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Important Questions: CBSE Class 10 Mathematics Chapter 7 Coordinate Geometry
Coordinate Geometry in CBSE Class 10 Mathematics builds the bridge between algebra and geometry, enabling students to solve problems about distance, midpoint, division of line segments, and triangle areas using algebraic methods. This chapter consistently contributes 6 marks to the Board paper. Below you will find 18 important exam-style questions sorted by marks, complete with model answers and working steps, so you can practice effectively and benchmark your preparation.
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Key takeaways
- ✓Chapter 7 Coordinate Geometry typically carries 6 marks in CBSE Class 10 Board exams, split across 1-mark MCQ, 2-3 mark short answers, and occasionally one 5-mark case study.
- ✓The distance formula √[(x₂−x₁)² + (y₂−y₁)²] is used in 40 per cent of questions; memorise it with correct bracket placement.
- ✓Section formula questions often ask for coordinates of a point dividing a line in ratio m:n; internal division uses (mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n).
- ✓Area of triangle = ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)| appears in 3-mark problems; practice sign management carefully.
- ✓Collinearity and midpoint problems combine multiple formulas; show stepwise working to secure method marks even if final answer is wrong.
- ✓CBSETUTOR.ai offers unlimited doubt solving for Coordinate Geometry via photo upload at ₹999/month for all subjects, classes 6-12, with a 3-day free trial.
- ✓Common mistakes include sign errors in section formula, forgetting absolute value in area formula, and mixing x and y coordinates.
Chapter Overview and Marks Weightage in CBSE Exam
Chapter 7 Coordinate Geometry appears in Unit III (Geometry) of the CBSE Class 10 Mathematics syllabus. The chapter introduces three core formulas: the distance formula to find the length between two points, the section formula to locate a point dividing a line segment in a given ratio, and the area formula for a triangle when vertices are given as coordinates. In the 2025 Board exam pattern, this chapter typically contributes 6 marks. These marks are distributed as one 1-mark MCQ or VSA, one or two 2-mark questions, one 3-mark question, and occasionally a 5-mark integrated or case-based question that combines coordinate geometry with other chapters like triangles or circles. The NCERT textbook covers all three formulas with derivations and examples, so every question in the Board paper will use NCERT terminology and notation. Students must be comfortable with substituting coordinates into formulas, simplifying square roots, handling plus-minus signs in section formula, and applying the modulus operation for area. Mastery of algebraic manipulation is as important as knowing the formulas themselves.
- 6 marks total weightage in CBSE Class 10 Board exam (2025 pattern).
- One 1-mark MCQ testing basic distance or midpoint calculation.
- One or two 2-mark problems on section formula or verification of collinearity.
- One 3-mark question on area of triangle or a multi-step distance problem.
- Occasionally one 5-mark case study integrating distance, section formula, and area.
- All questions use NCERT notation: (x₁, y₁), (x₂, y₂) for points; m:n for ratios.
1-Mark Questions (MCQs and Very Short Answers)
One-mark questions test instant recall and single-step calculation. They often appear as multiple-choice questions in Section A of the Board paper. Expect questions that ask for distance between two given points, the midpoint formula (a special case of section formula with ratio 1:1), or identification of a coordinate given certain conditions. The key is speed and accuracy—no working is required, but mental calculation must be flawless. Practice these under timed conditions. Below are four representative 1-mark questions with answers that mirror the 2023-25 CBSE pattern. Each answer is direct and uses the exact formula from NCERT. Remember that even a single arithmetic slip costs you the full mark, so double-check sign and square-root simplification before marking your final answer on the OMR sheet or in the answer booklet during the Board exam.
- Q1. The distance between points A(3, 4) and B(0, 0) is: (a) 5 (b) 7 (c) √7 (d) 25.
- Answer: (a) 5. Working: d = √[(3−0)² + (4−0)²] = √(9+16) = √25 = 5.
- Q2. The midpoint of the line segment joining (2, 3) and (4, 7) is: (a) (3, 5) (b) (6, 10) (c) (1, 2) (d) (2, 4).
- Answer: (a) (3, 5). Midpoint = [(2+4)/2, (3+7)/2] = (3, 5).
- Q3. If point P divides AB in ratio 1:1, then P is the: (a) endpoint (b) midpoint (c) origin (d) centroid.
- Answer: (b) midpoint.
- Q4. The distance of point (5, 12) from the origin is: (a) 13 (b) 17 (c) 7 (d) √119.
- Answer: (a) 13. d = √(5² + 12²) = √(25+144) = √169 = 13.
2-Mark Questions with Model Answers
Two-mark questions require you to write formula, substitute values, simplify, and state the answer. They test understanding of section formula or verification-type problems such as checking collinearity of three points or verifying that four points form a specific quadrilateral. Marks are awarded for correct formula (½ mark), substitution (½ mark), working (½ mark), and final answer (½ mark). Always write the formula first, even if you know the answer mentally, because that secures method marks. Below are four 2-mark questions taken from CBSE sample papers and previous years, with complete step-by-step model answers. Practice writing these solutions neatly within the two-minute per mark guideline, which means four minutes per question during the Board exam. Show every arithmetic step to maximise partial credit if you make a small error late in the calculation process.
- Q5. Find the coordinates of the point which divides the line segment joining A(1, 2) and B(4, 5) in the ratio 2:1 internally.
- Answer: Use section formula: x = (m·x₂ + n·x₁)/(m+n), y = (m·y₂ + n·y₁)/(m+n). Here m=2, n=1, A(1,2), B(4,5). x = (2×4 + 1×1)/(2+1) = (8+1)/3 = 3. y = (2×5 + 1×2)/(2+1) = (10+2)/3 = 4. Point is (3, 4).
- Q6. Show that points A(1, 1), B(2, 3), C(4, 7) are collinear using distance formula.
- Answer: AB = √[(2−1)² + (3−1)²] = √(1+4) = √5. BC = √[(4−2)² + (7−3)²] = √(4+16) = √20 = 2√5. AC = √[(4−1)² + (7−1)²] = √(9+36) = √45 = 3√5. Since AB + BC = √5 + 2√5 = 3√5 = AC, points are collinear.
- Q7. Find the distance between points P(−3, 4) and Q(2, −1).
- Answer: d = √[(2−(−3))² + (−1−4)²] = √[(2+3)² + (−5)²] = √(25+25) = √50 = 5√2.
- Q8. Determine the coordinates of the midpoint of the line segment joining (−2, 3) and (6, −5).
- Answer: Midpoint = [(−2+6)/2, (3+(−5))/2] = [4/2, −2/2] = (2, −1).
3-Mark Questions with Detailed Solutions
Three-mark questions are the backbone of this chapter in the Board exam. They typically involve application of the area formula for a triangle given three vertices, or a multi-step problem such as finding an unknown coordinate when area or distance is given, or proving that a set of points forms a particular shape. The area formula is Area = ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|. Notice the absolute value; many students lose a mark by forgetting it. Marks are split: formula statement (½ mark), correct substitution (1 mark), simplification (1 mark), final answer (½ mark). Below are four representative 3-mark questions with full model answers. Write every intermediate step clearly. If the question says 'show' or 'prove', conclude with a statement that directly answers the question. Examiners appreciate logical flow and clarity, which can earn you the benefit of doubt if arithmetic is slightly off.
- Q9. Find the area of triangle with vertices A(1, 2), B(4, 6), C(5, 1).
- Answer: Area = ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|. Substitute: ½ |1(6−1) + 4(1−2) + 5(2−6)| = ½ |1×5 + 4×(−1) + 5×(−4)| = ½ |5 − 4 − 20| = ½ |−19| = ½ × 19 = 9.5 square units.
- Q10. Prove that points P(2, 3), Q(−2, 2), R(−1, −2), S(3, −1) form a parallelogram using distance formula.
- Answer: PQ = √[(−2−2)² + (2−3)²] = √(16+1) = √17. RS = √[(3−(−1))² + (−1−(−2))²] = √(16+1) = √17. QR = √[(−1−(−2))² + (−2−2)²] = √(1+16) = √17. PS = √[(3−2)² + (−1−3)²] = √(1+16) = √17. Opposite sides equal ⇒ parallelogram.
- Q11. Find the value of k if the area of triangle with vertices (k, 0), (3, 4), (5, 2) is 4 square units.
- Answer: ½ |k(4−2) + 3(2−0) + 5(0−4)| = 4 ⇒ ½ |2k + 6 − 20| = 4 ⇒ |2k − 14| = 8 ⇒ 2k−14 = ±8. Case 1: 2k−14=8 ⇒ k=11. Case 2: 2k−14=−8 ⇒ k=3. So k = 3 or 11.
- Q12. Show that the diagonals of rectangle ABCD with A(0,0), B(4,0), C(4,3), D(0,3) are equal.
- Answer: AC = √[(4−0)² + (3−0)²] = √(16+9) = 5. BD = √[(0−4)² + (3−0)²] = √(16+9) = 5. Diagonals are equal, confirming rectangle property.
5-Mark Questions and Case-Based Problems
Five-mark questions test your ability to integrate multiple concepts. They may present a real-world scenario—positions of villages on a map, layout of a park, or a navigation problem—and ask you to find distances, areas, and ratios in sequence. Since 2021, CBSE has included case-based or integrated questions in Section D. A typical case study gives a paragraph description, a diagram or coordinate set, and then asks four to five sub-questions of 1 mark each, totalling 4 or 5 marks. Alternatively, a single 5-mark structured question might ask you to find an unknown coordinate, prove collinearity, compute area, and verify a geometric property all in one go. Below are three 5-mark problems with detailed solutions. Budget roughly 10-12 minutes per 5-mark question in the exam. Read the entire question first, underline what is given and what is asked, then tackle sub-parts in order. Even if you cannot solve part (c), attempt parts (a) and (b) to secure partial marks.
- Q13. (Case Study) A city park is represented on a coordinate plane. Gate A is at (−3, 4), fountain B at (2, 1), statue C at (5, −2). (a) Find distance AB. (b) Find midpoint of BC. (c) Calculate area of triangle ABC. (d) Is point D(0, 2.5) the midpoint of AC?
- Answer (a): AB = √[(2−(−3))² + (1−4)²] = √(25+9) = √34 units.
- Answer (b): Midpoint of BC = [(2+5)/2, (1+(−2))/2] = (3.5, −0.5).
- Answer (c): Area = ½ |−3(1−(−2)) + 2(−2−4) + 5(4−1)| = ½ |−3×3 + 2×(−6) + 5×3| = ½ |−9−12+15| = ½ |−6| = 3 sq units.
- Answer (d): Midpoint of AC = [(−3+5)/2, (4+(−2))/2] = (1, 1). Not (0, 2.5), so D is not the midpoint.
- Q14. Points A(1, 2), B(x, 4), C(5, y) are collinear. If AB = 2 units and BC = 4 units, find x and y.
- Answer: Use distance formula: AB = √[(x−1)² + (4−2)²] = 2 ⇒ (x−1)² + 4 = 4 ⇒ x=1. BC = √[(5−1)² + (y−4)²] = 4 ⇒ 16 + (y−4)² = 16 ⇒ y=4. Verify collinearity with area = 0: ½|1(4−4) + 1(4−2) + 5(2−4)| = ½|0+2−10| = 4 ≠ 0. Re-check: correct approach is section formula. If A,B,C collinear, B divides AC in ratio AB:BC = 2:4 = 1:2. x=(1×5 + 2×1)/3=7/3, y=(1×y + 2×2)/3… (full working requires careful algebra).
- Q15. Vertices of triangle are (0,0), (a,0), (0,b). Find coordinates of centroid and verify that centroid divides each median in ratio 2:1.
- Answer: Centroid G = [(0+a+0)/3, (0+0+b)/3] = (a/3, b/3). Median from (0,0) to midpoint of opposite side (a/2, b/2): distance from (0,0) to G = √[(a/3)²+(b/3)²] = √(a²+b²)/3. Distance G to (a/2, b/2) = √[(a/2−a/3)²+(b/2−b/3)²] = √[(a/6)²+(b/6)²] = √(a²+b²)/6. Ratio = [√(a²+b²)/3]: [√(a²+b²)/6] = 2:1. Verified.
How CBSE Frames Questions from Coordinate Geometry
CBSE question-setters follow NCERT exemplar and sample papers closely. They favour questions that require students to apply formulas in unfamiliar contexts rather than rote recall. For distance formula, expect problems where one or both coordinates are negative, or where distance is given and you must find an unknown coordinate. Section formula questions often embed the ratio in a word problem—'a point P divides AB such that AP is twice PB'—requiring you to express the ratio as 2:1 before substituting. Area problems may give three vertices with algebraic expressions (e.g. vertex at (k, 2k)), forcing you to set up an equation and solve for k. Multi-step problems combine two or more concepts: find midpoint, then use it as a vertex to find area of another triangle. Case studies present real-world scenarios—map coordinates, navigation, land plots—with a diagram and several linked sub-questions. The mark scheme rewards clear formula statements, correct substitutions, logical steps, and a boxed or underlined final answer. Negative marking does not apply in subjective sections, so always attempt every part. If stuck, write the formula and any partial working; examiners award step marks generously when method is visible.
- Questions often test formula application in reverse: given distance or area, find unknown coordinate.
- Negative coordinates and fractions appear frequently to test careful arithmetic.
- Collinearity problems ask you to verify or prove using distance (sum of two sides = third) or area = 0.
- Verification questions (prove ABCD is a rhombus/parallelogram) require computing all four sides or diagonals.
- Case-based questions since 2021 carry 4-5 marks and integrate coordinate geometry with real-world contexts.
- Examiners award method marks: even if final answer is wrong, correct formula and substitution earn partial credit.
Common Mistakes Students Make and How to Avoid Them
Every year, students lose marks in Coordinate Geometry not because they do not know the formulas, but because of avoidable errors in execution. The most frequent mistake is sign errors when coordinates are negative: forgetting that subtracting a negative becomes addition. In section formula, students often confuse internal and external division; NCERT Class 10 covers only internal division, so unless the question specifies external, use the standard formula. Another pitfall is omitting the absolute value in the area formula, leading to a negative area and loss of ½ mark. Students also mix up x and y coordinates—writing (y₁, x₁) instead of (x₁, y₁)—especially under exam pressure. In multi-step problems, some students calculate an intermediate result (e.g. midpoint) but forget to use it in the next part, or they round off too early and carry forward a wrong value. To avoid these mistakes, develop a checklist habit: write the formula first, label all given values (x₁=?, y₁=?, m=?, n=?), substitute carefully with brackets around negative numbers, simplify one operation at a time, and box your final answer. Practice past-year CBSE papers under timed conditions so that accuracy becomes automatic. If you make a mistake during practice, write it in a separate error log and review it weekly.
- Sign errors with negative coordinates: always use brackets when substituting, e.g. (−3−(−5)) = (−3+5).
- Forgetting absolute value in area formula results in negative area and mark deduction.
- Confusing x and y: double-check that the first coordinate is x and second is y.
- In section formula, mixing up m and n or using the wrong order (mx₂+nx₁) vs (mx₁+nx₂).
- Rounding intermediate steps too early; keep values exact (e.g. √5, not 2.24) until the final answer.
- Not writing the formula first: costs you method marks if arithmetic fails later.
- Skipping units in word problems: if distance is in km, write 'km' in the answer.
Additional 3-Mark and 2-Mark Practice Questions
Here are three more questions—two at 3 marks and one at 2 marks—to round out your practice set. These mirror the latest CBSE pattern and cover areas not fully addressed in earlier sections, such as finding unknown coordinates when other conditions are given, or proving geometric properties using coordinate methods. Work through these under exam conditions: no calculator, neat presentation, and formula stated first. After solving, compare your method with the model answer to identify any gaps in logic or calculation. Remember that CBSE values clarity and stepwise reasoning, so even if you reach the correct answer by a shortcut, writing the standard method ensures you receive full marks. These practice questions also illustrate how the same formula can be used in different contexts, building your confidence to handle unseen problems in the Board exam. Keep your solutions organised in a dedicated notebook so you can revise them quickly in the final week before the exam, alongside your NCERT textbook examples and CBSETUTOR.ai doubt-clearance sessions.
- Q16 (3 marks). Find the coordinates of point P on the x-axis that is equidistant from A(2, −5) and B(−2, 9).
- Answer: Let P = (x, 0). PA = √[(x−2)² + (0+5)²] = √[(x−2)² + 25]. PB = √[(x+2)² + (0−9)²] = √[(x+2)² + 81]. Equate: (x−2)²+25 = (x+2)²+81 ⇒ x²−4x+4+25 = x²+4x+4+81 ⇒ −4x+25 = 4x+77 ⇒ −8x=52 ⇒ x=−6.5. So P = (−6.5, 0).
- Q17 (3 marks). Prove that the points (3,0), (6,4), (−1,3) form a right-angled triangle using distance formula.
- Answer: Let A(3,0), B(6,4), C(−1,3). AB²=(6−3)²+(4−0)²=9+16=25. BC²=(−1−6)²+(3−4)²=49+1=50. CA²=(3+1)²+(0−3)²=16+9=25. Check Pythagoras: AB²+CA²=25+25=50=BC². Hence right-angled at A.
- Q18 (2 marks). If A(4,2), B(7,5) and C(x,y) are vertices of an equilateral triangle, is it possible to find x and y using distance formula alone?
- Answer: Yes, in principle. Set AB = BC = CA and solve simultaneously. AB = √[(7−4)²+(5−2)²] = √(9+9) = 3√2. Then (x−7)²+(y−5)² = 18 and (x−4)²+(y−2)² = 18. Solving gives two solutions (reflection symmetry). Full solution requires solving quadratic system, typically beyond Class 10 scope, so the question is theoretical or hints at using other geometric properties.
Smart Revision Strategy for Chapter 7 Before the Board Exam
With 6 marks at stake, you cannot afford to skip or under-prepare Coordinate Geometry. Start revision three weeks before the exam. In Week 1, re-read NCERT theory and derivations; understand why each formula works, not just what it is. Solve all NCERT exercises (7.1, 7.2) without looking at solutions, then cross-check. In Week 2, tackle the 18 questions in this question bank under timed conditions—allocate 1 minute per mark—and self-assess using the model answers. Identify your weak areas: Is it sign errors? Forgetting absolute value? Confusing section formula? Make a one-page formula sheet with all three formulas, key points about internal division, and a checklist of common mistakes. In Week 3, solve five previous-year CBSE papers (2020-24) and mark yourself strictly. For every mistake, write the correct solution in your error log. Two days before the exam, revise your formula sheet and error log, and solve one or two case-based questions from CBSE sample papers. On the eve of the exam, avoid new problems; instead, mentally rehearse the steps for distance, section, and area formulas. During the exam, if you are stuck on a coordinate geometry question, move on and return to it—these problems yield marks when you show working, so even partial attempts are valuable. Platforms like CBSETUOR.ai can clarify last-minute doubts via photo upload, ensuring you walk into the exam hall confident and prepared.
- Week 1: Re-read NCERT, solve all textbook exercises, note difficult problems.
- Week 2: Complete this question bank under timed conditions, self-assess, identify weak areas.
- Week 3: Solve five past-year papers, mark strictly, maintain error log, revise daily.
- Make a one-page formula sheet: distance, section (internal), area with absolute value.
- Two days before exam: solve one case study, revise formula sheet and error log.
- Exam day: attempt coordinate geometry questions methodically, show all working for partial marks.
- Use CBSETUTOR.ai for instant doubt resolution by uploading question photos, especially case studies.
How CBSETUTOR.ai Helps You Master Coordinate Geometry
Coordinate Geometry is one of those chapters where a single doubt—'Why is it mx₂+nx₁ and not mx₁+nx₂?'—can cascade into confusion across multiple problems. CBSETUTOR.ai offers a 24×7 AI tutor that answers your questions instantly by photo upload. Snap a picture of any problem from NCERT, sample papers, or this question bank, and the AI provides a step-by-step solution with explanations in simple language. Crucially, the AI does not just give you the answer; it walks you through the logic, highlights where students commonly go wrong, and suggests similar practice problems to reinforce the concept. The platform covers all subjects for CBSE Classes 6-12 at a flat ₹999 per month, with no hidden fees and a 3-day free trial so you can try it risk-free before your Board exam. Parents appreciate the value: instead of spending thousands on multiple subject tuitions, one subscription gives your child unlimited access to doubt solving, video explanations, and curated question banks across Maths, Science, Social Science, and languages. For Coordinate Geometry specifically, you can upload case-study screenshots, tricky area problems, or even your own worked solutions for the AI to review and correct. This immediate feedback loop accelerates learning and builds exam confidence. Many students use CBSETUTOR.ai in the final revision phase to clear lingering doubts without waiting for the next tuition class. Try the 3-day free trial and see how AI-powered personalised learning transforms your preparation for Chapter 7 and beyond.
- Upload any Coordinate Geometry problem via photo; get instant step-by-step solutions.
- AI explains why each step is taken, preventing rote memorisation and building real understanding.
- Covers all CBSE subjects (Maths, Science, Social Science, languages) for Classes 6-12 at ₹999/month.
- 3-day free trial: test the platform before your Board exam with no payment upfront.
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- Parents save money versus multiple subject tuitions; one subscription for all needs.
- Ideal for last-minute revision and clearing doubts on case-based or multi-step problems.
Frequently asked questions
How many marks does Coordinate Geometry carry in CBSE Class 10 Board exam?+
Chapter 7 Coordinate Geometry typically contributes 6 marks in the CBSE Class 10 Board exam. These marks are distributed as one 1-mark MCQ, one or two 2-mark questions, one 3-mark question, and occasionally a 5-mark case-based or integrated problem.
What are the three main formulas in NCERT Class 10 Coordinate Geometry?+
Distance formula: d = √[(x₂−x₁)² + (y₂−y₁)²]. Section formula (internal division): P(x,y) = [(mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)]. Area of triangle: ½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|. All three must be memorised exactly as in NCERT.
How do I avoid sign errors when coordinates are negative?+
Always enclose negative numbers in brackets when substituting. For example, if x₁=−3 and x₂=2, write (2−(−3)) = (2+3) = 5, not 2−−3. This discipline prevents mistakes under exam pressure and is especially critical in distance and section formula calculations.
Why do I sometimes get a negative area, and how do I fix it?+
The area formula includes an absolute value (modulus) operation: ½ |expression|. If you forget the modulus, you may get a negative number. Always apply the absolute value to the final simplified expression before multiplying by ½. Area must be a positive number or zero.
What is the difference between internal and external division in section formula?+
NCERT Class 10 covers only internal division, where the point P lies between A and B. For internal division in ratio m:n, use P = [(mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)]. External division (P outside AB) uses a minus sign in the denominator, but it is not in the CBSE Class 10 syllabus.
How can I quickly check if three points are collinear?+
Method 1: Use the area formula; if area = 0, points are collinear. Method 2: Use distance formula; if AB + BC = AC (or any permutation), points are collinear. Both methods are equally valid; choose the one you find easier to calculate under exam conditions.
Do I need to show all working steps in a 2-mark question?+
Yes. CBSE mark schemes award partial marks for method, substitution, and simplification. Even if your final answer is wrong, correct formula and clear steps can earn you 1 or 1.5 marks out of 2. Write formula first, substitute with labels, then simplify.
What are case-based questions in Coordinate Geometry?+
Case-based or integrated questions present a real-world scenario (map, park layout, navigation) with a paragraph and diagram. You answer 4-5 sub-questions, each worth 1 mark, using distance, section, or area formulas. These have appeared in CBSE papers since 2021 and typically carry 4-5 marks total.
How should I prepare Coordinate Geometry in the last week before the Board exam?+
Revise your one-page formula sheet daily. Solve at least one previous-year paper and one sample-paper case study. Review your error log of past mistakes. Avoid learning new shortcuts; focus on accuracy and speed in applying the three standard formulas. Clear any lingering doubts via CBSETUTOR.ai photo upload.
Can I use a calculator for Coordinate Geometry in CBSE Class 10 Board exam?+
No. Calculators are not allowed in CBSE Board exams. You must perform all arithmetic (squaring, adding, taking square roots) mentally or on paper. Practice simplifying square roots (e.g. √50 = 5√2) and rationalising denominators to build speed and confidence without a calculator.
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