- Always check the interval and function symmetry before computing by substitution or by parts; properties can reduce calculation by 90 percent
Fundamental Theorem of Calculus — Connecting Derivatives and Integrals
The Fundamental Theorem of Calculus (FTC) is the bridge between differentiation and integration. It has two parts. Part 1: If F(x) = ∫[a to x] f(t) dt, then F'(x) = f(x). This says that the derivative of an integral with variable upper limit is the integrand evaluated at that limit. Part 2: If F is an antiderivative of f (meaning F'(x) = f(x)), then ∫[a to b] f(x) dx = F(b) - F(a). This is the evaluation formula you use every time you compute a definite integral. First find the indefinite integral (antiderivative), then substitute the upper limit, subtract the result of substituting the lower limit. The notation is F(x) evaluated from a to b, written as [F(x)]ₐᵇ or F(x)|ₐᵇ. The FTC justifies why we can ignore the constant of integration in definite integrals: F(b) + C minus (F(a) + C) cancels the C. Memorise the statement and practice applying Part 2 in every definite integral problem. Also remember that if f is continuous on [a, b], the integral from a to b exists and equals F(b) - F(a) for any antiderivative F.
- FTC Part 1: Differentiating an integral with respect to its upper limit returns the integrand at that limit
- FTC Part 2: ∫[a to b] f(x) dx = F(b) - F(a) where F is any antiderivative of f; this is the evaluation step
- The constant C cancels in definite integrals, so you can omit it when computing F(b) - F(a)
- If the upper limit is a function of x, use the chain rule: d/dx[∫[a to g(x)] f(t) dt] = f(g(x))·g'(x)
Key Definitions and Terminology
Mastering terminology is essential for writing precise Board exam answers and understanding question wording. An indefinite integral or antiderivative is a family of functions F(x) + C whose derivative is the given function f(x). The arbitrary constant C accounts for the fact that derivatives of constants are zero. A definite integral is the limit of Riemann sums, representing the net signed area between the curve y = f(x) and the x-axis from x = a to x = b. The lower limit a and upper limit b are the bounds of integration. The integrand is the function f(x) being integrated. The variable of integration is x (or whichever variable appears in dx). An improper integral has one or both limits infinite, or the integrand has a discontinuity in the interval; these are introduced in higher courses but may appear as extension problems. A primitive or antiderivative is another name for the indefinite integral. The process of finding an integral is called integration or quadrature. Understanding these terms helps you parse problem statements and write answers that earn full method marks even if you make a small computational error.
- Indefinite integral: ∫ f(x) dx = F(x) + C where F'(x) = f(x); result is a function plus constant
- Definite integral: ∫[a to b] f(x) dx; result is a real number representing area or accumulated quantity
- Integrand: the function f(x) inside the integral sign
- Limits of integration: a (lower limit) and b (upper limit) in a definite integral
- Arbitrary constant of integration: C in the indefinite integral, representing the family of antiderivatives
- Primitive: synonym for antiderivative; F is a primitive of f if F' = f
Memory Tricks, Mnemonics and Common Mistakes to Avoid
ILATE mnemonic for integration by parts: Inverse trig, Logarithmic, Algebraic, Trigonometric, Exponential — choose u in that priority order. King Property mnemonic: When you see limits 0 to a, try replacing x with a minus x and add the two forms; if lucky, terms cancel and you get a constant. Sign mistakes: integral of sin x is minus cos x (negative), integral of cos x is plus sin x (positive); integral of csc²x is minus cot x, integral of sec²x is plus tan x. Forgetting the constant: In indefinite integrals, always write plus C at the end; Board examiners deduct half a mark for this omission. Limits transformation in substitution: If you substitute u = g(x) in a definite integral, transform both limits; new lower limit is g(a), new upper limit is g(b); do not substitute back. Absolute value in logarithms: Always write ln|u| not ln(u) unless you know u is positive; this prevents domain errors. Partial fractions: Factor the denominator completely first; if the numerator degree is greater than or equal to the denominator degree, perform polynomial division before decomposing. Arctan and arcsin domain: Make sure the argument is within the domain of the inverse trig function; for arcsin, argument must be between minus one and one.
- ILATE: I-Inverse trig, L-Logarithmic, A-Algebraic, T-Trigonometric, E-Exponential; choose u left to right
- King Property: ∫[0 to a] f(x) dx = ∫[0 to a] f(a-x) dx; add both sides to eliminate difficult terms
- Sign Check: Sine integrates to negative cosine, cosine integrates to positive sine; csc² to negative cot, sec² to positive tan
- Constant C: Never omit in indefinite integrals; definite integrals do not need C because it cancels
- Limits in substitution: Transform limits or substitute back; mixing both causes errors
- Absolute value: ln|x| not ln(x) unless context guarantees x positive; same for ln|sec x| in tan x integral
Three Solved Mini-Examples Applying the Formulas
Example 1 (Standard Form): Evaluate ∫ (5x⁴ + 3/x - 2eˣ) dx. Split term by term: ∫ 5x⁴ dx + ∫ (3/x) dx - ∫ 2eˣ dx. Apply power rule, logarithm and exponential formulas: 5·(x⁵/5) + 3·ln|x| - 2·eˣ + C = x⁵ + 3ln|x| - 2eˣ + C. Example 2 (Substitution): Evaluate ∫ sin³x·cos x dx. Set u = sin x, then du = cos x dx. The integral becomes ∫ u³ du = (u⁴)/4 + C = (sin⁴x)/4 + C. Example 3 (Definite Integral with Property): Evaluate ∫[-π to π] x·sin x dx. Check: f(x) = x·sin x, f(-x) = (-x)·sin(-x) = (-x)·(-sin x) = x·sin x, so f is even. By property: ∫[-π to π] = 2∫[0 to π] x·sin x dx. Now integrate by parts: u = x, dv = sin x dx, du = dx, v = -cos x. ∫ x·sin x dx = x·(-cos x) - ∫ (-cos x) dx = -x·cos x + sin x. Evaluate from 0 to π: [-π·cos π + sin π] - [0·cos 0 + sin 0] = [-π·(-1) + 0] - [0 + 0] = π. So ∫[-π to π] = 2π. These examples cover standard forms, substitution and definite integrals with symmetry, three pillars of Board exam integration problems. Practice these methods until you can execute each in under three minutes.
- Always identify the integration technique first: standard form, substitution, by parts, or property
- For substitution, write out du explicitly and check that it matches part of the integrand
- For integration by parts, apply ILATE, compute u, du, v, dv carefully before substituting into the formula
- For definite integrals, check for symmetry (even/odd function or property 4) before evaluating the antiderivative
One-Glance Last-Minute Revision Box for Board Exams
Power rule: ∫ xⁿ dx = xⁿ⁺¹/(n+1) + C, n≠-1. Reciprocal: ∫ (1/x) dx = ln|x| + C. Exponential: ∫ eˣ dx = eˣ + C. Sine and Cosine: ∫ sin x dx = -cos x + C, ∫ cos x dx = sin x + C. Sec²: ∫ sec²x dx = tan x + C. Csc²: ∫ csc²x dx = -cot x + C. Arcsin: ∫ dx/√(a²-x²) = sin⁻¹(x/a) + C. Arctan: ∫ dx/(a²+x²) = (1/a)tan⁻¹(x/a) + C. Integration by parts: ∫ u dv = uv - ∫ v du. ILATE for choosing u: Inverse, Logarithmic, Algebraic, Trigonometric, Exponential. FTC Part 2: ∫[a to b] f(x) dx = F(b) - F(a). King Property: ∫[0 to a] f(x) dx = ∫[0 to a] f(a-x) dx. Even function: ∫[-a to a] f(x) dx = 2∫[0 to a] f(x) dx. Odd function: ∫[-a to a] f(x) dx = 0. Substitution: u=g(x), du=g'(x) dx; transform limits in definite integrals. Partial fractions: factor denominator, split into A/(x-r) terms, solve for coefficients. Always add constant C in indefinite integrals. Check signs for trig integrals. Write absolute value in logarithms. These formulas and tips cover 95 percent of Board exam integration questions; revise this box the night before your exam and again in the reading time.
- Standard forms: memorise all 15-20 basic formulas verbatim; no derivation needed during exam
- Methods: substitution for composite functions, by parts for products, properties for symmetric integrals, partial fractions for rational functions
- Definite integrals: apply FTC Part 2, transform limits in substitution, use properties to simplify before computing
- Common errors: missing constant C, wrong sign in trig integrals, forgetting absolute value in ln, incorrect limits transformation
Frequently asked questions
What is the difference between indefinite and definite integrals in CBSE Class 12 Mathematics Chapter 7?+
An indefinite integral produces a family of functions F(x) + C and represents the general antiderivative of f(x). A definite integral ∫[a to b] f(x) dx yields a specific real number representing the net signed area under the curve from x = a to x = b. Indefinite integrals always include the constant of integration C; definite integrals do not because C cancels when you compute F(b) - F(a).
How many marks does Chapter 7 Integrals carry in the CBSE Class 12 Mathematics Board exam?+
Integrals typically contributes 10-12 marks in the CBSE Class 12 Mathematics Board exam. Questions range from 2-mark standard integration formulas to 6-mark problems involving integration by parts, substitution and definite integral properties. The chapter also appears in application problems in coordinate geometry and differential equations, indirectly adding another 4-5 marks.
What is the ILATE rule and when do I use it for integration by parts?+
ILATE is a mnemonic for choosing which function to set as u in the integration by parts formula ∫ u dv = uv - ∫ v du. It stands for Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential. Choose u as the function appearing first in this list, and let dv be the rest. For example, in ∫ x·ln x dx, ln x is Logarithmic (L) and x is Algebraic (A), so set u = ln x and dv = x dx.
Why do we write ln|x| instead of ln(x) when integrating 1/x?+
The absolute value ensures the formula is valid for negative x as well. The natural logarithm ln(x) is defined only for positive x. Since the derivative of ln|x| is 1/x for all x ≠ 0 (both positive and negative), we write ∫ (1/x) dx = ln|x| + C. Omitting the absolute value loses marks in Board exams if the domain includes negative values.
How do I know when to use substitution versus integration by parts?+
Use substitution when the integrand is a composite function f(g(x)) and you can spot g'(x) elsewhere in the integrand. Use integration by parts when the integrand is a product of two functions, one easy to differentiate and the other easy to integrate, and substitution does not simplify it. If the integrand is a product involving x, ln x, or an inverse trig function, try by parts first. If you see a chain like (3x+1)⁵ or e^(x²)·2x, substitution is faster.
What is the King Property of definite integrals and how does it help?+
The King Property states ∫[0 to a] f(x) dx = ∫[0 to a] f(a-x) dx. You replace x with a-x in the integrand, getting a second expression for the same integral. Adding the two equations often causes difficult terms to cancel, leaving a simpler constant integrand. For example, ∫[0 to π/2] (sin x)/(sin x + cos x) dx becomes (1/2)·(π/2) = π/4 after applying the property. This technique saves several minutes in Board exams.
Do I need to memorise all the standard integration formulas for the Board exam?+
Yes, absolutely. CBSE Board exams do not provide a formula sheet, so you must memorise all standard formulas: power rule, trigonometric integrals, exponential and logarithmic integrals, and the six inverse trigonometric forms. Examiners expect instant recall. Practice writing the full list daily for one week before the exam to build automatic recall under exam pressure.
How do I handle limits when using substitution in a definite integral?+
After substituting u = g(x), transform the limits: the new lower limit is g(a) and the new upper limit is g(b). Then integrate in terms of u from g(a) to g(b) and evaluate. Do not substitute x back if you have already transformed the limits. Alternatively, you can find the indefinite integral in u, substitute back to x, then apply limits in x. Choose one method per problem to avoid confusion and errors.
What are the most common mistakes students make in Chapter 7 Integrals?+
Forgetting to add the constant of integration C in indefinite integrals is the top mistake. Others include sign errors in trigonometric integrals (especially negative cosine for sine), omitting absolute value in ln|x|, incorrect application of integration by parts (wrong choice of u and dv), and failing to transform limits correctly in substitution for definite integrals. Also, students often skip checking for even or odd symmetry, missing shortcuts that save time.
Can CBSETUTOR.ai help me practice integration problems with step-by-step solutions?+
Yes, CBSETUTOR.ai offers a 24×7 AI tutor for CBSE Class 12 Mathematics at a flat ₹999 per month, covering all subjects and classes 6-12. You can upload a photo of any integration problem and receive detailed step-by-step solutions, explanations of which formula or method to use, and hints for similar questions. The platform is ideal for clearing doubts at night or during self-study. A 3-day free trial is available so you can test the service before committing.
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