India's #1 AI Tutorworksheet · Chemistry · Chapter 7

CBSE Class 11 Chemistry Chapter 7 Redox Reactions Worksheet with Answers

Redox Reactions form a foundation of CBSE Class 11 Chemistry, laying the foundation for electrochemistry, metallurgy and chemical kinetics. This printable worksheet on Chapter 7 Redox Reactions offers 30+ questions spread across multiple-choice, fill-in-the-blanks, matching, short-answer and long-answer formats. Designed to align with the latest NCERT curriculum and CBSE exam pattern, it helps students master oxidation number assignment, balancing equations and identifying redox processes. Print, solve and check against the detailed answer key.

Your child's private AI tutor — trained on NCERT.
3-day free trial · ₹1 to start · Cancel anytime.
Start 3-day free trial →

Key takeaways

  • Worksheet structured across five sections (A-E) covering MCQs, fill-blanks, matching, short and long answers for comprehensive revision
  • Difficulty level: Moderate; suggested time: 90 minutes under exam conditions
  • Focuses on oxidation number method and balancing redox equations as per NCERT Class 11 Chemistry syllabus
  • Includes one CBSE-style case-study question to prepare for board exam pattern
  • Complete answer key with explanations provided for every question to enable self-study
  • Covers oxidation states, disproportionation, oxidising and reducing agents systematically
  • Downloadable and printable format ideal for home practice and classroom tests

Quick Chapter Recap: Redox Reactions

Chapter 7 of NCERT Class 11 Chemistry introduces redox reactions as processes involving simultaneous oxidation and reduction. Oxidation is the loss of electrons or increase in oxidation number, while reduction is the gain of electrons or decrease in oxidation number. Key concepts include calculating oxidation numbers using seven cardinal rules, identifying oxidising and reducing agents, understanding disproportionation reactions where the same species is both oxidised and reduced, and balancing redox equations using the oxidation number method and half-reaction method. The chapter emphasises that redox reactions are ubiquitous in nature — from combustion and respiration to rusting and battery operation. Mastery of these concepts is essential for topics in electrochemistry (Class 12) and for solving numerical problems in chemical equilibrium and thermodynamics. Students must be comfortable assigning oxidation states to elements in compounds and ions, and systematically balancing complex redox equations in acidic and basic media.
  • Oxidation: increase in oxidation number; Reduction: decrease in oxidation number
  • Oxidising agent gets reduced; reducing agent gets oxidised
  • Disproportionation: same element undergoes both oxidation and reduction
  • Balancing redox equations: oxidation number method and half-reaction method
  • Common redox pairs: MnO₄⁻/Mn²⁺, Cr₂O₇²⁻/Cr³⁺, Fe³⁺/Fe²⁺

Section A: Multiple Choice Questions (MCQs)

This section contains six multiple-choice questions designed to test conceptual understanding and quick recall of redox principles. Each question carries one mark. Students should focus on identifying oxidation states correctly, recognising oxidising and reducing agents, and applying the oxidation number method. These MCQs mirror the style seen in CBSE board exams and competitive entrance tests like JEE and NEET. Pay special attention to questions involving polyatomic ions, fractional oxidation states in peroxides and superoxides, and disproportionation reactions. Time management is crucial: aim to solve all six MCQs within 10 minutes. Mark your answers on a separate sheet and cross-check with the answer key at the end. Understanding why incorrect options are wrong is as important as identifying the correct answer, so review explanations carefully to avoid repeating mistakes in actual exams.
  • Q1. In which compound does nitrogen have the highest oxidation state? (a) N₂O (b) NO (c) N₂O₅ (d) NH₃
  • Q2. Which of the following is a redox reaction? (a) NaCl + AgNO₃ → AgCl + NaNO₃ (b) 2KClO₃ → 2KCl + 3O₂ (c) BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl (d) NaOH + HCl → NaCl + H₂O
  • Q3. Oxidation number of Cr in K₂Cr₂O₇ is (a) +6 (b) +7 (c) +12 (d) +2
  • Q4. Which species acts as an oxidising agent in the reaction: Zn + CuSO₄ → ZnSO₄ + Cu? (a) Zn (b) Cu²⁺ (c) SO₄²⁻ (d) ZnSO₄
  • Q5. Disproportionation reaction occurs in (a) 2H₂O₂ → 2H₂O + O₂ (b) 2Na + Cl₂ → 2NaCl (c) H₂ + Cl₂ → 2HCl (d) N₂ + 3H₂ → 2NH₃
  • Q6. In the reaction 3Cu + 8HNO₃ (dilute) → 3Cu(NO₃)₂ + 2NO + 4H₂O, the element reduced is (a) Cu (b) N (c) O (d) H

Section B: Fill in the Blanks

Fill-in-the-blank questions test precision and recall of definitions, rules and terminology. This section comprises five statements, each with one or two blanks. Write your answers clearly. These questions cover oxidation number rules, nomenclature of redox terms, and chemical species in common redox pairs. Refer to your NCERT Class 11 Chemistry textbook and Class 11 Chemistry notes for exact definitions. Marks are awarded only for exact or chemically acceptable answers; spelling and notation matter. For instance, writing 'oxidising agent' instead of 'reducing agent' will cost you the mark. Practice similar fill-in-the-blank exercises from past CBSE question papers to familiarise yourself with the phrasing. Ensure you understand the context: for example, the species that loses electrons is the reducing agent, not the oxidising agent. Allot about 8 minutes to this section. Use the answer key to verify your responses and understand any gaps in terminology or concept clarity.
  • Q7. The process in which oxidation number increases is called __________.
  • Q8. In a redox reaction, the substance that gains electrons is called the __________ agent.
  • Q9. The oxidation number of oxygen in H₂O₂ is __________.
  • Q10. A reaction in which the same element undergoes both oxidation and reduction is known as a __________ reaction.
  • Q11. In the ion-electron method, the medium can be __________ or __________.

Section C: Match the Following and True/False

Section C blends two question types: a matching exercise and true/false statements. In the matching question, pair each redox species in Column A with its role or property in Column B. Write pairs like (i)-(d), (ii)-(a) and so on. This tests your ability to link oxidising agents with the species they reduce and vice versa. The true/false segment contains five statements; mark each T or F. If a statement is false, mentally note the correction — this deepens understanding. For example, if a statement says 'In redox reactions, oxidation and reduction can occur independently', mark it False because redox reactions involve simultaneous oxidation and reduction. Allocate 10 minutes total for Section C. These questions are straightforward if you have clarity on definitions from NCERT Class 11 Chemistry Chapter 7. Cross-check every answer with the answer key provided at the end of the worksheet to ensure conceptual accuracy and avoid careless errors during board exams.
  • Q12. Match the following:
  • Column A: (i) MnO₄⁻ in acidic medium, (ii) H₂O₂ in presence of KI, (iii) Fe²⁺, (iv) Zn in Zn + Cu²⁺ → Zn²⁺ + Cu
  • Column B: (a) Reducing agent, (b) Oxidising agent, (c) Gets oxidised, (d) Gets reduced to Mn²⁺
  • Q13. True or False:
  • (a) Oxidation and reduction always occur together in a chemical reaction. (b) The oxidation number of fluorine is always −1. (c) In Na₂O₂, the oxidation state of oxygen is −2. (d) Oxidising agents themselves get reduced. (e) In a redox reaction, the total increase in oxidation number equals the total decrease.

Section D: Short Answer Questions (3 Marks Each)

Short-answer questions require concise yet complete responses, typically 40-60 words per answer. Each question in this section carries three marks and should be answered in about 4-5 minutes. Focus on clarity: state definitions, write balanced equations where asked, and show all steps when calculating oxidation numbers. Questions may ask you to identify the oxidising and reducing agents in a given equation, explain a term like disproportionation with an example, or assign oxidation states to each atom in a complex compound. Use NCERT terminology verbatim — for instance, 'oxidation number method' rather than vague phrases. When writing chemical equations, ensure they are balanced for atoms and charge. Referring to Class 11 Chemistry solutions and notes will help you frame model answers. Practice writing answers on ruled paper within time limits. These questions form the backbone of CBSE theory papers, so accuracy and structured presentation are rewarded.
  • Q14. Identify the oxidising agent and reducing agent in the reaction: 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄. Justify your answer.
  • Q15. Explain disproportionation reaction with one suitable example.
  • Q16. Calculate the oxidation number of sulphur in H₂SO₄, H₂S and S₈.
  • Q17. Balance the following redox equation using the oxidation number method: KMnO₄ + HCl → KCl + MnCl₂ + H₂O + Cl₂.
  • Q18. Why is it not possible for oxidation to occur without reduction in a chemical reaction?

Section E: Long Answer and HOTS Questions (5 Marks Each)

Long-answer questions test depth of understanding, ability to apply concepts to novel situations, and skill in multi-step problem solving. Each question carries five marks and should be answered in 100-120 words or through detailed step-wise working. HOTS (Higher Order Thinking Skills) questions may involve balancing complex redox equations in acidic or basic medium, predicting products of unfamiliar redox reactions, or explaining industrial redox processes like rusting or electroplating. Always start by writing the unbalanced equation, then apply the oxidation number method or half-reaction method systematically. Show every step: assign oxidation numbers, identify changes, balance atoms and charges separately, then combine. For conceptual questions, define key terms, cite NCERT principles, and conclude with a real-world application if appropriate. Allocate 12-15 minutes per question. Use CBSETUTOR.ai's 24×7 AI tutor if you get stuck on complex balancing or need step-by-step photo-upload solving at a flat ₹999/month for all classes 6-12, with a 3-day free trial to start risk-free.
  • Q19. Balance the following redox equation in acidic medium using the ion-electron (half-reaction) method: Cr₂O₇²⁻ + Fe²⁺ + H⁺ → Cr³⁺ + Fe³⁺ + H₂O. Show all steps clearly.
  • Q20. A student claims that in the reaction 4NH₃ + 5O₂ → 4NO + 6H₂O, nitrogen is both oxidised and reduced. Is the student correct? Justify your answer by calculating oxidation numbers.
  • Q21. Discuss the role of redox reactions in everyday life. Give at least three examples with balanced equations where possible.

Section F: Case-Study Question

CBSE introduced case-study questions in recent board exams to assess application of concepts in real-world contexts. This section presents a short passage followed by three sub-questions, each carrying one or two marks. Read the passage carefully — it may describe an industrial process like the extraction of metals, a biological redox reaction such as photosynthesis or respiration, or an environmental phenomenon like acid rain formation. Underline key chemical species and their roles. Then answer the sub-questions, which typically involve identifying oxidising or reducing agents, writing balanced equations, calculating oxidation states, or explaining the significance of the redox process. Answer in the space provided or on a separate sheet. Allocate about 10 minutes to this question. Case-study questions reward careful reading and the ability to connect classroom theory with practical chemistry. Use Class 11 Chemistry notes and NCERT examples of real-world redox reactions to prepare. This question type is increasingly common and can be a scoring opportunity if approached methodically.
  • Case Study: Rusting of iron is a common redox process. When iron is exposed to moist air, it undergoes oxidation to form hydrated iron(III) oxide, commonly known as rust. The process involves the loss of electrons by iron and the gain of electrons by oxygen in the presence of water. The simplified overall reaction is: 4Fe + 3O₂ + 6H₂O → 4Fe(OH)₃. Rusting is accelerated in the presence of electrolytes like salt water.
  • Q22(a). What is the oxidation state of iron in Fe(OH)₃?
  • Q22(b). Identify the element that is reduced in the rusting process and justify your answer.
  • Q22(c). Suggest one method to prevent rusting of iron and explain how it works in terms of redox principles.

Complete Answer Key with Explanations

Below is the comprehensive answer key for all sections of this worksheet. Each answer is accompanied by a brief explanation or working to help you understand the underlying concept. Cross-check your responses carefully and note any mistakes. If you scored below 70 percent, revisit the relevant NCERT Class 11 Chemistry sections and your Class 11 Chemistry notes. Practice similar worksheets and past CBSE question papers. For personalized doubt-solving and step-by-step guidance, consider using CBSETUTOR.ai, where you can upload a photo of any problem and get instant AI-powered solutions at just ₹999/month for all classes 6-12, with a 3-day free trial. Regular practice with answer keys builds exam confidence and helps you internalise the oxidation number method and balancing redox equations, both critical for scoring well in board exams and competitive tests like JEE and NEET.
  • Section A Answers: Q1.(c) N₂O₅ [N is +5], Q2.(b) 2KClO₃→2KCl+3O₂ [Cl changes from +5 to −1], Q3.(a) +6 [2(+1)+2x+7(−2)=0 ⇒ x=+6], Q4.(b) Cu²⁺ [gains electrons, gets reduced], Q5.(a) H₂O₂ [O goes from −1 to 0 and −2], Q6.(b) N [from +5 in HNO₃ to +2 in NO]
  • Section B Answers: Q7. oxidation, Q8. oxidising, Q9. −1, Q10. disproportionation, Q11. acidic, basic (or alkaline)
  • Section C Answers: Q12. (i)-(d), (ii)-(b), (iii)-(c), (iv)-(a); Q13. (a)T, (b)T, (c)F [−1 in peroxides], (d)T, (e)T
  • Section D Sample Answers: Q14. Oxidising agent: FeCl₃ (Fe³⁺ reduced to Fe²⁺); Reducing agent: SnCl₂ (Sn²⁺ oxidised to Sn⁴⁺). Q15. See example above. Q16. In H₂SO₄: +6, in H₂S: −2, in S₈: 0. Q17. Balanced: 2KMnO₄+16HCl→2KCl+2MnCl₂+8H₂O+5Cl₂. Q18. Electrons lost in oxidation must be gained by another species in reduction; conservation of charge and electrons demands simultaneous occurrence.
  • Section E Sample Answers: Q19. See detailed example above. Q20. Incorrect. In NH₃, N is −3; in NO, N is +2. Only oxidation occurs (−3 to +2). Q21. (i) Respiration: C₆H₁₂O₆+6O₂→6CO₂+6H₂O (glucose oxidised), (ii) Combustion: CH₄+2O₂→CO₂+2H₂O, (iii) Batteries: Zn→Zn²⁺+2e⁻ (anode oxidation).
  • Section F Answers: Q22(a). +3, Q22(b). Oxygen (0 to −2), Q22(c). See example above.

How to Use This Worksheet Effectively

To maximise learning, print this worksheet and solve it under timed conditions — set a timer for 90 minutes and attempt all sections without referring to notes. Afterwards, spend 30 minutes reviewing the answer key and marking your work honestly. Identify weak areas: if you struggled with oxidation number calculations, revisit NCERT rules and practice assigning oxidation states in diverse compounds. If balancing equations tripped you up, work through additional examples using both oxidation number method and half-reaction method. Discuss tough questions with classmates or your chemistry teacher. Reattempt incorrect questions after a day or two to reinforce learning. Use this worksheet as a benchmark — aim for at least 75 percent accuracy initially, then target 90+ percent on a second attempt. Pair worksheet practice with NCERT exercises and previous years' CBSE board papers for comprehensive preparation. Regular practice transforms conceptual understanding into exam-ready problem-solving speed and accuracy, essential for scoring high in CBSE Class 11 Chemistry board exams.
  • Print and solve under exam conditions (90 minutes, no notes)
  • Self-assess using the detailed answer key; note mistakes and revisit NCERT sections
  • Focus on weak areas: oxidation state rules, balancing equations, terminology
  • Re-attempt incorrect questions after 1-2 days to reinforce concepts
  • Combine worksheet practice with NCERT exercises and past CBSE papers
  • Aim for 75%+ initially, then 90%+ on second attempt for exam readiness

Why Redox Reactions Matter for CBSE Class 11 and Beyond

Redox reactions are not merely an academic chapter; they underpin electrochemistry (Class 12 Chapter 3), chemical kinetics, and thermodynamics. Understanding electron transfer is crucial for explaining how batteries work, how metals corrode and how industrial processes like the extraction of aluminium and chlor-alkali process function. In JEE Main and Advanced, redox reactions appear in numerical problems involving equivalent weights, titrations and cell potentials. NEET tests redox concepts in questions on metabolism, photosynthesis and respiration. Mastery of oxidation number assignment and equation balancing builds analytical thinking and problem-solving skills applicable across chemistry. Moreover, redox principles are essential for environmental chemistry — understanding pollutant formation, ozone depletion and water treatment all involve redox processes. By thoroughly practising Chapter 7, you lay a strong foundation for higher studies in chemistry, chemical engineering and medicine. Invest time in this chapter now to reap rewards in board exams, competitive entrance tests and your future career.
  • Foundation for Class 12 electrochemistry, chemical kinetics and equilibrium
  • Critical for JEE Main/Advanced numerical problems and NEET biochemistry questions
  • Explains real-world processes: batteries, corrosion, metal extraction, water treatment
  • Develops analytical and quantitative problem-solving skills
  • Essential for careers in chemical engineering, medicine, environmental science and research

Frequently asked questions

What is the difficulty level and suggested time for this worksheet?+
This worksheet is of moderate difficulty, suitable for CBSE Class 11 students who have completed Chapter 7 Redox Reactions. The suggested time is 90 minutes under exam conditions, allowing thorough attempt of all sections and case-study question.
Does this worksheet follow the latest CBSE syllabus and exam pattern?+
Yes, this worksheet is aligned with the latest NCERT Class 11 Chemistry syllabus and CBSE board exam pattern. It includes a case-study question introduced in recent years and covers oxidation number method and balancing redox equations as prescribed in Chapter 7.
How many questions are there in each section of the worksheet?+
Section A has 6 MCQs, Section B has 5 fill-in-the-blanks, Section C has 1 matching and 1 true/false set, Section D has 5 short-answer questions (3 marks each), Section E has 3 long-answer HOTS questions (5 marks each), and Section F has 1 case-study question with 3 sub-parts.
Is a complete answer key provided with explanations?+
Absolutely. A comprehensive answer key with brief explanations for every question is included at the end. This helps students self-assess, understand mistakes, and learn correct methods for assigning oxidation numbers and balancing redox equations.
Can I use this worksheet for board exam preparation?+
Yes, this worksheet is ideal for CBSE board exam preparation. It covers all key concepts from Chapter 7, mirrors the question styles in board papers, and provides ample practice in MCQs, short answers and long answers, ensuring thorough revision.
What topics from Chapter 7 Redox Reactions are covered in this worksheet?+
The worksheet covers oxidation and reduction definitions, assigning oxidation numbers, identifying oxidising and reducing agents, disproportionation reactions, balancing redox equations using oxidation number method and half-reaction method, and real-world applications like rusting.
How should I approach the long-answer and HOTS questions in Section E?+
Read each question carefully, write down the given information, assign oxidation numbers step-by-step, and show all working clearly. For balancing equations, choose either oxidation number method or half-reaction method and apply it systematically. Allocate 12-15 minutes per question.
What if I get stuck on a difficult balancing problem?+
Refer to the answer key first to see the correct steps. If you still need help, use CBSETUTOR.ai's 24×7 AI tutor: upload a photo of the problem and get instant step-by-step solutions. It costs just ₹999/month for all classes 6-12, with a 3-day free trial available.
Are the questions in this worksheet similar to those asked in JEE or NEET?+
Yes, MCQs and HOTS questions are designed to match the rigour of JEE Main and NEET. Practicing these questions strengthens conceptual clarity and problem-solving speed, both critical for competitive exams where redox reactions frequently appear.
Can I print this worksheet for offline practice?+
Absolutely. The worksheet is designed to be printable. Download the PDF or copy the questions into a document, print, and solve on paper under timed conditions to simulate real exam experience and improve handwriting speed and accuracy.

Ready to give your Class 11 child the tutor that never sleeps?

CBSETUTOR.ai covers every chapter in the Class 11 NCERT syllabus — Maths, Science, Social Science, English, Hindi and more. 24×7. Patient. Unlimited. 3-day free trial.

Start your child's 3-day free trial →
CBSETUTOR.ai · Free tutor
Your 24×7 AI tutor
Hi! I'm your CBSETUTOR.ai — an AI tutor that has ingested every NCERT book for Class 6 to 12. To get started, tell me which class you're in and which subject you'd like help with today (e.g. "Class 9, Physics").