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CBSE Class 12 Chemistry Chapter 2 Electrochemistry Worksheet with Answers

Electrochemistry is a high-weightage chapter in CBSE Class 12 Chemistry, contributing 5-6 marks in the board examination. This printable worksheet covers all NCERT topics—electrochemical cells, Nernst equation, conductance, batteries and fuel cells—with a balanced mix of theory recall, numerical problems and application-based questions. Complete this worksheet in one sitting to simulate exam conditions and use the detailed answer key for self-evaluation.

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Key takeaways

  • Worksheet contains 65+ questions spanning all difficulty levels and question types as per CBSE Class 12 board exam pattern for Electrochemistry.
  • Covers electrochemical cells (Galvanic and electrolytic), electrode potentials, Nernst equation derivations and applications thoroughly.
  • Includes numerical problems on conductance, molar conductivity, Kohlrausch law and electrochemical cell calculations.
  • Case-study question mirrors the latest 2025 CBSE board exam format with real-world applications of fuel cells and batteries.
  • Complete answer key provided with step-by-step explanations, standard electrode potential values and formula references.
  • Designed for 90-minute self-assessment; ideal for pre-board practice and chapter revision before CBSE Class 12 board exams.
  • CBSETUTOR.ai offers 24×7 doubt solving with photo upload for tricky Electrochemistry numericals at ₹999/month with 3-day free trial.

Quick Chapter Recap: Electrochemistry

Chapter 2 of NCERT Class 12 Chemistry focuses on the interconversion of chemical energy and electrical energy. Electrochemical cells are devices that convert chemical energy into electrical energy (Galvanic cells) or electrical energy into chemical energy (electrolytic cells). Key concepts include standard electrode potential, cell potential calculation using the Nernst equation, conductance and its measurement, molar conductivity, Kohlrausch law, and applications in batteries (primary and secondary) and fuel cells. The chapter also covers electrolysis, products at electrodes, and Faraday's laws of electrolysis. Understanding sign conventions, standard reduction potentials from the electrochemical series, and the relationship between Gibbs free energy and cell potential is crucial for solving numerical problems. The 2025 CBSE board exam typically includes 1-2 MCQs, one 2-mark question, one 3-mark question and sometimes a case-study question from this chapter.
  • Galvanic cells: spontaneous redox reactions, anode (oxidation), cathode (reduction), positive EMF
  • Nernst equation: E(cell) = E°(cell) - (0.0591/n) log Q at 298 K for calculating cell potential under non-standard conditions
  • Conductance (G) = 1/Resistance; conductivity (κ) and molar conductivity (Λm) relationships
  • Kohlrausch law: molar conductivity at infinite dilution is sum of individual ionic contributions
  • Standard hydrogen electrode (SHE) reference: E° = 0.00 V at all temperatures
  • Batteries: Primary (non-rechargeable like dry cell), Secondary (rechargeable like lead storage), Fuel cells (H₂-O₂)

Section A: Multiple Choice Questions (1 mark each)

This section tests your conceptual clarity and quick recall of Electrochemistry fundamentals. Each MCQ has four options; select the most appropriate answer. Topics covered include cell representation, electrode reactions, standard potentials, conductance units, and battery chemistry. Remember that in galvanic cell notation, anode is written on the left and cathode on the right, with salt bridge represented by double vertical lines. For Nernst equation problems, ensure you identify the number of electrons transferred correctly. The electrochemical series helps predict spontaneity: a metal with lower reduction potential will displace one with higher reduction potential from its salt solution. Pay attention to units: conductivity is in S m⁻¹, molar conductivity in S cm² mol⁻¹, and cell constant in cm⁻¹ or m⁻¹ depending on the problem context.
  • Q1. The EMF of a galvanic cell is always: (a) Positive (b) Negative (c) Zero (d) Depends on concentration
  • Q2. Standard electrode potential of hydrogen electrode is taken as: (a) 1.00 V (b) 0.00 V (c) -1.00 V (d) 0.76 V
  • Q3. Which cell can be recharged? (a) Dry cell (b) Mercury cell (c) Lead storage battery (d) Fuel cell
  • Q4. Unit of molar conductivity is: (a) S m² mol⁻¹ (b) S cm² mol⁻¹ (c) S m⁻¹ (d) ohm cm
  • Q5. In the Nernst equation, 'n' represents: (a) Number of moles (b) Number of electrons (c) Avogadro number (d) Normality
  • Q6. Corrosion of iron is: (a) Reduction (b) Oxidation (c) Sublimation (d) Decomposition
  • Q7. The conductivity of a solution decreases on dilution because: (a) Number of ions per unit volume decreases (b) Degree of dissociation decreases (c) Both (a) and (b) (d) None
  • Q8. In a fuel cell, the energy conversion is: (a) Heat to electrical (b) Chemical to electrical (c) Mechanical to electrical (d) Nuclear to electrical

Section B: Fill in the Blanks (1 mark each)

Complete each statement with the correct term, formula, or value. This section reinforces terminology and key formulae from Class 12 Chemistry Chapter 2. When writing chemical formulae, ensure correct subscripts and superscripts. For example, the calomel electrode uses Hg₂Cl₂, not HgCl₂. The relationship between Gibbs free energy and cell potential is ΔG° = -nFE°, where F is the Faraday constant (96500 C mol⁻¹). Conductance and resistance are reciprocals: G = 1/R. Molar conductivity at infinite dilution is denoted as Λ°m. The salt bridge typically contains KCl or KNO₃ in agar-agar gel to maintain electrical neutrality. Standard cell potential is calculated as E°(cathode) - E°(anode). Electrolysis always involves non-spontaneous reactions driven by external electrical energy.
  • Q9. The device used to convert chemical energy into electrical energy is called an __________ cell.
  • Q10. The electrode at which oxidation occurs is called the __________.
  • Q11. E°cell = E°cathode - E°__________.
  • Q12. Λ°m for CH₃COOH can be calculated using Kohlrausch law as Λ°(CH₃COONa) + Λ°(HCl) - Λ°(__________).
  • Q13. The unit of cell constant is __________.
  • Q14. At equilibrium, the EMF of a cell is __________.
  • Q15. The electrode potential __________ (increases/decreases) when concentration of ions in solution increases.
  • Q16. Rusting of iron involves loss of __________ from iron metal.

Section C: Match the Following and True/False (1 mark each)

Part C1 requires matching electrochemical concepts with their correct descriptions or values from the electrochemical series. The standard reduction potential values must be memorized for common half-cells: Li⁺/Li has the most negative value (-3.05 V), making lithium the strongest reducing agent, while F₂/F⁻ has the most positive (+2.87 V), making fluorine the strongest oxidizing agent. Copper does not displace hydrogen from dilute acids because E°(Cu²⁺/Cu) = +0.34 V is more positive than E°(H⁺/H₂) = 0.00 V. The electrochemical series helps predict the feasibility of redox reactions. Part C2 tests understanding of statements about conductance, batteries, and cell conventions. Remember that molar conductivity increases on dilution for weak electrolytes due to increased degree of dissociation, but conductivity always decreases because the number of ions per unit volume decreases despite increased ionization.
  • Part C1: Match Column A with Column B
  • Column A: (i) Salt bridge (ii) Anode (iii) SHE (iv) Λ°m
  • Column B: (a) Molar conductivity at infinite dilution (b) 0.00 V (c) Maintains electrical neutrality (d) Negative electrode in galvanic cell
  • Part C2: State True or False
  • Q17. Molar conductivity of a solution increases with dilution. (True/False)
  • Q18. In electrolytic cell, anode is positive. (True/False)
  • Q19. Fuel cells are more efficient than conventional cells. (True/False)
  • Q20. The value of E°cell is independent of concentration. (True/False)

Section D: Short Answer Questions (2-3 marks each)

These questions require concise explanations, definitions, derivations or short numerical solutions. CBSE Class 12 board exams typically allocate 2 marks for definition-based or one-step calculation questions and 3 marks for two-step problems or short derivations. When defining terms, include the mathematical expression and SI unit. For electrochemical cell problems, always write the cell representation correctly using IUPAC conventions: anode half-cell on left, cathode on right, single vertical line for phase boundary, double vertical line for salt bridge. Numerical answers must include proper units and significant figures. The Nernst equation at 298 K simplifies to E = E° - (0.0591/n) log Q, which is most commonly used in calculations. For conductance problems, remember cell constant (G*) = κ/G where κ is conductivity and G is conductance. Kohlrausch law is essential for calculating Λ°m of weak electrolytes which cannot be measured directly.
  • Q21. Define molar conductivity. How does it vary with dilution for weak electrolytes? (2 marks)
  • Q22. Write the cell representation and calculate E°cell for the reaction: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s). Given E°(Zn²⁺/Zn) = -0.76 V, E°(Cu²⁺/Cu) = +0.34 V. (3 marks)
  • Q23. State Faraday's first law of electrolysis. (2 marks)
  • Q24. Why is it not possible to measure the potential of a single electrode? (2 marks)
  • Q25. Distinguish between primary and secondary batteries with one example each. (3 marks)
  • Q26. Calculate the standard free energy change for the cell: Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s) if E°cell = 3.17 V. (3 marks)
  • Q27. What is a salt bridge? Write its two functions. (2 marks)

Section E: Long Answer and HOTS Questions (5 marks each)

This section contains application-based and higher-order thinking problems that test deep conceptual understanding and multi-step problem-solving skills typical of CBSE Class 12 Chemistry board exams. Each question carries 5 marks and requires detailed explanations, derivations or complex numerical calculations. When deriving the Nernst equation, start from the relationship between Gibbs free energy and reaction quotient: ΔG = ΔG° + RT ln Q, then substitute ΔG = -nFE and ΔG° = -nFE° to arrive at the final form. For conductance numericals, you may need to apply multiple concepts: cell constant determination, conductivity calculation, and finally molar conductivity using the relationship Λm = (κ × 1000)/M where M is molarity. Problems involving concentration cells require careful application of the Nernst equation with E° = 0. Electrochemical series applications demand understanding of relative electrode potentials to predict reaction feasibility and product formation during electrolysis.
  • Q28. (a) Derive the Nernst equation for a general electrochemical cell. (b) Calculate the emf of the cell: Zn|Zn²⁺(0.1 M)||Cu²⁺(0.01 M)|Cu at 298 K. E°cell = 1.10 V. (5 marks)
  • Q29. (a) State and explain Kohlrausch law of independent migration of ions. (b) The conductivity of 0.001 M acetic acid is 4.95 × 10⁻⁵ S cm⁻¹. Calculate its molar conductivity and degree of dissociation. Given Λ°m(CH₃COOH) = 390.5 S cm² mol⁻¹. (5 marks)
  • Q30. (a) Explain the construction and working of a standard hydrogen electrode. (b) Why is it not feasible to use SHE in routine laboratory work? (c) What are reference electrodes? Give one example. (5 marks)

Section F: Case Study Question (4 marks)

Case-study questions have been a mandatory component of CBSE Class 12 Chemistry board papers since 2021. This format presents a real-world scenario or experimental context followed by 3-4 sub-questions that test application, analysis and evaluation skills. The case study on fuel cells connects Electrochemistry concepts to sustainable energy solutions, a topic of global importance. Hydrogen-oxygen fuel cells are increasingly used in space missions and electric vehicles because they produce electricity continuously as long as fuel is supplied, unlike conventional batteries which get discharged. The electrode reactions involve oxidation of hydrogen at the anode (2H₂ + 4OH⁻ → 4H₂O + 4e⁻ in alkaline medium) and reduction of oxygen at the cathode (O₂ + 2H₂O + 4e⁻ → 4OH⁻). The overall reaction is 2H₂ + O₂ → 2H₂O with water as the only product, making it environmentally clean. Students must read the passage carefully and answer specific questions based on the given information and their chapter knowledge.
  • Case Study: Read the passage and answer questions 31-34.
  • Passage: Fuel cells are galvanic cells that convert the energy of combustion of fuels like hydrogen, methane, methanol, etc., directly into electrical energy. The hydrogen-oxygen fuel cell operates at 373-473 K with 40% efficiency. In this cell, hydrogen and oxygen are bubbled through porous carbon electrodes into concentrated aqueous sodium hydroxide solution. Catalysts like finely divided platinum or palladium metal are incorporated into the electrodes for increasing the reaction rate. The electrode reactions are: Cathode: O₂(g) + 2H₂O(l) + 4e⁻ → 4OH⁻(aq); Anode: 2H₂(g) + 4OH⁻(aq) → 4H₂O(l) + 4e⁻.
  • Q31. What is the overall cell reaction in a H₂-O₂ fuel cell? (1 mark)
  • Q32. Why are fuel cells considered more efficient than conventional cells? (1 mark)
  • Q33. Name the electrolyte used in the H₂-O₂ fuel cell and state the role of platinum. (1 mark)
  • Q34. Calculate the maximum work obtained from the H₂-O₂ fuel cell if E°cell = 1.23 V and 2 moles of H₂ are consumed. (1 mark)

Complete Answer Key with Explanations

This detailed answer key provides correct answers with brief explanations, formula references and calculation steps for self-assessment. Cross-check your responses carefully and understand the logic behind each answer. For MCQs, the explanation highlights why the chosen option is correct and why others are incorrect. Numerical answers include the relevant formula, substitution of values with units, and final answer with appropriate significant figures. CBSE awards full marks only when units are correctly mentioned in the final answer. For derivations, ensure you follow the logical sequence of steps as shown in the answer key. Understanding the conceptual reasoning is more important than memorizing answers. If you score below 70% on this worksheet, revise the NCERT Class 12 Chemistry Chapter 2 thoroughly, focusing on weak areas. Students aiming for 95+ in boards should target 90%+ on this worksheet. Use CBSETUTOR.ai for step-by-step photo-based doubt solving if you are stuck on any tricky Electrochemistry numerical or concept.
  • Section A Answers: 1(a), 2(b), 3(c), 4(b), 5(b), 6(b), 7(a), 8(b)
  • Section B Answers: 9-electrochemical, 10-anode, 11-anode, 12-NaCl, 13-cm⁻¹ or m⁻¹, 14-zero, 15-increases, 16-electrons
  • Section C Answers: C1- (i)c, (ii)d, (iii)b, (iv)a; C2- Q17-True, Q18-True, Q19-True, Q20-True
  • Q21: Molar conductivity is conductance of all ions produced from 1 mole of electrolyte in solution; unit S cm² mol⁻¹. For weak electrolytes, Λm increases sharply with dilution due to increased degree of dissociation.
  • Q23: Faraday's first law states that the mass of substance deposited or liberated at an electrode is directly proportional to the quantity of electricity passed: m ∝ Q or m = ZQ where Z is electrochemical equivalent.
  • Q24: A single electrode potential cannot be measured because oxidation or reduction cannot occur alone; both half-reactions must occur simultaneously. We can only measure potential difference between two electrodes.
  • Q25: Primary batteries cannot be recharged (e.g., dry cell, mercury cell); secondary batteries can be recharged by passing current in reverse direction (e.g., lead storage battery, Ni-Cd battery).
  • Q26: ΔG° = -nFE°cell = -2 × 96500 × 3.17 = -611810 J = -611.81 kJ
  • Q27: Salt bridge is a U-tube containing inert electrolyte in agar gel. Functions: (i) Completes the circuit, (ii) Maintains electrical neutrality by allowing ion migration.
  • Q29(b): Λm = (κ × 1000)/M = (4.95×10⁻⁵ × 1000)/0.001 = 49.5 S cm² mol⁻¹; α = Λm/Λ°m = 49.5/390.5 = 0.127 or 12.7%
  • Q30(a): SHE consists of platinum electrode coated with platinum black, dipped in 1 M HCl, with H₂ gas at 1 bar bubbled at 298 K. Reaction: 2H⁺ + 2e⁻ ⇌ H₂. By convention E° = 0.00 V. (b) Not feasible due to difficulty in maintaining 1 bar H₂ pressure and 1 M acid. (c) Reference electrodes like calomel or silver-silver chloride are used instead.
  • Q32: Fuel cells convert chemical energy directly to electrical energy without combustion, avoiding Carnot cycle limitations; efficiency ~40-60% vs ~20-25% in thermal plants.
  • Q33: Electrolyte is concentrated NaOH(aq). Platinum acts as a catalyst to increase the rate of electrode reactions.
  • Q34: Maximum work = -ΔG = nFE°cell = 4 × 96500 × 1.23 = 474780 J = 474.78 kJ (since 2 moles H₂ involves transfer of 4 moles e⁻)

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Tips for Scoring Full Marks in Electrochemistry

Electrochemistry questions in CBSE Class 12 Chemistry board exams are highly scoring if you follow a systematic approach. For cell representation, always follow IUPAC conventions strictly: anode on left, cathode on right, phase boundaries marked correctly. In numerical problems, write the formula first, then substitute values with units, and box the final answer with correct unit and significant figures—CBSE marking schemes award step-wise marks, so even if your final answer is wrong, you can earn partial credit for correct method. Memorize standard electrode potentials for at least 10 common half-cells including Li⁺/Li, Zn²⁺/Zn, Fe²⁺/Fe, H⁺/H₂, Cu²⁺/Cu, Ag⁺/Ag, and Au³⁺/Au. For Kohlrausch law problems, carefully identify the ions and write the equation correctly—common errors include wrong ionic formulae or sign mistakes. During electrolysis questions, determine the products at anode and cathode based on discharge potential and concentration; remember that in aqueous solutions, H₂O can be oxidized or reduced preferentially. Practice at least 20 Nernst equation numericals with varying concentrations and number of electrons to build speed and accuracy.
  • Make a formula sheet with Nernst equation, conductance relationships, Faraday's laws, and ΔG-E° relation for quick revision
  • Practice cell notation rigorously; incorrect representation costs easy marks in board exams
  • Solve previous 5 years' CBSE board papers for Electrochemistry—question pattern repeats
  • For case studies, underline key data in the passage before attempting sub-questions
  • Time management: allocate 15 minutes for a 5-mark derivation+numerical question, 5 minutes for 2-mark definitions
  • Revise electrochemical series the night before exam—it helps in MCQs and predicting reactions

Frequently asked questions

What is the weightage of Electrochemistry in CBSE Class 12 Chemistry board exam 2025?+
Electrochemistry typically carries 5-6 marks in the CBSE Class 12 Chemistry board exam. You can expect 1-2 MCQs (1 mark each), one short answer question (2-3 marks), and often a numerical problem or case study (3-4 marks) from this chapter.
How do I remember the electrochemical series for board exams?+
Create a mnemonic for the first letters of metals in decreasing order of reactivity: Li, K, Ca, Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au. Practice writing the series daily. Remember Li⁺/Li has most negative E° (-3.05 V) and Au³⁺/Au has positive E° (+1.50 V). Focus on relative positions—that is what helps predict reactions.
What is the most common mistake students make in Nernst equation problems?+
The most common error is getting the sign wrong (writing + instead of -) or miscounting the number of electrons transferred (n). Always identify oxidation states first, count electron change carefully, and remember the equation is E = E° minus the log term. At equilibrium, E = 0, which gives you the relation between E° and K.
How is molar conductivity different from conductivity?+
Conductivity (κ) is the conductance of a solution of specific dimensions; unit is S m⁻¹ or S cm⁻¹. Molar conductivity (Λm) is conductance of all ions produced by 1 mole of electrolyte; unit is S cm² mol⁻¹. Relationship: Λm = (κ × 1000)/M where M is molarity. Conductivity decreases on dilution, but molar conductivity increases.
Can a cell with negative E° value work as a galvanic cell?+
No. A galvanic cell requires a spontaneous reaction, which occurs only when E°cell is positive (ΔG° negative). If E°cell is negative, the reaction is non-spontaneous and requires external electrical energy to proceed—this is an electrolytic cell, not a galvanic cell.
Why do we use platinum electrodes in SHE and fuel cells?+
Platinum is chemically inert, does not participate in the electrode reaction, has excellent electrical conductivity, and acts as an efficient catalyst for hydrogen and oxygen reactions. Platinum black (finely divided platinum) provides large surface area for gas adsorption, increasing reaction rate without getting consumed.
What is Kohlrausch law and why is it important?+
Kohlrausch law states that at infinite dilution, molar conductivity of an electrolyte is the sum of individual contributions of its constituent ions: Λ°m = λ°+ + λ°-. It is crucial because it allows calculation of Λ°m for weak electrolytes (like CH₃COOH) which cannot be measured directly, using Λ°m values of strong electrolytes.
How do I prepare Electrochemistry in 3 days before board exams?+
Day 1: Revise NCERT theory—electrochemical cells, cell notation, Nernst equation derivation, conductance definitions. Day 2: Solve 15-20 numericals covering Nernst equation, conductance, and electrolysis. Day 3: Attempt previous year board questions and one full worksheet. Memorize electrode potentials, formulae, and Faraday constant value (96500 C mol⁻¹). Focus on scoring areas like cell notation and formula-based short questions.
Is Electrochemistry difficult compared to other Class 12 Chemistry chapters?+
Electrochemistry has a reputation for being numerical-heavy, but it is actually one of the most scoring chapters if you practice systematically. The formulae are few and the question pattern is predictable. Unlike Organic Chemistry which requires memorization of many reactions, Electrochemistry needs conceptual clarity and formula application—easier to master with focused practice.
Where can I get step-by-step solutions for tricky Electrochemistry numericals?+
CBSETUTOR.ai offers instant step-by-step solutions via photo upload. Snap any Electrochemistry problem from your worksheet or reference book, and the AI tutor breaks it down formula-by-formula with unit checks and final answer. At ₹999/month for all subjects across Classes 6-12, plus a 3-day free trial, it is the most affordable 24×7 doubt-solving resource for CBSE students preparing for board exams.

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