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Class 12 Mathematics Chapter 1 Relations and Functions — Formulas & Key Points
Relations and Functions is the opening chapter of NCERT Class 12 Mathematics and forms the foundation for calculus, continuity and advanced topics in the CBSE syllabus. This formula sheet consolidates every definition, property and theorem from Chapter 1 into tables and bullet points. Whether revising types of relations, checking if a function is one-one or onto, or computing inverse functions, this page serves as a one-stop quick-reference guide.
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Key takeaways
- ✓A relation R on set A is an equivalence relation if and only if it is reflexive, symmetric and transitive simultaneously.
- ✓A function f: A → B is one-one (injective) if distinct elements in A map to distinct elements in B; it is onto (surjective) if every element in B has a pre-image in A.
- ✓Composition of functions (gof)(x) = g(f(x)) is defined only when range of f is a subset of domain of g; composition is associative but not commutative.
- ✓A function f is invertible if and only if it is bijective (both one-one and onto); the inverse function f⁻¹ satisfies (fof⁻¹)(x) = x and (f⁻¹of)(x) = x.
- ✓Binary operations on sets must satisfy closure; associative and commutative properties depend on the specific operation defined.
- ✓Common mistakes include confusing domain-codomain with range, forgetting to verify all three properties for equivalence, and assuming gof equals fog.
Core Definitions — Relations
A relation R from set A to set B is a subset of the Cartesian product A × B. When A = B, we say R is a relation on A. The following table captures the fundamental types and properties of relations that appear repeatedly in CBSE Class 12 board papers. Understanding these definitions is essential because questions often ask you to verify whether a given relation is reflexive, symmetric, transitive or equivalence. Every property has a precise mathematical condition; memorise the symbolic form alongside the English statement.
- Domain of R = {a ∈ A: (a, b) ∈ R for some b ∈ B}
- Range of R = {b ∈ B: (a, b) ∈ R for some a ∈ A}
- Codomain of R is the set B itself; range is always a subset of codomain
Properties of Relations — Quick Reference Table
The table below lists reflexive, symmetric, transitive and equivalence properties. Each property has a formal definition and a quick test you can apply during exams. A relation is an equivalence relation if and only if it satisfies all three: reflexive, symmetric and transitive. NCERT exercises in Class 12 Mathematics Chapter 1 heavily test verification of these properties, so keep this table handy during revision. Equivalence relations partition a set into disjoint equivalence classes, a concept that underpins modular arithmetic and many higher-level proofs.
- Reflexive: ∀ a ∈ A, (a,a) ∈ R — every element is related to itself
- Symmetric: (a,b) ∈ R ⇒ (b,a) ∈ R — relation works both ways
- Transitive: (a,b) ∈ R and (b,c) ∈ R ⇒ (a,c) ∈ R — relation carries through a chain
- Equivalence: R is reflexive, symmetric and transitive all at once
Types of Functions — Definitions and Tests
Functions map every element of the domain to exactly one element in the codomain. In CBSE Class 12 Mathematics, you must distinguish between one-one (injective), onto (surjective) and bijective functions. A function f: A → B is one-one if f(x₁)=f(x₂) implies x₁=x₂; it is onto if for every y ∈ B there exists x ∈ A such that f(x)=y. Bijective functions are both one-one and onto, and only bijective functions are invertible. The NCERT textbook provides algebraic and graphical tests; in board exams, you may be asked to prove injectivity or surjectivity algebraically or to sketch and interpret graphs. Remember that composition and invertibility questions always presume you know these classifications inside out.
- One-One (Injective): f(x₁)=f(x₂) ⇒ x₁=x₂, or equivalently x₁≠x₂ ⇒ f(x₁)≠f(x₂)
- Onto (Surjective): Range of f equals codomain B; every element in B is 'hit'
- Bijective: both one-one and onto; establishes a perfect pairing between A and B
- Many-One: at least two distinct elements in A map to the same element in B
- Into: at least one element in B has no pre-image in A
Composition of Functions — Formula and Properties
Composition (gof)(x) means apply f first, then apply g to the result: (gof)(x)=g(f(x)). The domain of gof is the set of all x in the domain of f such that f(x) lies in the domain of g. Composition is associative: (fog)oh = fo(goh), but it is not commutative: gof ≠ fog in general. NCERT Class 12 Mathematics exercises require you to compute compositions, verify associativity and show non-commutativity with counter-examples. Composition is central to defining inverse functions and is tested in 3–4 mark questions every year in CBSE boards. Always write down the domain and range of each function before attempting composition.
- (gof)(x) = g(f(x)); apply f first, then g
- Domain of gof ⊆ domain of f; specifically, x must satisfy f(x) ∈ domain of g
- Associative: ho(gof) = (hog)of
- Not commutative: usually gof ≠ fog
- Identity function I satisfies (Iof)(x)=f(x) and (foI)(x)=f(x)
Inverse Functions — Existence and Formula
A function f: A → B has an inverse f⁻¹: B → A if and only if f is bijective. The inverse satisfies (fof⁻¹)(y)=y for all y ∈ B and (f⁻¹of)(x)=x for all x ∈ A. To find f⁻¹ algebraically, write y=f(x), solve for x in terms of y to get x=f⁻¹(y), then swap variables. NCERT problems ask you to verify invertibility, compute the inverse and confirm the composition properties. Remember that if f is not bijective, an inverse function does not exist (though left or right inverses may exist in advanced contexts). Board exam questions often carry 4–6 marks for proving bijection and finding the explicit inverse formula.
- f invertible ⇔ f is bijective (one-one and onto)
- (fof⁻¹)(y)=y and (f⁻¹of)(x)=x (identity compositions)
- If f: A → B is invertible, then f⁻¹: B → A
- Graphs of f and f⁻¹ are reflections in the line y=x
Binary Operations — Definition and Properties
A binary operation * on a set A is a function *: A×A → A. Closure means for all a,b ∈ A, a*b ∈ A. Commutativity: a*b=b*a for all a,b. Associativity: (a*b)*c=a*(b*c) for all a,b,c. An identity element e satisfies a*e=e*a=a for all a. An element a has an inverse a⁻¹ if a*a⁻¹=a⁻¹*a=e. NCERT Class 12 Mathematics Chapter 1 includes tables to check these properties for operations like addition, multiplication and custom-defined operations. Board exams test your ability to verify closure, find identity and inverses, and prove or disprove commutativity and associativity with concrete examples.
- Closure: a*b ∈ A for all a,b ∈ A
- Commutativity: a*b = b*a
- Associativity: (a*b)*c = a*(b*c)
- Identity e: a*e = e*a = a
- Inverse of a: a*a⁻¹ = a⁻¹*a = e
Common Mistakes and Notation Traps
Many Class 12 students lose marks by confusing codomain with range, or by assuming every function has an inverse. Another frequent error is writing gof when you mean fog, or forgetting to check the domain condition before composing. When proving a relation is equivalence, you must verify all three properties explicitly; showing just two is insufficient. In binary operations, students often assume commutativity without proof—always test with a counter-example if in doubt. Notation mistakes include writing f⁻¹(x) for the reciprocal 1/f(x) instead of the inverse function. CBSETUTOR.ai helps students catch these mistakes in real time: upload a photo of your working, and the AI tutor highlights notation slips and logical gaps instantly, available 24×7 at ₹999/month for all classes 6–12, with a 3-day free trial.
- Codomain vs Range: codomain is the target set B; range is the actual set of output values, always ⊆ B
- One-One vs Onto: one-one concerns injectivity (no two inputs to same output); onto concerns surjectivity (every output is achieved)
- gof ≠ fog: composition order matters; always apply the rightmost function first
- f⁻¹(x) is the inverse function, not 1/f(x); write reciprocal as (f(x))⁻¹ or 1/f(x)
- Equivalence relation: must prove reflexive AND symmetric AND transitive; two out of three is not enough
Memory Tricks and Mnemonics
To remember reflexive, symmetric, transitive think 'RST' like a reset button—check all three to reset your relation as an equivalence. For one-one and onto, use the mnemonic 'Injective = Individual' (each output has at most one input) and 'Surjective = Covers All' (every output is hit). To recall composition order in gof, read right-to-left like Hebrew: 'f first, then g'. For binary operations, 'CCIA'—Closure, Commutativity, Identity, Associativity—is the standard checklist. These simple hooks save precious seconds in the board exam hall and reduce silly errors. Practice these mnemonics during mock tests so they become second nature by exam day.
- RST = Reflexive, Symmetric, Transitive (all three for equivalence)
- Injective = Individual outputs; Surjective = Covers all of codomain
- gof → read right-to-left: 'f first, g second'
- CCIA checklist for binary operations: Closure, Commutativity, Identity, Associativity
Three Solved Mini-Examples Applying the Formulas
Below are three worked problems that integrate multiple formulas from this chapter. Each example is chosen to reflect typical CBSE board exam patterns: verifying equivalence, proving a function is bijective and finding its inverse, and computing a composition. Work through these step-by-step, then try similar problems from the NCERT Class 12 Mathematics textbook exercises 1.1 to 1.4. Repetition of these problem types builds the muscle memory you need to solve unseen questions confidently under timed conditions.
One-Glance Last-Minute Revision Box
Use this box the night before your exam or during the 15-minute reading time in the exam hall. It condenses the entire chapter into bullet points you can scan in under two minutes. Cover the key definitions, the three properties for equivalence, the two conditions for bijection, the composition formula, the inverse existence criterion and the CCIA checklist for binary operations. Tick off each point as you recall the associated formula or test. This active recall drill cements memory and boosts confidence. Print this box or screenshot it on your phone for quick mobile revision during commute or breaks.
- Relation on A: subset of A×A; Equivalence ⇔ Reflexive + Symmetric + Transitive
- Function types: One-One (f(x₁)=f(x₂)⇒x₁=x₂), Onto (range=codomain), Bijective (both)
- Composition: (gof)(x)=g(f(x)); associative, not commutative; domain condition range(f)⊆domain(g)
- Inverse: exists ⇔ f bijective; (fof⁻¹)=I and (f⁻¹of)=I; graph symmetry about y=x
- Binary operation *: Closure (a*b∈A), Commutativity (a*b=b*a), Identity e (a*e=a), Associativity ((a*b)*c=a*(b*c))
- Common pitfalls: confusing codomain/range, forgetting domain in composition, assuming commutativity, writing f⁻¹ for reciprocal
Frequently asked questions
What is the difference between codomain and range of a function?+
Codomain is the entire target set B in the definition f: A → B. Range is the actual set of output values {f(x): x ∈ A}, which is always a subset of the codomain. A function is onto if range equals codomain.
How do I prove a relation is an equivalence relation?+
You must verify all three properties: (i) Reflexive – every element is related to itself, (ii) Symmetric – if aRb then bRa, (iii) Transitive – if aRb and bRc then aRc. Missing even one property means R is not equivalence.
What is the quickest test to check if a function is one-one?+
Assume f(x₁)=f(x₂) and try to prove x₁=x₂ algebraically. If you succeed, the function is one-one (injective). Alternatively, check that the horizontal line test holds on the graph: no horizontal line cuts the curve more than once.
When does a function have an inverse?+
A function f: A → B has an inverse if and only if it is bijective—both one-one and onto. If f is not bijective, you cannot define a function f⁻¹: B → A that satisfies the inverse composition properties.
Why is composition of functions not commutative?+
Because (gof)(x)=g(f(x)) applies f first then g, while (fog)(x)=f(g(x)) applies g first then f. These sequences usually yield different results. For example, if f(x)=x+1 and g(x)=x², then gof gives (x+1)² but fog gives x²+1.
How do I find the inverse of a function algebraically?+
First verify the function is bijective. Write y=f(x), solve for x in terms of y to get x=expression in y, then replace y with x. That expression is f⁻¹(x). Always verify by checking (fof⁻¹)(x)=x and (f⁻¹of)(x)=x.
What does closure mean for a binary operation?+
Closure means that for any two elements a,b in set A, the result a*b is also in A. For example, addition on natural numbers is closed because the sum of two naturals is a natural, but subtraction is not closed on naturals because 2−5=−3 ∉ ℕ.
Can a relation be symmetric and transitive but not reflexive?+
Yes. For example, on A={1,2}, let R={(1,1)}. It is symmetric (vacuously, since there is no (a,b) with a≠b) and transitive, but not reflexive because (2,2) is missing. So R is not an equivalence relation.
How many marks does Chapter 1 Relations and Functions carry in CBSE Class 12 boards?+
Typically 6–10 marks across 2–3 questions. You may see one 4-mark question on composition or inverse, one 2-mark question on types of relations, and a 1-mark multiple-choice question. Exact weightage varies slightly year to year.
Where can I get step-by-step solutions if I am stuck on an NCERT exercise problem?+
CBSETUTOR.ai offers 24×7 AI tutoring: snap a photo of the problem, and the platform provides instant worked solutions with explanations. It covers all NCERT exercises for Class 12 Mathematics at ₹999/month for classes 6–12, with a 3-day free trial to try before you subscribe.
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