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Important Questions: CBSE Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry

Chapter 1 'Some Basic Concepts of Chemistry' is the gateway to quantitative chemistry for CBSE Class 11 students. It introduces the mole concept, stoichiometry, empirical and molecular formulae, and laws of chemical combination—all fundamental to solving numerical problems throughout the year. This page compiles 18 important exam-oriented questions, grouped by marks, mirroring the exact pattern seen in recent CBSE board papers and sample question papers.

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Key takeaways

  • Chapter 1 typically carries 5-8 marks in the CBSE Class 11 final exam, spread across MCQ, VSA, and numerical problems.
  • The mole concept and stoichiometry form 60% of questions; mastering dimensional analysis and significant figures is critical.
  • CBSE frequently tests empirical and molecular formula determination through 3-mark or 5-mark numerical problems.
  • At least one question on limiting reagent or percentage yield appears almost every year in board papers.
  • Common mistakes include incorrect molar mass calculation, misuse of Avogadro's number, and rounding errors in significant figures.
  • Practising 15-18 representative questions with model answers builds confidence and covers the entire syllabus scope.
  • CBSETUTOR.ai offers 24×7 doubt-solving with photo upload for instant worked solutions at ₹999/month across Classes 6-12.

Chapter Overview and Marks Weightage in CBSE Exam

Chapter 1 'Some Basic Concepts of Chemistry' from NCERT Class 11 Chemistry typically contributes 5 to 8 marks in the annual CBSE board examination. The chapter covers the mole concept, stoichiometry, laws of chemical combination, empirical and molecular formulae, percentage composition, and significant figures. Recent CBSE question papers show that 2-3 MCQs (1 mark each) come from definitions and basic concepts, one 2-mark question on molar mass or Avogadro's number, and at least one 3-mark or 5-mark numerical on stoichiometry or limiting reagent. The 2023 board paper featured a 5-mark case-based question linking mole concept with real-world scenarios. Understanding this distribution helps students prioritise high-yield topics during revision. The chapter also sets the foundation for physical chemistry throughout Classes 11 and 12, so strong conceptual clarity here pays dividends in chapters on equilibrium, thermodynamics, and redox reactions.
  • MCQs and VSAs (1 mark each): 2-3 questions on SI units, significant figures, laws of chemical combination, Avogadro's number
  • 2-mark questions: Calculation of molar mass, conversion of units, simple stoichiometry
  • 3-mark questions: Empirical and molecular formula determination, percentage composition problems
  • 5-mark questions: Multi-step stoichiometry, limiting reagent analysis, case-based integrated problems

How CBSE Frames Questions from This Chapter

CBSE question setters follow a predictable pattern when designing questions from Chapter 1. They test conceptual understanding through MCQs on definitions (matter, mixture, mole, significant figures), numerical ability via stoichiometry and mole-concept problems, and application skills through case-based or real-world scenario questions. In the 2024 sample paper, one MCQ asked students to identify the correct number of significant figures in a measured value, while a 3-mark question required calculating the empirical formula from percentage composition data. Five-mark questions often integrate multiple concepts: for instance, determining the limiting reagent in a reaction, calculating theoretical yield, and then computing percentage yield. CBSE also loves dimensional analysis questions where students must convert between grams, moles, and number of particles using Avogadro's constant. Understanding this blueprint allows you to practise strategically rather than randomly.
  • Conceptual MCQs: Definitions, SI units, laws of chemical combination, nature of matter
  • Numerical short answers: Molar mass, Avogadro's number applications, unit conversions
  • Empirical/molecular formula: Given percentage composition or combustion analysis data
  • Stoichiometry: Balanced equations, limiting reagent, theoretical and percentage yield
  • Case-based: Real-life scenarios involving fertilisers, medicines, industrial processes

1-Mark Questions: MCQs and Very Short Answer (VSA)

One-mark questions in CBSE Class 11 Chemistry Chapter 1 are designed to test recall and basic comprehension. MCQs appear in Section A of the board paper and cover definitions, SI units, significant figures, and simple factual knowledge. VSAs may ask you to write a formula, state a law, or perform a quick one-step calculation. Practising 6-8 representative MCQs sharpens speed and accuracy. Remember that negative marking applies to MCQs in the board exam, so educated guessing is better than wild guessing. Below are six important 1-mark questions with model answers that have appeared in various CBSE sample papers and previous board exams.
  • Q1. How many significant figures are in the measurement 0.00508? Answer: Three (5, 0, 8). Leading zeros are not significant.
  • Q2. What is Avogadro's number? Answer: 6.022 × 10²³ particles per mole.
  • Q3. State the law of definite proportions. Answer: A chemical compound always contains the same elements in the same proportion by mass.
  • Q4. Which has more atoms: 1 g of hydrogen or 1 g of oxygen? Answer: 1 g of hydrogen (lighter molar mass means more moles, hence more atoms).
  • Q5. Write the SI unit of amount of substance. Answer: Mole (mol).
  • Q6. Define molarity. Answer: Number of moles of solute per litre of solution (mol/L or M).

2-Mark Questions: Short Answer Type

Two-mark questions require a brief explanation or a straightforward calculation with one or two steps. CBSE typically asks for molar mass calculations, simple mole-mass conversions, or application of Avogadro's number. Your answer should be concise—state the formula, plug in the values, and write the final answer with correct units. Marks are awarded for method (1 mark) and final answer (1 mark), so even if your arithmetic slips, showing the correct approach earns partial credit. Below are four high-probability 2-mark questions drawn from NCERT exemplar problems and past CBSE papers. Practise writing answers within three to four lines, maintaining clarity and logical flow.
  • Q7. Calculate the molar mass of sulphuric acid (H₂SO₄). Answer: H: 2 × 1 = 2; S: 1 × 32 = 32; O: 4 × 16 = 64. Total = 98 g/mol.
  • Q8. How many moles are present in 11 g of CO₂? Answer: Molar mass of CO₂ = 44 g/mol. Moles = 11 ÷ 44 = 0.25 mol.
  • Q9. What mass of calcium carbonate (CaCO₃) contains 3.011 × 10²³ formula units? Answer: 3.011 × 10²³ = 0.5 mol. Molar mass CaCO₃ = 100 g/mol. Mass = 0.5 × 100 = 50 g.
  • Q10. Distinguish between empirical formula and molecular formula. Answer: Empirical formula shows the simplest whole-number ratio of atoms (e.g. CH₂O). Molecular formula shows the actual number of atoms in one molecule (e.g. C₆H₁₂O₆).

3-Mark Questions: Numerical and Application-Based

Three-mark questions form the backbone of CBSE Chemistry numericals. They test your ability to apply formulas, perform multi-step calculations, and present working in a logical sequence. Common themes include empirical formula determination from percentage composition, stoichiometric calculations involving balanced equations, and percentage yield computations. CBSE mark schemes award 1 mark for correct formula/method, 1 mark for substitution with units, and 1 mark for final answer. Always write units at every step and round off according to significant figures. Below are four representative 3-mark questions that mirror the difficulty and style of recent board papers. Practise writing full solutions within half a page.
  • Q11. A compound contains 40% C, 6.7% H, and 53.3% O. Find its empirical formula. Answer: Assume 100 g sample. C: 40/12 = 3.33 mol; H: 6.7/1 = 6.7 mol; O: 53.3/16 = 3.33 mol. Ratio C:H:O = 1:2:1. Empirical formula = CH₂O.
  • Q12. Calculate the mass of oxygen required to completely burn 4.8 g of methane (CH₄). Answer: CH₄ + 2O₂ → CO₂ + 2H₂O. Moles CH₄ = 4.8/16 = 0.3 mol. Moles O₂ needed = 0.3 × 2 = 0.6 mol. Mass O₂ = 0.6 × 32 = 19.2 g.
  • Q13. When 5 g of calcium carbonate is heated, 2.8 g of CaO is obtained. Calculate percentage yield. Answer: CaCO₃ → CaO + CO₂. Moles CaCO₃ = 5/100 = 0.05 mol. Theoretical CaO = 0.05 × 56 = 2.8 g. Percentage yield = (2.8/2.8) × 100 = 100%.
  • Q14. How many moles of NH₃ can be formed from 14 g N₂ and 6 g H₂? Answer: N₂ + 3H₂ → 2NH₃. Moles N₂ = 14/28 = 0.5; moles H₂ = 6/2 = 3. Limiting reagent is N₂. NH₃ formed = 0.5 × 2 = 1 mol.

5-Mark Questions: Long Answer and Case-Based

Five-mark questions are comprehensive problems that integrate multiple concepts from Chapter 1. CBSE introduced case-based questions from 2021 onwards, where a short paragraph describes a real-world scenario (industrial synthesis, environmental chemistry, nutritional analysis) followed by sub-questions. A typical 5-mark numerical might ask you to balance an equation, identify the limiting reagent, calculate theoretical yield, and then compute percentage yield or excess reagent left. These questions demand clarity in presentation, correct use of significant figures, and logical step-wise working. Marks are distributed as 1 + 1 + 1 + 1 + 1 across sub-parts or method steps. Below are three high-value 5-mark questions that closely resemble those in recent CBSE board papers. Allocate seven to eight minutes per question during practice.
  • Q15. Case-based: Ammonia is manufactured by the Haber process: N₂ + 3H₂ → 2NH₃. In an experiment, 28 g N₂ and 9 g H₂ are mixed. (a) Identify the limiting reagent. (b) Calculate the mass of NH₃ formed. (c) Find the mass of excess reagent left. Answer: (a) Moles N₂ = 28/28 = 1; moles H₂ = 9/2 = 4.5. Required H₂ for 1 mol N₂ = 3 mol. Limiting reagent = N₂. (b) NH₃ = 1 × 2 = 2 mol = 34 g. (c) H₂ used = 3 mol = 6 g; left = 9 − 6 = 3 g.
  • Q16. A hydrocarbon on combustion gives 4.4 g CO₂ and 2.7 g H₂O. If its molar mass is 28 g/mol, find the molecular formula. Answer: Moles CO₂ = 4.4/44 = 0.1 → C = 0.1 mol; moles H₂O = 2.7/18 = 0.15 → H = 0.3 mol. Empirical formula CH₃. Empirical mass = 15. n = 28/15 ≈ 1.87 ≈ 2. Molecular formula = C₂H₆.
  • Q17. In a reaction, 10 g of A reacts with 15 g of B to give 20 g of C. If 8 g of A is taken with excess B, what mass of C is formed? Also verify the law of conservation of mass. Answer: Ratio A:C = 10:20 = 1:2. For 8 g A, C = 16 g. Total mass before = 8 + (15 × 0.8) = 20 g; after = 16 g C + 4 g excess = 20 g (conserved).

Common Mistakes Students Make in Chapter 1 Numericals

Even strong students stumble in Chapter 1 due to avoidable errors. The most frequent mistake is incorrect molar mass calculation—forgetting to multiply the atomic mass by the subscript or using outdated atomic weights. Another pitfall is misapplying Avogadro's number: students often confuse 6.022 × 10²³ particles per mole with per gram. Significant figures cause marks loss when final answers are not rounded correctly; CBSE mark schemes explicitly deduct for wrong sig figs. In stoichiometry, many skip balancing the equation first or misread coefficients, leading to wrong mole ratios. Limiting reagent problems trip up students who do not compare mole ratios with stoichiometric coefficients. Unit conversion errors, especially between grams and kilograms or litres and millilitres, are common. Finally, students often write the empirical formula as the molecular formula without checking the molar mass ratio. Being aware of these pitfalls and double-checking each step prevents silly marks loss.
  • Incorrect molar mass: Forgetting subscripts or using wrong atomic masses from an old periodic table
  • Misuse of Avogadro's number: Applying 6.022 × 10²³ per gram instead of per mole
  • Significant figures: Not rounding final answer to match the least precise measurement
  • Unbalanced equations: Performing stoichiometry on an unbalanced chemical equation
  • Limiting reagent confusion: Not dividing moles by stoichiometric coefficients to identify the limiting reagent
  • Unit mismatches: Mixing grams with kilograms or litres with cm³ without conversion
  • Empirical vs molecular formula: Reporting empirical formula without finding the molecular formula multiplier

Stoichiometry and Limiting Reagent Questions

Stoichiometry is the heart of Chapter 1 and one of the highest-weightage topics in CBSE Class 11 Chemistry. Questions on stoichiometry test your ability to use balanced chemical equations to relate masses, moles, and volumes of reactants and products. The limiting reagent concept appears almost every year in 3-mark or 5-mark questions. The trick is to convert all given masses to moles, divide by stoichiometric coefficients, and identify which reagent produces the least product. That reagent is limiting; the others are in excess. After identifying the limiting reagent, use it to calculate the theoretical yield of product. Finally, if actual yield is given, compute percentage yield as (actual/theoretical) × 100. CBSE loves multi-step problems that combine these elements. Practising the four questions below will make you exam-ready in this crucial area.
  • Always balance the equation before starting calculations
  • Convert all masses to moles using molar mass
  • Divide moles by stoichiometric coefficients to find the limiting reagent
  • Use the limiting reagent to calculate moles of product formed
  • Multiply by molar mass to get mass of product; compare with actual yield if given

Empirical and Molecular Formula Determination

Empirical and molecular formula questions are staples in CBSE papers. The empirical formula represents the simplest whole-number ratio of atoms, while the molecular formula shows the actual number of atoms in a molecule. To find the empirical formula from percentage composition, assume a 100 g sample, convert percentages to grams, then to moles using atomic masses, and divide by the smallest number of moles to get the simplest ratio. If the ratio is not whole, multiply by a small integer (2, 3, or 4) to clear fractions. To find the molecular formula, calculate the empirical formula mass and divide the given molar mass by it to get n, then multiply each subscript in the empirical formula by n. CBSE often provides combustion data or elemental analysis data instead of direct percentages, requiring you to back-calculate the masses of C, H, and O. The three questions below cover all these variations.
  • Q18. A compound has 52.2% C, 13.0% H, and 34.8% O by mass. Find the empirical formula. Answer: C: 52.2/12 = 4.35; H: 13/1 = 13; O: 34.8/16 = 2.175. Ratio 4.35:13:2.175 → divide by 2.175 → 2:6:1. Empirical formula = C₂H₆O.
  • Q19. The empirical formula of a compound is CH and its molar mass is 78 g/mol. Determine the molecular formula. Answer: Empirical mass = 12 + 1 = 13. n = 78/13 = 6. Molecular formula = C₆H₆.
  • Q20. On combustion, 0.29 g of an organic compound gave 0.66 g CO₂ and 0.27 g H₂O. Molar mass is 58 g/mol. Find molecular formula. Answer: C in CO₂ = (0.66 × 12)/44 = 0.18 g; H in H₂O = (0.27 × 2)/18 = 0.03 g. C: 0.18/12 = 0.015 mol; H: 0.03/1 = 0.03 mol. Ratio C:H = 1:2. Empirical formula CH₂, mass 14. n = 58/14 ≈ 4. Molecular formula C₄H₈.

Percentage Composition and Purity Calculations

Percentage composition questions ask you to find the mass percent of each element in a compound, or vice versa. The formula is straightforward: (mass of element in 1 mole / molar mass of compound) × 100. CBSE also tests purity and percentage yield concepts. Purity is the ratio of pure substance mass to total sample mass, expressed as a percentage. Percentage yield compares actual experimental yield with theoretical yield calculated from stoichiometry. These questions often appear in 2-mark or 3-mark formats and are easy scoring if you remember the formulas and show clear working. Below are sample problems that illustrate each variation. Make sure you write the formula first, substitute values with units, and box the final answer.
  • Percentage composition of element X = (mass of X in formula / molar mass) × 100
  • Percentage purity = (mass of pure substance / total mass of sample) × 100
  • Percentage yield = (actual yield / theoretical yield) × 100
  • Always check that the sum of percentage compositions equals 100% (or close, allowing for rounding)

How CBSETUTOR.ai Helps You Master Chapter 1

Chapter 1 numericals demand clarity in concept and speed in calculation—both of which come from repeated practice with instant feedback. CBSETUTOR.ai offers a 24×7 AI tutor that acts like a personal chemistry coach for CBSE Class 11 students. Stuck on a stoichiometry problem at 11 p.m.? Simply snap a photo of the question and upload it; the AI breaks down the solution step-by-step, highlighting the formula, showing substitution with units, and explaining common mistakes. Unlike generic video lectures, CBSETUTOR.ai tailors explanations to your exact doubt. It covers all NCERT exercises, exemplar problems, and previous years' board questions for Chapter 1. Parents across Delhi NCR, Mumbai, and Bengaluru trust CBSETUTOR.ai because it costs just ₹999 per month for full access across Classes 6 to 12—one flat fee, no hidden charges. A 3-day free trial lets your child experience the platform risk-free. For Chapter 1, the AI also generates unlimited practice questions on mole concept, empirical formula, and limiting reagent, so students build speed and confidence before the exam.
  • Photo-upload doubt solving: Snap your Chapter 1 numerical and get step-by-step solutions in seconds
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Revision Strategy for Chapter 1 Before the Exam

Chapter 1 is concept-heavy and calculation-intensive, so a focused revision strategy is essential. Start by reviewing NCERT in-text solved examples and end-of-chapter exercises; these form the blueprint for CBSE questions. Make a one-page formula sheet covering molar mass, Avogadro's number, percentage composition, empirical and molecular formula steps, stoichiometry ratios, and limiting reagent logic. Practise at least 15-18 numerical problems of varying difficulty—6 easy, 6 medium, 6 hard—to build speed and accuracy. Time yourself: 1-mark MCQs should take 30 seconds, 2-mark questions 2 minutes, 3-mark questions 4 minutes, and 5-mark questions 7 minutes. Rework any problem you get wrong until the method is automatic. Pay special attention to significant figures and unit consistency; these are easy marks if you are careful. One day before the exam, solve a full Chapter 1 question set in exam conditions, then review mistakes. This active recall strategy cements memory better than passive rereading. CBSETUTOR.ai's topic tests simulate real exam pressure and provide instant performance analytics.
  • Day 15-10 before exam: Read NCERT thoroughly, note down all formulas, solve in-text examples
  • Day 9-5: Practise 15-18 numerical problems from NCERT, exemplar, and previous year papers
  • Day 4-2: Revise formula sheet, rework mistakes, attempt a mock Chapter 1 test
  • Day 1: Light revision, focus on common errors, ensure calculator and formula sheet are ready
  • Use spaced repetition: Revise the same set of tough problems on Days 10, 7, and 2 for long-term retention

Frequently asked questions

How many marks does Chapter 1 carry in the CBSE Class 11 Chemistry final exam?+
Chapter 1 'Some Basic Concepts of Chemistry' typically carries 5 to 8 marks in the CBSE board exam. This includes 2-3 MCQs of 1 mark each, one or two short-answer questions of 2 marks, and at least one numerical problem of 3 or 5 marks covering stoichiometry or empirical formula.
What is the mole concept and why is it important?+
The mole concept links the microscopic world of atoms and molecules to macroscopic measurable quantities. One mole contains 6.022 × 10²³ particles (Avogadro's number) and has a mass equal to the substance's molar mass in grams. It is the foundation for all stoichiometric calculations in chemistry.
How do I identify the limiting reagent in a chemical reaction?+
Convert the given masses of all reactants to moles, then divide each by its stoichiometric coefficient from the balanced equation. The reactant with the smallest ratio is the limiting reagent. Use it to calculate the amount of product formed; other reactants are in excess.
What is the difference between empirical and molecular formula?+
The empirical formula shows the simplest whole-number ratio of atoms in a compound (e.g. CH₂O for glucose). The molecular formula shows the actual number of atoms in one molecule (e.g. C₆H₁₂O₆). The molecular formula is always a whole-number multiple of the empirical formula.
How many significant figures should I use in my final answer?+
Your final answer should have the same number of significant figures as the measurement with the fewest significant figures in the given data. For example, if you multiply 2.5 (2 sig figs) by 3.456 (4 sig figs), report the answer to 2 sig figs. CBSE deducts marks for incorrect rounding.
What are common mistakes students make in stoichiometry problems?+
Common errors include using an unbalanced equation, incorrect molar mass calculation, confusing empirical with molecular formula, not identifying the limiting reagent, and unit mismatches. Always balance the equation first, double-check atomic masses, and write units at every step to avoid these pitfalls.
Is Chapter 1 difficult compared to other chapters in Class 11 Chemistry?+
Chapter 1 is considered moderately difficult because it is calculation-heavy and introduces new concepts like the mole and stoichiometry. However, with systematic practice of 15-20 numerical problems and clear understanding of formulas, most students score well. It is less conceptually abstract than later chapters on structure of atom or bonding.
How does CBSETUTOR.ai help with Chapter 1 numericals?+
CBSETUTOR.ai provides instant step-by-step solutions to any Chapter 1 numerical via photo upload. It covers all NCERT, exemplar, and board questions, generates unlimited practice problems, and explains common mistakes. At ₹999/month for all classes, it is affordable and available 24×7. A 3-day free trial is available.
How much time should I spend on Chapter 1 during revision?+
Allocate 4-5 hours spread over 3-4 days for thorough Chapter 1 revision. Spend 2 hours on concept review and formula memorisation, 2 hours solving 15-18 practice numericals, and 1 hour on a timed mock test. This ensures you cover all question types and build exam speed.
Can I score full marks in a 5-mark stoichiometry question?+
Yes, if you show clear step-wise working: balance the equation, convert masses to moles, identify the limiting reagent, calculate product moles, convert to mass, and state the final answer with correct units and significant figures. CBSE awards partial marks for method even if the final answer is wrong, so never skip steps.

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