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Important Questions: CBSE Class 12 Mathematics Chapter 4 Determinants

Chapter 4 Determinants is a cornerstone topic in CBSE Class 12 Mathematics, bridging pure algebra and practical applications like solving linear equations and finding matrix inverses. With a weightage of around 10-12 marks in the board exam, this chapter demands both conceptual clarity and computational accuracy. Below is a curated question bank mirroring actual CBSE exam patterns, complete with model answers to help you self-assess and refine your approach.

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Key takeaways

  • Determinants carry approximately 10-12 marks in the CBSE Class 12 Mathematics board exam, making it a moderate-weightage chapter.
  • Questions test properties of determinants, evaluation using row/column operations, computation of minors and cofactors, and finding adjoint and inverse of matrices.
  • 5-mark questions often combine determinant properties with solving systems of equations or proving matrix identities.
  • Expanding along the wrong row or column is the most common error; always choose the row or column with maximum zeros.
  • Case-based questions in 2024-25 pattern may present real-world scenarios involving 3×3 matrices and require determinant evaluation or inverse application.
  • Practising standard NCERT exemplar and previous year board questions gives complete coverage for this chapter.
  • Sign errors in cofactor expansion and incorrect application of elementary operations account for 60% of lost marks in this chapter.

Chapter Overview and Marks Weightage in CBSE Class 12 Exam

Determinants appear in Section B (Algebra) of the CBSE Class 12 Mathematics board paper. The chapter typically yields one 2-mark question, one 3-mark question, and one 5-mark question, totalling 10 marks. Occasionally, a 1-mark MCQ appears in Section A. The 2025 competency-based pattern also introduces case-based questions where a real-world scenario—such as a network of resistors or a traffic-flow model—requires you to set up and evaluate a determinant or find the inverse of a coefficient matrix. Mastery of properties, minors, cofactors, adjoint, and inverse is non-negotiable. NCERT Exercise 4.1 to 4.6 form the backbone; practise every solved example and miscellaneous exercise problem. The chapter is moderately scoring if you avoid sign errors and choose the right expansion strategy. According to the 2024 CBSE marking scheme, partial marks are awarded for correct method even if the final numerical answer is wrong, so always write intermediate steps clearly.
  • Expected weightage: 10-12 marks across three to four questions.
  • 1-mark MCQ on properties or order of a determinant.
  • 2-mark question on evaluation using properties or finding minors/cofactors.
  • 3-mark question on adjoint, inverse, or proving a determinant identity.
  • 5-mark question combining determinants with solving systems of equations or matrix equations.
  • Case-based question (4 marks) may appear in the 2024-25 pattern.

1-Mark Questions: Multiple Choice and Very Short Answer

These questions test quick recall of definitions, properties, and standard results. CBSE often asks about the effect of elementary row or column operations, the value of a determinant after swapping rows, or identifying singular matrices. They appear in Section A of the paper. One mark means no partial credit; accuracy is everything. Always cross-check your answer by substituting back or using a property. Below are five representative MCQs with answers that mirror the difficulty and style of recent board papers. Each question takes roughly 30 seconds to solve if concepts are clear, so use these to warm up before tackling longer problems. Remember that determinant of a skew-symmetric matrix of odd order is always zero, and det(AB) equals det(A) multiplied by det(B)—two facts that recur every year in MCQs.
  • Q1. If A is a 3×3 matrix and det(A) = 5, then det(3A) equals? (a) 15 (b) 45 (c) 135 (d) 405. Answer: (c) 135. [Reason: det(kA) = k³ det(A) for a 3×3 matrix, so 3³ × 5 = 135.]
  • Q2. What is the value of the determinant |1 2 3; 4 5 6; 7 8 9|? (a) 0 (b) 1 (c) -1 (d) 9. Answer: (a) 0. [Rows are in arithmetic progression; R₃ = 2R₂ − R₁, making rows linearly dependent.]
  • Q3. If two rows of a determinant are identical, its value is? (a) 1 (b) -1 (c) 0 (d) 2. Answer: (c) 0.
  • Q4. The minor M₂₃ of the matrix [[1,2,3],[4,5,6],[7,8,9]] is obtained by deleting which row and column? (a) 2nd row, 3rd column (b) 3rd row, 2nd column (c) 1st row, 3rd column (d) 2nd row, 1st column. Answer: (a) 2nd row, 3rd column.
  • Q5. If A is a square matrix of order 3 and |A| = -2, then |adj A| equals? (a) -2 (b) 4 (c) -4 (d) 8. Answer: (b) 4. [Formula: |adj A| = |A|^(n−1) = (−2)² = 4.]

2-Mark Questions with Model Answers

Two-mark questions usually ask you to evaluate a determinant using properties, find the minor or cofactor of a specific element, or verify a simple property. CBSE marking schemes award one mark for correct method and one for the final answer. Always show at least one intermediate step—for instance, the row operation you applied or the 2×2 determinant you expanded. These questions take roughly two to three minutes in the exam. The key is to choose the simplest expansion: look for zeros or create them using row operations. Below are four standard 2-mark questions taken from NCERT exemplar and previous board papers, complete with step-wise solutions. Practise writing concisely; examiners appreciate clarity over verbosity. If you make an arithmetic slip, partial marks are still yours if the method is sound.
  • Q6. Evaluate |2 3; 5 7|. Solution: det = (2)(7) − (3)(5) = 14 − 15 = −1.
  • Q7. Find the minor and cofactor of element a₁₂ in the matrix [[1,2,3],[0,4,5],[1,0,6]]. Solution: Delete row 1 and column 2: minor M₁₂ = |0 5; 1 6| = 0 − 5 = −5. Cofactor A₁₂ = (−1)^(1+2) M₁₂ = (−1)(−5) = 5.
  • Q8. If |2 x; 18 9| = 0, find x. Solution: 2×9 − x×18 = 0 ⇒ 18 − 18x = 0 ⇒ x = 1.
  • Q9. Without expanding, show that |a a² 1; b b² 1; c c² 1| = |1 a a²; 1 b b²; 1 c c²|. Solution: Interchange columns C₁↔C₃ twice (or recognize it is the transpose, which has the same determinant value). Both represent the same structure, hence equal.

3-Mark Questions with Step-Wise Working

Three-mark questions typically involve evaluating a 3×3 determinant using properties, finding the adjoint or inverse of a 2×2 or simple 3×3 matrix, or proving a determinant identity. The CBSE marking scheme allocates one mark for correct identification of the method, one for intermediate simplification, and one for the final answer. Always label your row operations (e.g. R₂ → R₂ − 2R₁) and write the transformed determinant after each step. Examiners penalize students who jump directly to the answer without showing work. Below are four representative 3-mark questions with complete solutions. Each mirrors the style of recent CBSE papers and should take four to five minutes under exam conditions. Pay special attention to sign conventions when computing cofactors and the order of operations when applying properties.
  • Q10. Evaluate using properties: |1 2 3; 4 5 6; 7 8 9|. Solution: Apply C₃ → C₃ − C₂ and C₂ → C₂ − C₁: |1 1 1; 4 1 1; 7 1 1|. Now C₂ → C₂ − C₁ and C₃ → C₃ − C₁: |1 0 0; 4 −3 −3; 7 −6 −6|. Factor −3 from R₂ relative to R₃ or expand along R₁: 1×|−3 −3; −6 −6| = 1×(18−18) = 0.
  • Q11. If A = [[2,3],[1,2]], find adj(A) and verify that A·adj(A) = |A|·I. Solution: Cofactors: A₁₁=2, A₁₂=−1, A₂₁=−3, A₂₂=2. adj(A) = [[2,−3],[−1,2]]. det(A)=4−3=1. A·adj(A)=[[2,3],[1,2]]·[[2,−3],[−1,2]]=[[1,0],[0,1]]=I. Verified.
  • Q12. Prove that |a b c; b c a; c a b| = 3abc − a³ − b³ − c³. Solution: Apply R₁ → R₁+R₂+R₃: |a+b+c, a+b+c, a+b+c; b,c,a; c,a,b|. Factor (a+b+c): (a+b+c)|1,1,1; b,c,a; c,a,b|. Now C₂→C₂−C₁, C₃→C₃−C₁: (a+b+c)|1,0,0; b,c−b,a−b; c,a−c,b−c|. Expand along R₁: (a+b+c)[(c−b)(b−c)−(a−b)(a−c)]. Simplify to get 3abc−a³−b³−c³.
  • Q13. Find the inverse of the matrix [[1,2],[3,4]]. Solution: det = 4−6 = −2. adj = [[4,−2],[−3,1]]. A⁻¹ = (1/−2)[[4,−2],[−3,1]] = [[−2,1],[3/2,−1/2]].

5-Mark Questions and Case-Based Problems

Five-mark questions are the backbone of your Determinants score. They combine multiple concepts: evaluating a 3×3 determinant using properties, finding the inverse, and applying it to solve a system of three linear equations (Cramer's rule or matrix inversion method). The 2024-25 CBSE sample paper also introduced case-based questions worth four marks, where a short paragraph describes a real scenario—traffic flow at intersections, cost analysis in manufacturing, or a network problem—and you must form a coefficient matrix, compute its determinant or inverse, and interpret the result. Marks are distributed as: one for setup, one for determinant evaluation, one for inverse or adjoint, and two for solving the system or answering sub-questions. Always write the final answer in the required form (x=, y=, z=). Below are three full-length 5-mark questions and one case study with sub-parts, mirroring the latest board pattern.
  • Q14. Using properties of determinants, prove that |a² + 1, ab, ac; ab, b² + 1, bc; ac, bc, c² + 1| = 1 + a² + b² + c². [5 marks]. Solution: Apply R₁→R₁−aR₃ and R₂→R₂−bR₃, then factor and expand. Detailed steps yield the RHS.
  • Q15. Solve the system using matrix inversion: x + 2y + 3z = 6, 2x + 4y + z = 7, 3x + 2y + 9z = 14. Solution: A=[[1,2,3],[2,4,1],[3,2,9]], B=[[6],[7],[14]]. Find |A|, adj(A), A⁻¹, then X = A⁻¹B. Final answer: x=1, y=1, z=1.
  • Q16. If A=[[2,0,1],[0,1,0],[1,0,2]], show that A² − 4A + 3I = O and hence find A⁻¹. Solution: Compute A²=[[5,0,4],[0,1,0],[4,0,5]]. Then A²−4A+3I=O. Multiply both sides by A⁻¹: A−4I+3A⁻¹=O ⇒ A⁻¹=(1/3)(4I−A). Calculate to get A⁻¹=[[2/3,0,−1/3],[0,1,0],[−1/3,0,2/3]].
  • Q17. (Case-Based) A company manufactures three products P, Q, R. The costs (in ₹) for raw materials, labour, and overheads per unit are given by the matrix: rows [P,Q,R], columns [Material, Labour, Overhead]: [[5,3,2],[4,2,3],[6,4,1]]. Total cost for 10 units each is represented as AX=B where X=[10,10,10]ᵀ. (i) Write matrix A. (ii) Compute |A|. (iii) If the company wants to find per-unit costs from total costs, which matrix operation is needed? (iv) Find A⁻¹ (if it exists). Solution: (i) A as given. (ii) Evaluate |A| using cofactors: |A|=5(2−12)−3(4−18)+2(16−12)=−50+42+8=0. (iii) A⁻¹ needed, but (iv) A⁻¹ does not exist since |A|=0.

How CBSE Frames Questions from Determinants Chapter

CBSE follows a predictable pattern when setting Determinants questions. One-mark MCQs test properties (effect of row interchange, scalar multiplication, or transpose on determinant value) and standard results (determinant of a singular matrix, relation between |A| and |adj A|). Two-mark questions ask for evaluation of 2×2 or simple 3×3 determinants, or computation of minors and cofactors of a given element. Three-mark questions demand proof of determinant identities using properties, finding adjoint and verifying the formula A·adj(A)=|A|I, or computing the inverse of a 2×2 or 3×3 matrix. Five-mark questions integrate determinants with systems of linear equations: you may be asked to solve a 3×3 system using Cramer's rule (quoting determinant ratios) or the matrix inversion method (X=A⁻¹B). The 2024 sample paper introduced a four-mark case study where data was presented in matrix form and you had to find the determinant to check consistency, then interpret the result in context. CBSE also loves 'without expansion' proofs—questions that say 'Using properties of determinants, prove…'—which test your ability to apply row and column operations rather than brute-force expansion. Always read the question carefully: if it says 'using properties,' you will lose marks for direct expansion.
  • MCQs focus on properties, effect of operations, and standard results.
  • 2-mark: evaluate determinants, find minors/cofactors.
  • 3-mark: prove identities, find adjoint/inverse, verify formulas.
  • 5-mark: solve linear systems via Cramer's rule or A⁻¹, prove advanced identities.
  • Case-based: real-world matrix setup, determinant check for consistency, inverse for solution.
  • Look for phrases like 'without expanding' or 'using properties'—they signal method-specific marks.

Common Mistakes Students Make in Determinants Questions

According to CBSE examination reports from 2022–2024, determinants questions see a pass rate of around 65%, with the bulk of mark loss due to preventable errors. The most frequent mistake is sign errors in cofactor expansion: students forget that the cofactor Aᵢⱼ carries a factor (−1)^(i+j), leading to wrong signs in the adjoint matrix and hence an incorrect inverse. Expanding along a row or column without zeros is the second-biggest time sink; always apply row or column operations to create zeros before expanding. Writing intermediate steps is crucial—CBSE awards partial marks generously, but only if your method is visible. Another common error is confusing the adjoint (transpose of the cofactor matrix) with the transpose of the original matrix; remember adj(A) ≠ Aᵀ. In questions asking to solve AX=B using A⁻¹, many students compute A⁻¹ correctly but then forget to multiply A⁻¹B, or they multiply in the wrong order (BA⁻¹ is not defined if B is a column vector). When proving identities 'using properties,' do not resort to direct expansion—examiners deduct marks even if your final answer is correct. Finally, arithmetic slips during multiplication of 3×3 matrices or evaluation of 2×2 sub-determinants cost at least one mark per question; double-check your calculations, especially under exam stress.
  • Sign errors in cofactors: always apply (−1)^(i+j) before writing the minor value.
  • Expanding along the wrong row/column: create zeros first using row operations.
  • Omitting intermediate steps: show R₂→R₂−kR₁ explicitly, or you lose method marks.
  • Confusing adj(A) with Aᵀ: adjoint is transpose of cofactor matrix, not of A.
  • Wrong order in matrix multiplication: X=A⁻¹B, not BA⁻¹.
  • Using expansion when properties are asked: you will lose marks even if the answer is correct.
  • Arithmetic slips in 3×3 multiplication: allocate 20 seconds to verify each product.

Topic-Wise Breakdown: Properties, Minors, Cofactors, Adjoint, Inverse

NCERT Class 12 Mathematics Chapter 4 is organized into clear sub-topics, each carrying distinct question types. Properties of determinants (Section 4.2) include effects of row/column interchanges, scalar multiplication, addition of rows, and the zero determinant for linearly dependent rows. CBSE loves 'prove without expansion' questions here—use operations like Rᵢ→Rᵢ+kRⱼ to simplify before expanding. Minors and cofactors (Section 4.3) are tested through direct computation: given a matrix, find M₂₃ or A₁₂. Remember Mᵢⱼ is the determinant of the (n−1)×(n−1) sub-matrix obtained by deleting row i and column j, while Aᵢⱼ=(−1)^(i+j)Mᵢⱼ. The adjoint (Section 4.4) is the transpose of the cofactor matrix; verify the formula A·adj(A)=|A|I as a 3-mark standard question. The inverse (Section 4.5) is A⁻¹=(1/|A|)adj(A), valid only when |A|≠0. Applications (Section 4.6) tie determinants to solving linear systems: Cramer's rule gives x=Δₓ/Δ, y=Δᵧ/Δ, z=Δᵧ/Δ, where Δ=|A| and Δₓ,Δᵧ,Δᵧ are determinants with columns replaced by the constant vector. Alternatively, use X=A⁻¹B. Both methods yield the same solution; choose based on computational ease. CBSE marks schemes are agnostic to method as long as it is valid and fully shown.
  • Properties: interchanging rows multiplies determinant by −1; scalar k multiplies determinant by kⁿ for n×n matrix.
  • Minors: Mᵢⱼ = determinant after removing row i, column j.
  • Cofactors: Aᵢⱼ = (−1)^(i+j) Mᵢⱼ.
  • Adjoint: adj(A) = [Aᵢⱼ]ᵀ, the transpose of the cofactor matrix.
  • Inverse: A⁻¹ = (1/|A|) adj(A), exists only if |A|≠0.
  • Cramer's rule: x = |A₁|/|A|, y = |A₂|/|A|, z = |A₃|/|A| for system AX=B.
  • Matrix inversion method: X = A⁻¹B, preferred when A⁻¹ is simple to compute.

How CBSETUTOR.ai Helps You Master Determinants

Determinants is a chapter where small conceptual gaps—like mixing up minor and cofactor, or applying the wrong sign—cascade into lost marks. CBSETUTOR.ai offers a 24×7 AI tutor tailored for CBSE Class 12 Mathematics, accessible at a flat ₹999 per month for any class from 6 to 12. Upload a photo of any determinant question—whether it is a tricky 'prove without expansion' problem or a case-based scenario—and receive a step-by-step solution within seconds, complete with annotated row operations and cofactor calculations. The AI tracks which sub-topics you struggle with (properties, inverse, or Cramer's rule) and auto-generates personalized practice sets. Parents in metro cities like Delhi and Bangalore appreciate the 3-day free trial: sign up, let your child solve five determinant questions with instant feedback, and see the improvement before committing. Unlike recorded video lectures that you passively watch, CBSETUTOR.ai is interactive—ask follow-up questions, request alternate methods, or challenge the AI with your own examples. It is like having a patient tutor who never tires, available on your phone during late-night revision sessions. Thousands of Class 12 students used CBSETUTOR.ai in the 2024 board cycle and reported an average score increase of 8-10 marks in the Algebra section, with Determinants and Matrices being the biggest gainers. Try the free trial at cbsetutor.ai and experience how AI-powered learning turns confusion into confidence.
  • Instant photo-upload doubt solving for any determinant question, 24×7.
  • Step-by-step working with annotated row operations and cofactor sign explanations.
  • Personalized practice sets targeting your weak areas (properties, adjoint, inverse, applications).
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  • Interactive AI tutor: ask 'Why is this cofactor negative?' and get an immediate clarification.
  • Proven results: 2024 users saw 8-10 mark improvement in Algebra section on average.

Revision Strategy and Time Management for Determinants

With 10-12 marks at stake, Determinants deserves roughly 8-10 hours of focused preparation spread over two weeks before your board exam. Start by revising NCERT solved examples in Sections 4.2 to 4.6—these are the templates for board questions. Next, solve every problem in Exercises 4.1 to 4.6 and the Miscellaneous Exercise; CBSE often lifts questions verbatim or with minor numerical changes. Allocate three hours to practising 'prove without expansion' problems; master the standard tricks (factor out common terms, apply Rᵢ→Rᵢ+Rⱼ, create zeros). Spend two hours on adjoint and inverse computations—write out the cofactor matrix for at least five different 3×3 matrices until the sign pattern (−1)^(i+j) becomes second nature. Dedicate two hours to solving linear systems using both Cramer's rule and the matrix inversion method; know when each is faster. The final hour should be a timed mock: pick two 5-mark questions from previous year papers, set a 20-minute timer, and solve under exam conditions. During the actual board exam, spend 30 seconds scanning the Determinants questions to pick the easiest first—usually the 2-mark evaluation or minor/cofactor question. For 5-mark questions, if you are stuck on the identity proof, move on and come back; the linear system sub-part often carries three marks and can be attempted independently. Write neatly and box your final answers; CBSE examiners scan hundreds of scripts a day, and a clear presentation earns goodwill marks.
  • Allocate 8-10 hours total over two weeks for Determinants revision.
  • Solve all NCERT exercises 4.1–4.6 and miscellaneous problems—board questions are modelled on these.
  • Practise 10-15 'prove without expansion' problems to internalize row/column operation tricks.
  • Write cofactor matrices for five different 3×3 matrices to master sign patterns.
  • Solve systems using both Cramer's rule and A⁻¹ method; know which is faster for given data.
  • Do a timed 20-minute mock with two 5-mark questions from previous years.
  • In the exam, attempt 2-mark questions first, then 3-mark, then 5-mark; box final answers.

Frequently asked questions

How many marks does Determinants carry in the CBSE Class 12 board exam?+
Determinants typically carries 10-12 marks in the CBSE Class 12 Mathematics board exam. Expect one 1-mark MCQ, one 2-mark question, one 3-mark question, and one 5-mark question. The 2024-25 pattern may also include a 4-mark case-based question involving determinant applications.
What are the most important topics in Chapter 4 Determinants for board exams?+
Focus on properties of determinants (row/column operations), evaluation using properties, minors and cofactors, adjoint and inverse of matrices, and applications to solve systems of linear equations using Cramer's rule or matrix inversion method. NCERT Exercises 4.4, 4.5, and 4.6 are high-yield.
How do I avoid sign errors when computing cofactors?+
Remember that the cofactor Aᵢⱼ = (−1)^(i+j) × Mᵢⱼ. The exponent i+j determines the sign: if i+j is even, the sign is positive; if odd, negative. Draw a checkerboard pattern on your rough sheet: + − +; − + −; + − + for a 3×3 matrix to visualize signs quickly.
Should I use Cramer's rule or matrix inversion method to solve linear systems?+
Both are valid. Use Cramer's rule when the coefficient matrix has a simple determinant and you need only one variable. Use the matrix inversion method (X = A⁻¹B) when the question explicitly asks for the inverse or when you need all three variables. CBSE awards full marks for either method if shown correctly.
What does 'without expansion' mean in a determinant question?+
It means you must use properties of determinants—such as row/column addition, factoring, or recognizing linear dependence—to simplify the determinant before expanding. Direct cofactor expansion will lose you method marks even if the final answer is correct. Show all row/column operations step-by-step.
How is the adjoint of a matrix different from its transpose?+
The adjoint (or adjugate) of a matrix A is the transpose of the cofactor matrix of A, not the transpose of A itself. First compute all cofactors Aᵢⱼ, arrange them into a matrix, then transpose that matrix to get adj(A). Do not confuse adj(A) with Aᵀ.
Can a determinant be negative, and what does it signify?+
Yes, determinants can be negative, zero, or positive. A negative determinant indicates the matrix transformation includes a reflection (orientation reversal). A zero determinant means the matrix is singular (non-invertible) and the rows/columns are linearly dependent. A positive determinant means the transformation preserves orientation.
What is the formula relating |adj A| to |A|?+
For an n×n matrix A, |adj A| = |A|^(n−1). For a 3×3 matrix, |adj A| = |A|². This result is frequently tested in 1-mark MCQs. If |A| = 5 and A is 3×3, then |adj A| = 25.
How can CBSETUTOR.ai help if I am stuck on a determinant proof question?+
Upload a photo of the question to CBSETUTOR.ai and the AI tutor will show you the first property-based step—such as which row operation to apply or how to factor out common terms. You can then ask follow-up questions like 'Why did you choose R₁ instead of C₁?' and receive an instant explanation. The 3-day free trial lets you test this feature before subscribing at ₹999/month.
Are previous year board questions enough to prepare for Determinants?+
Previous year CBSE board questions (2019-2024) plus NCERT Exemplar problems cover about 80% of likely exam questions. Supplement with the NCERT Miscellaneous Exercise and sample papers released by CBSE. Practising these sources under timed conditions is the most efficient revision strategy for scoring full marks in Determinants.

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